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chemical elements and their compounds - Sciencemadness Dot Org

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Ortho- <strong>and</strong> Para-Hydrogen 13<br />

The electrons must spin in opposite directions (antiparallel), or the molecule<br />

would not hold together; but the spins of the nuclei may either be<br />

in the same (parallel) or in opposite directions, <strong>and</strong> certain properties of<br />

the molecule, especially its specific heat, will be different in the two<br />

arrangements. In 1927 Dennison pointed out 4 that the observed specific<br />

heats could be made to agree with the theory only if it was assumed that<br />

the time of transition was very long in comparison with the time in which<br />

the specific heats were measured, so that the gas was in effect a mixture<br />

of the two forms in fixed proportions. Subsequent work has entirely confirmed<br />

this view. The two differ especially in the fact that of the rotational<br />

energy (which is practically all the heat energy other than translational<br />

that the molecules have up to high temperatures) the ortho (parallel)<br />

molecules have the odd quantum states 1, 3, 5, etc., <strong>and</strong> the para (antiparallel)<br />

the even, 0, 2, 4, etc., which results in the ortho having, especially<br />

at low temperatures, a smaller specific heat than the para. We thus have:<br />

Ortho Para<br />

(Oj (OJ (OJ ^)<br />

Spins parallel Spins antiparallel<br />

Rotational quanta odd Rotational quanta even<br />

The proportions can be determined from the heat conductivity (which<br />

depends on the specific heat) by observing the rate of cooling of a heated<br />

wire in the gas,<br />

At equilibrium at the ordinary temperature <strong>and</strong> above it the gas contains<br />

25 per cent, of para <strong>and</strong> 75 per cent, of ortho, but on cooling the<br />

percentage of para rises, because more of the gas can thus go into the<br />

(even) zero-quantum state, <strong>and</strong> at the boiling-point of hydrogen (20*4° K.)<br />

only a fraction of 1 per cent, of ortho remains. The proportions at equilibrium<br />

<strong>and</strong> the specific heats are:<br />

Temp.<br />

Per cent, para<br />

Hp. ht. Pure para<br />

Pure ortho<br />

Normal* H2<br />

2O 0 K.<br />

99-8<br />

50° K.<br />

76-9<br />

0040<br />

0000<br />

0010<br />

100° K.<br />

38-5<br />

1-504<br />

0-073<br />

0-431<br />

200° K.<br />

26-0 .<br />

2-767<br />

1151<br />

1-555<br />

298° K.<br />

251<br />

2-186<br />

1-838<br />

1-925<br />

Inf.<br />

2500<br />

* i.e. the equilibrium mixture at the ordinary temperature, which has 25 per<br />

umit. para.<br />

In order to make para-hydrogen (it is of course impossible to get the<br />

ortho with less than 25 per cent, of para) the gas must be cooled (if possible<br />

with liquid hydrogen, though liquid air under reduced pressure will give<br />

a gas with 45 per cent, of para), <strong>and</strong> then brought to equilibrium by means<br />

of a catalyst. This is most easily done by absorbing the gas on charcoal,<br />

<strong>and</strong> then after some minutes or hours, according to the activity of the<br />

the charcoal, pumping it off.<br />

* D. M. Dennison, Proo. Boy, Soo, 1927» 115, 483,

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