Thanks for the question regarding "connect by ", versi

Find Employee's top most manager August 19, 2004 - 6pm Central time zone
Bookmark | Bottom | Top
Reviewer: Mita from NJ
For the following data,
Emp_id Mgr_id
1 2
2 3
3 4
4
5 6
6 7
7
I need the following result
EmpId TopManager
1 4
2 4
3 4
4 4
5 7
6 7
7 7
How can I achieve this ??
Followup August 19, 2004 - 8pm Central time zone:
if you gave me a create table and insert into's, i'd show you how to use a scalar subquery with
connect by using max to do this.
maybe that is enough to get you going....
Sample Data August 24, 2004 - 12pm Central time zone Bookmark | Bottom | Top
Reviewer: Mita from NJ
create table emp (emp_Id number, mgr_Id number);
insert into emp values(1,2);
insert into emp values(2,3);
insert into emp values(3,4);
insert into emp values(4,Null);
insert into emp values(5,6);
insert into emp values(6,7);
insert into emp values(7,Null);
Followup August 24, 2004 - 3pm Central time zone:
ops$tkyte@ORA9IR2> select emp_id,
2 to_number( substr(
3 (select max( to_char(level,'fm000009') || ' ' || emp_id )
4 from emp e2
5 start with e2.emp_id = e1.emp_id
6 connect by prior mgr_id is not null and prior mgr_id = emp_id )
7 , 8 ) ) top_mgr
8 from emp e1
9 /
EMP_ID TOP_MGR
---------- ----------
1 4
2 4