Thanks for the question regarding "connect by ", versi

7902 ******FORD 7566 3000
as you can see , the condition returns King, Scott and Ford . but Jones in the list because he is
the MGR of Scott and Ford.
That what I want. How can I do this.
Thanks
Followup May 8, 2006 - 7am Central time zone:
that is a bit of a sticky problem. we can do it upside down rather easily:
ops$tkyte@ORA10GR2> select EMPNO,SUBSTR(rpad('*',2*level,'*' ) || ENAME,1,30), MGR,SAL
2 FROM EMP
3 start with sal >= 3000
4 CONNECT BY PRIOR mgr = empno
5 /
EMPNO SUBSTR(RPAD('*',2*LEVEL,'*')|| MGR SAL
---------- ------------------------------ ---------- ----------
7788 **SCOTT 7566 3000
7566 ****JONES 7839 2975
7839 ******KING 5000
7839 **KING 5000
7902 **FORD 7566 3000
7566 ****JONES 7839 2975
7839 ******KING 5000
7 rows selected.
but going from the top down is a tad harder:
ops$tkyte@ORA10GR2> select EMPNO,SUBSTR(rpad('*',2*level,'*' ) || ENAME,1,30), MGR,SAL
2 FROM EMP
3 where empno in ( select EMPNO
4 FROM EMP
5 start with sal >= 3000
6 CONNECT BY PRIOR mgr = empno )
7 start with empno in ( select EMPNO
8 FROM EMP
9 where connect_by_isleaf = 1
10 start with sal >= 3000
11 connect by prior mgr = empno )
12 CONNECT BY PRIOR empno = mgr
13 /
EMPNO SUBSTR(RPAD('*',2*LEVEL,'*')|| MGR SAL
---------- ------------------------------ ---------- ----------
7839 **KING 5000
7566 ****JONES 7839 2975
7788 ******SCOTT 7566 3000
7902 ******FORD 7566 3000
it would only make sense to do the "start with" subquery IF you have multiple roots and thought
that the filtering done by the subquery would prune away large parts of the hierarchy - otherwise,
just build the entire hierarchy and then prune it with the where clause.
May 9, 2006 - 4pm Central time zone Bookmark | Bottom | Top
Reviewer: Isam from Jordan
Thank you for help.
That is what I need. I will use this logic in different queries of my project.
Thanks again.
Connect by doing extra full Scan? June 1, 2006 - 12pm Central time zone Bookmark | Bottom | Top
Reviewer: Greg from Toronto