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Chapter 4 Linear Differential Operators

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116 CHAPTER 4. LINEAR DIFFERENTIAL OPERATORS<br />

and found that<br />

L † = −i d<br />

dx , Q[u, v] = −iu∗v. (4.23)<br />

The operator −id/dx (which you should recognize as the “momentum” operator<br />

from quantum mechanics) obeys L = L † , and is therefore, formally<br />

self-adjoint, or Hermitian.<br />

Example: Let<br />

d<br />

L = p0<br />

2 d<br />

+ p1<br />

dx2 dx + p2, (4.24)<br />

with the pi all real. Again let us find the adjoint L † with respect to the inner<br />

product with w ≡ 1. Now, proceeding as above, but integrating by parts<br />

twice, we find<br />

u ∗ [p0v ′′ + p1v ′ + p2v] − v [(p0u) ′′ − (p1u) ′ + p2u] ∗<br />

= d <br />

p0(u<br />

dx<br />

∗ v ′ − vu ∗′ ) + (p1 − p ′ 0 )u∗v . (4.25)<br />

From this we read off that<br />

L † = d2<br />

dx2 p0 − d<br />

dx p1 + p2<br />

= p0<br />

d 2<br />

dx 2 + (2p′ 0<br />

d<br />

− p1) + (p′′ 0<br />

dx − p′ 1 + p2). (4.26)<br />

What conditions do we need to impose on p0,1,2 for this L to be formally<br />

self-adjoint with respect to the inner product with w ≡ 1? For L = L † we<br />

need<br />

We therefore require that p1 = p ′ 0<br />

p0 = p0<br />

2p ′ 0 − p1 = p1 ⇒ p ′ 0 = p1<br />

p ′′<br />

0 − p ′ 1 + p2 = p2 ⇒ p ′′<br />

0 = p ′ 1. (4.27)<br />

, and so<br />

L = d<br />

<br />

d<br />

p0 + p2, (4.28)<br />

dx dx<br />

which we recognize as a Sturm-Liouville operator.<br />

Example: Reduction to Sturm-Liouville form. Another way to make the<br />

operator<br />

d<br />

L = p0<br />

2 d<br />

+ p1<br />

dx2 dx + p2, (4.29)

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