- Page 1 and 2: A Text Boo
- Page 3 and 4: Foreword Design is an integral aspe
- Page 5: PREAMBLE THE CONSTITUTION OF INDIA
- Page 10 and 11: 1.2 ISOMETRIC PROJECTION The isomet
- Page 12 and 13: 1.3 DRAWING OF ISOMETRIC PROJECTION
- Page 14 and 15: Example 2 : Solution : ISOMETRIC PR
- Page 16 and 17: Example 5: Solution : Example 6: So
- Page 18 and 19: Example 8: Solution: A (iv) Join th
- Page 20 and 21: B B 75 35 O A (i) (ii) 30º 30º O
- Page 22 and 23: Example:13: Solution : b B O B b O
- Page 24 and 25: 1.3.3 FRUSTUM OF PYRAMID Example 16
- Page 26 and 27: Example 18 : Solution: Example 19 :
- Page 28 and 29: ISOMETRIC PROJECTION Steps (i) Draw
- Page 30 and 31: Example24 : Solution: Example 25 :
- Page 32 and 33: Example 27 : Solution: ISOMETRIC PR
- Page 34 and 35: Steps: 1. Draw an isometric project
- Page 36 and 37: Steps: 1. Draw an isometric project
- Page 38 and 39: Steps: 1. Draw an isometric project
- Page 40 and 41: Steps: 1. Draw an isometric project
- Page 42 and 43: Steps: 1. Draw an isometric project
- Page 44 and 45: 40 25 3. BELOW: CIRCULAR SLAB 4. BE
- Page 46 and 47: 44 11. BELOW: CIRCULAR SLAB 12. BEL
- Page 48 and 49: CHAPTER 2 2.1 INTRODUCTION 2.2 SCRE
- Page 50 and 51: (i) EXTERNAL THREAD MACHINE DRAWING
- Page 52 and 53: (xiii) MAJOR DIAMETER OR OUTSIDE DI
- Page 54 and 55: Solution D = 0.96 P D 6 d = 0.64 P
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Solution: Example 3 : Solution : D
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Example 5 : Solution : Steps Involv
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EXAMPLE 6: Solution: 60° 60° Step
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Steps Involved (i) Since the circle
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Steps Involved 2.5.4 HOOK BOLT/J-BO
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MACHINE DRAWING 5 Draw to scale ful
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MACHINE DRAWING (v) Project the top
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Example 12 : d 1.5 d Fig 2.24 MACHI
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MACHINE DRAWING 5. Draw to scale 1:
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BOLT 30° 0.8d Steps Involed: Ø2d
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Exercises: NOTE: Assume missing dim
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MACHINE DRAWING (iv) Fig 2.36 is th
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Exercises Note: Take p = 5mm and ot
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Exercises: NOTE: Assume missing dim
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Example 21: Solution: Example 22: 4
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Fig 2.51 shows views of some of the
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2.15.1 TYPES OF SUNK KEYS 2.15.1.1
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Example 26: Solution: Example 27: S
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Example 29: Solution: 1.5t KEY SHAF
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These bearings can be: 1. Needle Be
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Now let us solve some questions: Qu
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R 5 70 A Answer of fig. 3.5 BUSH R
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OPEN BEARING This bearing consists
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Question: The figure given below (f
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R 75 150 Ø 50 DETAILS OF PLUMMER B
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Answer of fig. 3.16 M18 Ø8 R 40 10
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FOOTSTEP BEARING OR PIVOT BEARING T
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14 BEARINGS NOTE: As per our syllab
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95 BEARINGS Question: The figure gi
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CHAPTER4 All of you have seen a tra
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USE OF COTTER JOINT The joint is us
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Dimensions of a Sleeve and Cotter J
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Answer of fig 4.7 114 Ø 24 A Ø66
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116 ROD JOINTS of alignment so that
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Answer of fig. 4.13 A 118 A 7 RIGHT
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120 ROD JOINTS Exercise: The pictor
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122 ROD JOINTS Dimensions of a Knuc
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Answer of fig 4.19 (a) 124 90 120
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Answer of fig 4.21 126 35 70 35 Ø3
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GIB AND COTTER JOINT 128 ROD JOINTS
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Answer: of fig (4.27) 130 RIGHT SID
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Answer of fig 4.29 A 132 10 32 12 3
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Exercises Q.1. What is cotter? Q.2.
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136 TIE-ROD AND PIPE JOINTS In such
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Solutions: 138 Ø 25 Point to remem
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Solution: X Exercise 5.1 140 Ø60
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142 TIE-ROD AND PIPE JOINTS (b) Dis
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144 TIE-ROD AND PIPE JOINTS Thus, i
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146 42 20 M 10 (THREADED LENGTH = 2
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Solution: Exercise 5.2 148 X Ø 58
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CHAPTER6 Shafts as we have learnt i
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6.1.1.1 Features: 152 SHAFT COUPLIN
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154 SHAFT COUPLINGS (i) It can be s
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A Solution: 156 HEX. BOLTS (4-OFF)
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158 SHAFT COUPLINGS PROTECTED FLANG
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160 SHAFT COUPLINGS Solution: Detai
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162 SHAFT COUPLINGS Solution: Let u
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164 WHAT WE HAVE LEARNT SHAFT COUPL
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Outer cylindrical surface of the pu
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Ø144 Example 1 : 168 PULLEYS Draw
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7.3 V- BELT PULLEY: In the V- belt
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172 PULLEYS EXERCISE 4 : Fig 7.10 s