TTC Timmler Technology TTC Silent Gravitiy Cooling – Modultherm ...

TTC Timmler Technology 

TTC Silent Gravitiy Cooling – Modultherm 

Planning Documentation 

for Engineers and Plant Contractors

TTC Order Key for Cooling Units 

2 

Order Key for TTC Cooling Units 

AASS 30 33 2 L 1 

Performance category 

1 = for construction height 33 (effective duct height H 1,5–6 m) 

eff. 

2 = for construction height 51 (effective duct height H 1,5–7 m) 

eff. 

Water connection 

L = Left 

R = Right 

Function 

2 = 2 pipe system 

Construction height [cm] 

33 > for series: AASS; ASVI; AISI; AVSI 

51 > for series: AASS; ASVI; AISI; AVSI 

Width [dm] 

08 - 10 - 12 - 14 - 16 - 18 - 20 - 22 - 24 dm 

Series 

AASS 

AISI 

AAVS 

AASI 

© 2004 TTC Timmler Technology GmbH. 

This document or any part thereof may not be reprinted, copied, or translated and figures and 

diagrams may not be used without prior written agreement from TTC Timmler Technology GmbH. 

Issued 02/2005. We reserve the right to make technical changes.

TTC Contents 

TTC Timmler 

Technology GmbH 

Zum Wetterschacht 1 

D-45659 Recklinghausen 

Tel +49(0)23 61-9 15 96 80 

Fax +49(0) 23 61-9 15 96 89 

Email: info@ttc-technology.de 

http://www.ttc-technology.de 

General Information 4 – 5 

• Air-conditioning in general 

• TTC cooling units, function, advantages and applications 

Installation Examples 6 – 9 

• Installation options 

• Air inlets and outlets for TTC cooling units 

• TTC cooling units in primary air mode 

Technical Data and Information 10 – 11 

• Dimensions 

• Series 

• Weights 

Performance Diagrams 12 – 13 

• Cooling capacity for categories 1 and 2 

• Pressure drop on the water side 

• Formulae to calculate capacity 

Design Example 14 – 15 

• Water and air cooling 

• Pressure drop on the water side 

Accessories 16 

• Capacity reducing factors for TTC air inlet and outlet grating 

• Part no. for TTC air inlet and outlet grating 

Installation Instructions 17 – 18 

• Pipe installation for TTC cooling units 

• Reduced capacity through infiltrated air 

Order and Calculation Sheet 19 

for TTC Modultherm cooling units and accessories 

3

4 

TTC Information About Air Conditioning 

Advantages of TTC Modultherm cooling units 

Why do we air condition rooms? Is ventilation required? 

Advantages of TTC Modultherm 

Working people spend the majority of 

their working life indoors. A maximum of 

physical and intellectual work is to be 

performed in this artificial environment. 

Studies with volunteers have shown that a 

persons productivity can be directly 

related to the thermal and air hygienical 

comfort of the room. In this context the 

air velocity, the relative humidity, the 

temperature gradient and the supply of 

primary air are of particular interest. 

Fig. 4.1-4.3 show mainly the results of 

studies by Prof. Ole Fanger and D. Wyon 

with a select number of volun-teers to 

determine peoples dissatisfaction with 

and acceptance of air-conditioning 

systems. 

Preferred cooling systems 

Either water or air is generally the carrier 

for the cooling energy. The following 

solutions are commonly used to cool down 

commercial premises: 

• Centrally treated and cooled primary air 

• Cooling of structural elements 

• Chilled ceiling systems 

• Wall and ceiling systems with cooling 

units or chilled beams 

• Cooling units or convectors combined 

with cooled primary air 

Intellectual Performance [%] 

95 

90 

85 

80 

75 

70 

65 

60 

22 23 24 25 26 27 28 29 30 

Room Temperature [°C] 

4.1 Intellectual performance at different 

room temperatures 

Issued 02/2005. We reserve the right to make technical changes. 

Relevant laws* and regulations* provide 

that commercially used spaces must have 

a primary airflow rate of approx. 6-9 m 3 / 

(h · m 2 ) or a change of air at 2-3 times the 

room volume to comply with air hygiene 

requirements. These minimal primary air 

streams can thus significantly reduce 

ventilation systems and save running and 

investment costs. 

*(Arbeitsstättenrichtlinie /German Work Place Directive, DIN 

1946 / Part 2 / Paragraph 3.2) 

4.2 Unhappiness at different temperatures 

Unhappy people [%] 

60 

40 

20 

10 

5 

1 

0,1 

Present in the room for 90 minutes 

Present in the room for 180 minutes 

0 1 2 3 4 5 6 

Temperature curve [K] 

Percentage of people who are unhappy with the 

rooms air conditioning, dependent on the: 

• floor level (ankle height) 0.1 m and 

head height (person is seated) 1.1m 

• No draughts, air speed 0.1-0.2 m/s 

• Condensation tray as standard, to 

prevent damage to furnishings and the 

building if condensation occurs 

• High fall ducts for the cooling air to 

provide high cooling capacity with 

a small space requirement 

• Silent operation without ventilation 

• Low running and investment costs for 

high comfort levels 

• Easy to upgrade if alterations are required 

• A wealth of design options for the 

room, for planners and architects 

• High thermal and hygienic comfort if 

combined with a primary air system 

• Additional to let area 

• Room temperatures can be individually 

controlled 

4.3 Acceptance with different airconditioning 

systems 

Unhappy People (%) 

40 

35 

30 

25 

20 

15 

10 

with RLT system 

without RLT system 

5 

0 

cooling ceiling* and 

distributed ventilation 

22 23 24 25 26 27 28 

Room temperature [°C] 

Acceptance with different air-conditioning systems 

and room temperatures. (A study by P. O. 

Fanger and D. Wyon) 

* Note! Instead of cooling ceilings, cooling units or 

cooling convectors could be used as an alternative.

TTC Modultherm Cooling System 

The functional principle of TTC Modultherm 

Functional principle 

The functional principle of the TTC cooling units is based on the 

natural fact that warm and cold air have a different air density 

ρ [kg/m 3 ]. 

At ceiling level warm air enters through the inlet grating (4) and 

is cooled down in the air cooler (1) through which cold water 

flows (see Fig. 5.1). If operated at high humidity, e.g. in a hotel 

room, special production rooms or when operated with-out preconditioned 

primary air a conden-sation tray is supplied as 

standard under-neath the air cooler. Through the fall duct (2) 

and an attractive air outlet (3) the cooled air is returned to the 

room. 

This cooled air is then warmed up again by heat sources in the 

room, e.g. people, lighting, computers and other electrical and 

electronic equipment, sunrays through the windows, the warmth 

of the walls and rises to the ceiling. 

The air velocity generated in the room through thermal 

conditions is very low and can only be measured with special 

equipment. This minute air circulation results in high thermal 

comfort levels and minimum temperature gradients in the 

occupied zone. The characteristic curves shown in the capacity 

diagrams on pages 12-14 are based on test rig measurements 

and were carried out under defined installation and operating 

conditions. 

Differing constructional conditions will need to be taken into 

account when determining the cooling performance of cooling 

units. TTC will be happy to help you with your calculations. 

H wirks. 

12 

11 

2 

1 

T erf. 

4 

3 

Performance factors 

The performance of the TTC cooling units depends on many 

factors, for example: 

• The effective fall duct height, H eff. 

• The fall duct depth D req. (for unit height 330 = 100 mm and 

for unit height 510 = 150 mm) 

• Spacing between sealing off walls (desired 600-800 mm, 

see page 17) 

• Smooth surface of the fall ducts and sealing off walls 

• Prevention of infiltrated air 

• Duct insulation on front and rear walls 

• The free cross-section of the inlet and outlet gratings (at 

least 70% of the visible surface of the finned cooling unit). 

For other cross-sections see the chapter Reduced 

Performance on page 16 

• Median temperature difference ∆ϑ m [K] between air intake 

and median temperature of the cooling medium 

• Water viscosity and quality (VDI 2025) 

• Flow path restriction caused by the pipe work or structural 

obstacles 

• Redirection of the cool air flow 

Area of application 

TTC Modultherm cooling units are ideally suited for all areas of 

application, where silent and efficient control of temperature is 

required: 

Small and open plan offices, Conference rooms, Computer 

rooms, Recording and TV studios, Hotel rooms, Public access 

areas, Reception areas, Department stores, Printing and paper 

works, Assembly and production facilities, to remove heat from 

electronic or electrical control cabinets, etc. 

10 

5.1 Room airflow in cooling 

mode using TTC cooling units 

(1) Air cooler incl. condensation 

tray 

(2) Fall duct for cold air 

(3) Air opening (min. 70 % free 

cross-section of the air cooler 

visible area) 

(4) Air inlet grating (min. 70 % 

free cross-section of the air 

cooler visible area) 

(10) False floor convector for 

heating mode 

(11) Required fall duct depth Dreq. (12) Effective fall duct height Heff. Issued 02/2005. We reserve the right to make technical changes. 

5

TTC Installation Examples 

Fig. 6.1 shows the installation of an AASS unit in a TV studio or a 

test centre on a wall (dry construction wall installed in post-andbeam 

construction). 

Key to 6.1 

14 

1 

4 

(1) Cooling unit incl. condensation tray to collect condensate in 

2 

dehumidification mode 

(2) Fall duct with sealing off walls (5) (spacing 600-800 mm) 

The minimum depth D is 100mm for unit height 33 and 

req. 

5 

150mm for unit height 51 

(6) Floor outlet grating with a free cross-section of 70 % of the 

visible area of the finned air cooler 

(4) Air inlet grating with a free cross-section of 70% of the 


9 

(5) Sealing off walls to stabilize the cold air flow 

(9) Mixing desk or test console in studios or test centres 

Note! 

The minimum requirements under 2, 3 and 4.1 must be complied 

with to ensure the quoted capacities. 

6 

For other free cross-sections see page 16 or contact TTC. 6.1 Room air flow with TTC cooling units in cooling mode 

Fig. 6.2-6.4 show three options for the air intake. Other options 

are available, please contact TTC. 

Fig. 6.2 shows the air flow to the cooling unit (1) via an air inlet 

grating (4) which has been integrated into a false ceiling. 

In Fig. 6.3 the air inlet grating has been replaced by an air gap 

(7) in the false ceiling. 

Fig. 6.4 shows ceiling panels with slits for the air intake. 

Optionally slots may also be placed at the ceiling edges. 

Key to 6.2-6.4 

(1) Cooling unit incl. condensation tray to collect condensate in 

dehumidification mode 


The minimum depth D req. is 100mm for unit height 33 and 




(7) Air gap in the false ceiling (70% free cross-section) 

(8) Ceiling panels with air slits (free cross-section, 70% or the 

visible area of the finned air cooler) 

Gaps between wall and ceiling (not shown) 

Note! 

The minimum requirements under 2, 4, 7 and 8 must be complied 

with to ensure the quoted capacities. 

For other free cross-sections see page 16 or contact TTC. 

6 

Example 1: Cooling unit on a wall 

Example 2: Air intake for cooling units 


2 

1 

6.2 Air intake through air inlet gratings in a false ceiling 

1 

2 7 

6.3 Air intake through an air gap in the false ceiling 

2 

1 

6.4 Air intake through ceiling panels 

4 

8


2 

1 

5 

4 

3 

4 

7.1 Room air flow with TTC cooling units in cooling mode 

2 

1 

5 

3 

4 

7.2 Air being released into the room through wall and floor 

gratings 

Example 3: Cooling unit behind a screen 

This example (Fig. 7.1) illustrates the installation of an AASS 

cooling unit above a cupboard or shelves. 

Key to 7.1 

(1) Cooling unit AASS incl. condensation tray to collect 

condensate in dehumidification mode 


The minimum depth, D req. is 100mm for unit height 33 and 


(3) Air outlet grating with a free cross-section of 70% of the 


(4) Screened air inlet grating (the free air intake should be 70% 

of the visible area of the finned air cooler) 


Note! 

The minimum requirements under 2, 3 and 4 must be complied 

with to ensure the quoted performances. 


Example 4: Air outlet grating into the room 

Fig. 7.2 illustrates the option for air to be dispersed into the 

room through an air outlet grating (3). This type of air flow into 

the room ensures a good, even temperature distribution. 

To dimension the floor air outlets consultation with a ventilation 

engineer is recommended. 

Key to 7.2 

(1) Cooling unit AASS incl. condensation tray to collect 









Note! 

The minimum requirements under 3 and 4 must be complied 

with to ensure the quoted performance. 



7


8 

Example 5: Cooling unit integrated into the duct 

Fig. 8.1 shows the AISI cooling unit (1) integrated into a fall 

duct (2). On the room side the cooling unit is screened by an 

architecturally appealing air inlet grating which should have a 

free cross-section of 70%. For this type of installation a 

mounting frame is supplied as standard. The top joint to the 

bare ceiling is formed, for example, by a waffle-type ceiling at 

the discretion of the architect and client. 

Key to 8.1 

(1) Cooling unit AISI incl. condensation tray to collect 


(2) Fall duct with sealing off walls 5 (spacing 600–800 mm) 








Note! 

The minimum requirements under 2, 3 and 4 must be complied 

with to ensure the quoted performance. 


2 

1 

5 

3 

5 

4 

2 

1 

5 

3 

8.1 TTC cooling unit integrated in the duct 

Example 6: Cooling unit on a wall with dispersed air outlet at the window 

Fig. 8.2 shows the cooling unit AASS (1) 

above a fall duct (2). On the room side the 

cooling unit is screened by an 

architecturally appealing air inlet grating 

(4) which should have a free cross-section 

of 70%. 

The air is returned to the room through a 

floor grating at the window. This type of 

installation always requires a false floor. 

Key to 8.2 

Items (1), (2), (4) are (5) equivalent to 

Fig. 8.1. 

(6) Floor grating integrated into the false 

floor as a dispersed air outlet. 

Note! 

The minimum requirements under 2, 3 and 

4 must be complied with to ensure the 

quoted performance. 

For other free cross-sections see page 16 

or contact TTC. 


8.2 Air distribution via air dispersal outlet in the floor 

4 

6


Example 7: Cooling unit in a false ceiling with additional primary air mode Function 

Function 

Example 7 (Fig. 9.1) shows how TTC units may be combined with a primary air system. 

Via the primary channel (8) conditioned outdoor air is blown at low speed into the fall 

ducts via channels or pipes. If suitable silencers are used the sound pressure level can 

be kept below 30 (dBA). 

Installation 

The cooling unit (1) can be installed on a wall between the bare and the false ceiling, 

on a cupboard or shelves. Design options showing how the cooling units could be 

covered on the room side are shown on page 6 (Fig. 6.2-6.4). 

For the primary air intake the following variants would be suitable: 

• Air outlet gratings (3) in walls, cupboards or shelves 

• Air outlet gratings in the false floor, see Fig. 8.1 on page 8 

• Dispersed air outlets 

Outdoor air flow 

In rooms to be occupied by people the outdoor air flow needs to be sized dependent on 

how many people are present in the room at the same time and what the room is used 

for (see the table on the right). 

The outdoor air flow is frequently provided at 2.5-3 times the change of room air. 

At the maximum outdoor temperature values (see DIN 4701 / parts 1 and 2 as well as 

VDI 2078) the outdoor air flow can be reduced by 50% of the minimum outdoor air 

flow per person. For rooms with additional pollution through smells (e.g. tobacco 

smoke) the minimum outdoor air flow is increased by 20 m3 /h per person. 

4 

3 

5 

1 

2 

13 

Minimum primary air flow per person 

and hour* 

Room type m3 /h 

Small office 30 

Open plan office 50 

Theatre/concert hall 20 

Canteen 30 

Conference room 30 

Cinema 20 

Banqueting hall 20 

Rest room 30 

Break room 30 

Class room 30 

Reading room 20 

Lecture theatre 30 

Show room 20 

Shop 20 

Museum 20 

Hotel room 30 

Public house/restaurant 

Gymnastic and sport hall 

40 

with seating for spectators 20 

*) in accordance with DIN 1946 / Part 2 /Paragraph 

3.2 

9.1 TTC Modultherm cooling unit with 

primary air mode 

(1) Air cooler incl. condensation tray 


(3) Air outlet grating (min. 70% free 

cross-section of the visible area of 

the air cooler) 

(4) Air inlet grating (min. 70% free crosssection 

of the visible area of the air 

cooler) 

(5) Sealing off walls to stabilize the cold 

air flow 

(13) Primary air channel 


9

TTC Dimensions and Information 

AASS 33 (51)** series 

Design 

(1) Air cooler made of copper pipes with 

aluminium fins, max. operating 

temperature 90 0C, max. operating 

pressure 10 bar 

(2) Housing completely made of 

galvanized steel plate 

(3) Water connection with R 3/4“, torsion 

protection 

(4) Condensation tray to collect 


(5) Condensate drain, ø12 mm, mounted 

on the condensate tray and supplied as 

standard 

Installation 

The cooling unit can be installed above 

shafts, cupboards or shelves. For examples 

see pages 6-9. 

Important: To ensure optimum operation 

sealing off walls spaced at 600 to 800 mm 

need to be installed in the fall ducts. 

10 

AAVS 33/51** series 

Design 



temperature 90 0 C, max. operating 



galvanized steel plate incl. mounting 

frame (6) 

(3) Water connection with R 3/4“, torsion 

protection 



(5) Condensate drain, ø12 mm, mounted 

on the condensate tray and supplied as 

standard 

(6) Mounting frame made of galvanized 

steel sheet, supplied as standard 

Installation 

The mounting frame is used to install the 

cooling unit in front of the fall duct wall. 





10.1 

Part no: AASS .. ..**) 08 10 12 14 16 18 20 22 24 

Finned length L finned [mm] 720 920 1120 1320 1520 1720 1920 2120 2320 

Total unit length L tot. [mm] 800 1000 1200 1400 1600 1800 2000 2200 2400 

Total weight (33) ≈ [kg] 26 32 39 46 52 59 65 72 79 


**) see order key on page 2 

10.2 

3 

40 

40 

*) Dimensions in brackets are for construction height 51 

Part no: AAVS .. ..**) 08 10 12 14 16 18 20 22 24 






2 

1 

1 

2 

Finned length Lfinned 

Frame length FL 



4 

330 (510)* 

300 (510)* 


5 

25 

105 

5 

50 

30 

Ø12 mm 

200 

1 

5 

150 

5 

80 

3 

300 

4 

30 

100 

(150)* 

6 

100 

(150)*

TTC Dimensions and Information 

11.1 

Part no: AISI .. ..**) 08 10 12 14 16 18 20 22 24 






11.2 

3 

40 

3 

40 

Part no: AASI .. ..**) 08 10 12 14 16 18 20 22 24 






5 

345 (525)* 


2 

5 

2 



50 



50 

25 

Ø 12 mm 

225 

(405)* 

145 

(325)* 

45 

25 

Ø 12 mm 

145 

(325)* 


6 

30 

70 

70 

153 

1 

4 

1 

4 

153 

30 

6 

345 (525)* 

225 

(405)* 

AISI 33 (51)** series 

Design 



temperature 90 0C (2) Housing completely made of 


frame (6) 

(3) Water connection R 3/4“ torsion 

protection 



(5) Condensate drain, ø12 mm, 

mounted on the condensate tray and 

supplied as standard 



Installation 

The cooling unit is installed in the fall 

duct for the cold air (see page 8). 




AASI 33 (51)** series 

Design 



temperature 90 0C, max. operating 




frame (6) 

(3) Water connection R 3/4“ torsion 

protection 



(5) Condensate drain, ø12 mm, 

mounted on the condensate tray and 

supplied as standard 



Installation 

The mounting frame is used to install the 

cooling unit in front of the fall duct wall. 





11

TTC Capacity Diagrams 

Category 1 

Specific cooling capacity: category 1 Specific pressure drop heat exchanger: category 1 

1700 

1600 

1500 

1400 

1300 

1200 

1100 

1000 

900 

800 

700 

600 

500 

400 

300 

280 

200 

100 

12.1 

12 

Category 1 (cooling) 

2,2 m 

6 7 8 9 10 11 12 13 

Median temperature difference ∆ϑ [K] m 

6,0 m 

5,0 m 

4,0 m 

3,5 m 

3,0 m 

2,5 m 

2,0 m 

1,5 m 

Formula to calculate the median temperature difference ∆ϑ m 

1 

< 

Specific cooling capacity q spec. [W/m] 

. 

< 

< 

t [°C] + t [°C] 

W1 W2 ∆ϑ [K] = t – for cooling mode 

m R 

2 

∆ϑ m [K] = median temperature difference between cooling 

medium and room temperature 

t W1 [°C] = cold water inlet 

t W2 [°C] = cold water outlet 

t R [°C] = room temperature 


< 

15 

10 

8 

6 

5 

4 

3 

2 

1,0 

0,8 

0,6 

0,5 

0,4 

0,3 

0,2 

0,1 

0,08 

0,06 

kg/h 10 

kg/s 

12.3 

. 

< > 

Specific pressure drop ∆p w specif. [kPa/m] finned 

0,003 

15 

20 

25 30 40 50 60 80 100 150 200 300 400 500 700 

0,005 0,007 0,01 0,015 0,02 0,03 0,04 0,06 0,08 0,1 0,15 0,20 

. 

< Water mass flow mw > 

Formula to calculate the overall sensitive cooling capacity of 

the TTC Modultherm cooling unit 

3 

. . 

Q [W] = q [W/m] · L [m] 

K(tot.) K(spec.) finned 

· 

QK.(tot.) . 

qspecif. [W] 

[W/m] 

= total cooling capacity of a cooling unit 

= specific cooling capacity of a cooling unit 

Lfinned [m] = finned length of the cooling unit 

. 

Formula to calculate the specific water mass flow mw · q [kW] · L [m] 

· 

(specif.) finned 

4 m 

· 

[kg/h] = 860 · 

W t - t [K] 

W2 W1 

Formula to calculate the overall pressure drop ∆p of the 

w(tot.) 

cooling unit on the water side 

. 

. 

· 

5 ∆p [kPa] = ∆p [kPa/m] • L [m] 

w(tot.) w(spec.) finned 

∆p. [kPa/m] = see figure 12.3 

w(specif.)

TTC Performance Diagrams 

Category 2 

Specific cooling capacity: category 2 Specific pressure drop heat exchanger: category 2 

2600 

2500 

2400 

2300 

2200 

2100 

2000 

1900 

1800 

1700 

1600 

1500 

1400 

1300 

1200 

1100 

1000 

900 

800 

700 

600 

500 

435 

400 

300 

200 

13.1 

Specific cooling capacity q spec. [W/m] 

. 

< 

< 

Category 2 (cooling) 

< 

2,2 m 

6 7 8 9 10 11 12 13 14 15 16 

7,0 m 

6,0 m 

Median temperature difference ∆ϑ m [K] 

5,0 m 

4,0 m 

3,5 m 

3,0 m 

2,5 m 

2,0 m 

1,5 m 

Formula to calculate the overall pressure drop ∆p of the 

w(tot.) 

cooling unit on the water 

. 

. 

5 ∆p [kPa] = ∆p [kPa/m] • L [m] 

w(tot.) w(spec.) finned 

. 

∆p [kPa/m] = see Fig. 12.3 

w(spec.) 

< 

15,0 

10,0 

8,0 

6,0 

5,0 

4,0 

3,0 

2,0 

1,5 

1,0 

0,8 

0,6 

0,5 

0,4 

0,3 

0,2 

0,1 

0,09 

0,08 

0,06 

0,05 

0,04 

0,03 

0,02 

kg/h 

217 kg/h 

50 60 80 100 150 200 300 400 500 700 1000 1500 2000 3000 4000 

kg/s 

13.3 

0,015 0,02 0,03 0,04 0,06 0,08 0,1 0,15 0,20 0,30 0,40 0,6 0,8 01,0 1,4 

Formula to calculate the medium temperature difference ∆ϑ m 

1 

. 

< > 

Specific pressure drop ∆p w specif. [kPa/m] 

t [°C] + t [°C] 

W1 W2 

∆ϑ [K] = t – for cooling mode 

m R 2 

∆ϑ m [K] = median temperature difference between cooling 

medium and room temperature 

t W1 [°C] = cold water inlet 

t W2 [°C] = cold water outlet 

t R [°C] = room temperature 

Formula to calculate the overall sensitive cooling capacity of 

the TTC Modultherm cooling unit 

3 

. . 

Q [W] = q [W/m] · L [m] 

K(tot.) K(spec.) finned 

· 

Q [W] K.(tot.) 

. 

q [W/m] spec. 

= total cooling capacity of a cooling unit 

= specific capacity of a cooling unit 

L [m] finned = finned length of a cooling unit 

Formula to calculate the specific water mass flow mw 4 m· [kg/h] = 860 · 

W 

· 

· 

q [kW] · L [m] 

(spec.) finned 

t - t [K] 

W2 W1 

< 

. 

Water mass flow mw Issued 02/2005. We reserve the right to make technical changes. 

> 

13

TTC Design Example 

Example 1: Dimensioning a cooling unit for cooling mode 

Calculation assumptions > 

Calculate ∆ϑ m 

Determine q· K(spec.) 

Required ribbed width, L finned > 

Required TTC cooling units > 

Cooling performance on the 

water side > 

Result > 

14 

> 

> 

Task: 

An office (see page 15, Fig. 15.1) with a sensitive cooling load Q = 2.000 W is to be cooled 

K(sen.) 

with AASS or AVSI series cooling units and also to be ventilated with additional, pre-conditioned 

primary air. The unit is to be installed above a range of cupboards or a set of shelves at a height of 

2.5m (see Fig. 15.1). The room volume is approx. 80 m3 . The pre-conditioned primary air is blown 

into the room at 180 · 

C through flexible pipes in the fall ducts. 

• Cold water temperatures: t = 16 W1 0C and t = 20 W2 0C • Room temperature: t = 26 ºC 

R 

• Primary air temperature: t = 18 ºC 

L(ZU) 

• Max. possible installation length L for the cooling unit(s) = 5.50 m 

max. 

• The primary air rate, V is 240 m A(prim) 3 · 

/h at 3 times room air change 

• The sound pressure level shall not exceed 30 dB(A) 

• The effective fall duct hight H ≈ 2.2 m 

eff. 

Step-by-step illustration of the solution: 

1. Calculate the median temperature difference ∆ϑ with the following formula 

m 

∆ϑ = t - [(t + t ) : 2] (see pages 12/13, equation 1) 

m R W1 W2 

∆ϑ = 26 - [(16 + 20) : 2] = 8 K 

m 

2. For ∆ϑ = 8 K take the specific cooling values q 

· 

from the diagrams for capacity 

m Conv.(spec.) 

categories „1“ and „2“ (see page 12/13): 

• Category „1“ = 280 W/m 

• Category „2“ = 435 W/m 

this results in: 

a) required finned length, L for category 1 = 2000 W : 280 W/m ≈ 7.15 m 

finned 

b) required finned length, L for category 2 = 2000 W : 435 W/m ≈ 4.60 m 

finned 

Conclusion: 

• Due to structural restrictions (max. 5.5m) the length required under a), L = 7m, cannot be 

finned 

used 

• The length calculated under b), L = 4.6 m meets the requirement 

finned 

3. Select the required TTC cooling units 

• Max. available TTC cooling unit length, L total = 2.4 m with L finned = 2.32 m 

• To fulfil the requirement you will need 2 TTC performance category 2 cooling units 

2 off: AASS.24.51.2._.2 (see order key on page 2) 

4. Calculation to check the actual cooling capacity on the water side 

· 

Q [W] = q [W/m] · W [m] · n [units] 

K(total) spec. finned 

· 

= 435 · W/m · 2.32 m · 2 ≈ 2020 W = 2.02 kW (required 2.000 kW) 

Q K(total.) 

Cooling power of the primary air > 5. Calculate the additional cooling capacity from the primary air 

· 

V [m A(tot.) 

Q (kW) = K(air) = 0.64 kW 

3 /h] · r [kg/m . L 3 ]· cp[kJ/kg·K] · ∆t [K] 

L L 

3600 

240 (m3 /h) · 1,2 (kg/m . 3 · 

Q [kW] = 

K(air) 

· 

) · 1 (kJ/kg·K) · 8 (K) 

3600 

Overall cooling power > 6. In total the cooling capacity on the water and air side: 

. 

Q = 2.02 kW (step4 4) + 0,64 kW (step 5) = 2.66 kW 

K(water,air) 

Please note > 


• If TTC Gratings are used as air inlets and outlets (see page 16) the cooling power calculated 

under point 4 must be multiplied by the correction factors in tables 16.1-16.7.

TTC Design Example 

Example 2: How to calculate the pressure drop on the water side 

Calculation assumptions > 

Result water mass flow > 

Specific pressure drop > 

Result ∆p w(tot.) 

> 

Task 

To calculate the pressure drop on the water side, ∆p of the cooling unit with part no: 

W(total) 

AASS.24.51.2._.2 in example 1 (page 14) 

Parameters required for the calculation: 

• Cold water temperatures: t = 16 ºC; t = 20 ºC 

W1 W2 

• Finned length of the cooling unit, L = 2.32 m 

finned 

· 

• Specific cooling capacity q = 435 W/m (see page 14, calculation step 2) 

K(spec.) 

Solution 

. 

The water pressure drop is approximated via the water mass flow m using equation 4 (see page 

W 

13) 

· 

m W [kg/h] = 860 · 

· 

q [kW/m] · L [m] 

(spezif.) finned 

t - t [K] 

W2 W1 

0,435 kW/m · 2,32 m 

20 0C - 16 0 m 

· 

= 860 · ≈ 217 kg/h 

W 

C 

From diagram 13.3 (page 13) take the 

specific hydraulic pressure drop ∆p w(spec.) ≈ 0,09 kPa/m 

The total water pressure drop ∆p W(total) for the cooling unit (L finned = 2.32 m) is: 

∆p w(ges.) [kPa] = ∆p w(spezif.) [kPA/m] · L finned [m] 

∆p w(total) = 0.09 kPa/m · 2.32 m ≈ 0.21 kPa 

3. Illustration of the system calculated in examples 1 and 2 

15.1 

(1) Air cooler with condensation tray 


(3) Air outlet grating 

(4) Air inlet grating 

(8) Primary air channel 

(AL) Sealing batten against infiltrated air 

Note! 

For other free cross-sections of the air inlet 

and air outlet gratings please refer to page 

16 or contact TTC. 


15

TTC Air Inlet and Outlet Gratings 

Order no. 

Reduced performance of the TTC air outlets in conjunction with TTC cooling units 

TTC Air inlet and outlet gratings Rod free Reduced performance factors ”f“ 

All figures are based on the cooling unit and the air outlet 

graving being identical in length. The heights of the cooling 

units are for a grating height of 200mm in line with the 

spacing 

”a“ 

crosssection 

TTC Modultherm cooling unit series 

AASS AASS AAVS AAVS AISI AISI AVSI AVSI 

preliminary documentation. 

mm % 33 51 33 51 33 51 33 51 

Note: The cooling power of the cooling unit in the diagrams (pages 12 and 13) must be corrected by the reduced performance factors 

”f“ stated in tables 16.1-16.7 if the above air inlet and outlet gratings are used. The reduced performance factors ”f“ are dependent 

on the type and the free cross-section of the gratings. The following formula is to be used: 

Q K(reduced) = Q K(1unit) · f min 

QK(reduced) QK(1unit) fin = reduced cooling capacity 

= calculated cooling capacity p.unit 

= for in flowing room air 

= for out flowing cooling air 

Example 

Q = 1.01 kW (see example on page 12) 

K(1unit) 

f = 0.84 (Table 16.3, Type AASS 51) 

in 

f = 0.84 (Table 16.3, Type AASS 51) 

out 

=> f = 0.84 

min 

f out 


16 

16.1 

16.2 

a a 

a a 

16.3 

a a 

16.4 

a a 

Longitudinal gratings rigid (full 

profile), made of aluminium, for 

air inlets and outlets in ceilings, 

walls and on the floor 

Comb gratings rigid (full 

profile), made of aluminium or 

V2A, for air inlets and outlets in 

ceilings, walls and on the floor 

Part no: TTC-KSF ❐ Alu ❐ V2A 

Comb gratings rigid (T-profile), 

(full profile), made of aluminium, 

for air inlets and outlets in 

ceilings, walls and on the floor 

Part no: TTC-KST ❐ Alu 

Comb gratings rigid (U-profile), 

(full profile), made of V2A or aluminium, 

for air inlets and outlets 

in ceilings, walls and on the floor 

20 88 0.94 0.84 0.94 0.84 0.94 0.84 0.94 0.84 

15 83 0.93 0.82 0.93 0.82 0.93 0.82 0.93 0.82 

10 77 0.92 0.81 0.92 0.81 0.92 0.82 0.92 0.81 

20 87 0.94 0.83 0.94 0.83 0.94 0.83 0.94 0.83 

15 83 0.93 0.82 0.93 0.82 0.93 0.82 0.93 0.82 

10 77 0.92 0.81 0.92 0.81 0.92 0.82 0.92 0.81 

20 80 0.92 0.82 0.92 0.82 0.92 0.82 0.92 0.82 

15 73 0.91 0.80 0.91 0.80 0.91 0.80 0.91 0.80 

10 65 0.88 0.78 0.88 0.78 0.88 0.78 0.88 0.78 

15 73 0.91 0.80 0.91 0.80 0.91 0.80 0.91 0.80 

10 65 0.88 0.78 0.88 0.78 0.88 0.78 0.88 0.78 

16.5 

Roll gratings flexible (hollow 

17.5 70 0.81 0.71 0.81 0.71 0.81 0.71 0.81 0.71 

7 

profile), made of V2A or alumi- 

16 60 0.79 0.70 0.79 0.70 0.79 0.70 0.79 0.70 

a nium, for air outlets on the floor 

12.5 62 0.79 0.69 0.79 0.69 0.79 0.69 0.79 0.69 

a 

Part no: TTC-QFH ❐ Alu ❐ V2A 

16.6 

16.7 

a 

a 

a 

a 

Part no: TTC-LSF ❐ Alu 

Part no: TTC-KSZ ❐ Alu ❐ V2A 

Roll gratings flexible (T-profile), 

made of aluminium, for air 

outlets on the floor 

Part no: TTC-QFT ❐ Alu 

Roll gratings flexible (Tprofile), 

made of aluminium, 

for air outlets on the floor 

Part no: TTC-BST ❐ Alu 

20 80 0.83 0.74 0.83 0.74 0.83 0.74 0.83 0.74 

15 70 0.81 0.71 0.81 0.71 0.81 0.71 0.81 0.71 

10 65 0.89 0.70 0.79 0.70 0.79 0.70 0.79 0.70 

8 40 0.71 0.61 0.71 0.61 0.71 0.61 0.71 0.61 

Q K(reduced) = 1.01 kW · 0.84 ≈ 0.85 kW 

Control of cooling capacity 

2 x AASS = 1,36 kW 

Cooling power of inflowing primary 

air = 0,64 kW 

Total of cooling capacity 2000 W = 2,0 kW

TTC Instructions For Pipe Work Installation 

Pipe work installation examples 

Modultherm AASS cooling unit Modultherm AISI cooling unit 

17.1 

Modultherm AAVS cooling unit Modultherm AASI cooling unit 

E 

17.2 

G 

E 

F 

Fall duct walls 

Spacing 600…800 mm 

A Cold water supply pipes (do 

not install these in front of 


B Stop valves for forward and 

return flow 

C Electrical control valve 

D Sealing off walls in the fall 

duct for the cooling air 

A 

A 

D 







return flow 




D 

F 

G 

B 

C 

≈ 250 

H 

~ 

G 

H 

C 

E Siphon to drain 

condensation 

F Side seals on the cooling 

unit against infiltrated air 

G Flexible connecting hoses 

H Relief valve 


condensation 





I 

~ 

B 

A 





return flow 




B 

H 

G 

17.3 

17.4 

E 

A A 

F 

E 

~ 



~~ 

F 

D 







return flow 




D 

F 

F 

I 


condensation 





I Mounting frame supplied as 

standard 

H 

I 


condensation 






C 

H 

~ 

A 

B 

C 

17

TTC Best Performance By Reducing Infiltrated Air 

Design of side sealing off walls and fall ducts 

18 

1 2 2 Correct 1 

Installation 

600…800 mm 

18.1 

The cooling unit has been correctly installed, 

no reduction in performance. 

(1) Side sealing off walls 

(2) Fall duct walls correctly arranged 

Infiltrated Air Infiltrated Air 

1 2 2 

1 

600…800 mm 

Incorrect 

Installation 

Correct 

Installation 

100 

(150)* 

18.7 

The calculated performance will be 

achieved with this installation. 

Air infiltration will not be possible. 

1 

Infiltrated Air 

600…800 mm 

2 2 Incorrect 

Installation 

1 

18.2 

The Cooling unit is too big. The calculated 

performance will not be achieved. 


(2) Fall duct walls 

Air 

Air 

Turbulence 

turbulence 

1 2 2 

1 

600…800 mm 

Incorrect 

Installation 

18.4 18.5 18.6 

The cooling unit is too small. The calculated 




Installation in front of ducts 


The cooling unit is too small. The calculated 




Incorrect 

Installation 

100 

(150)* 

18.8 

The calculated performance will not be 

achieved with this installation (air 

turbulences). 

Infiltrated Air Infiltrated Air 

1 2 2 Incorrect 1 

600…800 mm Installation 

18.3 

The cooling unit is too big. The calculated 




1 Unstable air flow Incorrect 1 

due to lack of fall Installation 

duct walls 

Fall ducts have not been installed. The 

calculated performance will not be 

achieved with this installation. 


Incorrect 

Installation 

100 

(150)* 

18.9 

The calculated performance will not be 

achieved with this installation (problems 

with infiltrated air).

TTC Calculation and Order Sheet 

Company Name 

Address 

Tel 

Fax 

Project Room 

Item 

Calculation Parameters Parameters Notes, Calculation Formulae 

1 Req. sensible cooling performance QK(sens.) W 

2 Clear room height hclear m 

3 Clear room width wclear m 

4 Clear room length lclear m 

5 Room volume 

m 

6 Effective fall duct height Heff. 7 To be installed above: 

8 Max. length for cooling unit(s) L (total) 

9 Max. height for cooling unit(s) H (total) 

3 /h 

m 

❏ Cupboard, shelves ❏ in front of ❏ above ❏ in the fall duct 

m 

m 

10 Cold water inlet t w1 

11 Cold water outlet t w2 

12 Room temperature t R 

13 Primary air temperature tL(in) 14 Primary air volume flow VL(in) m 

15 Max. sound pressure level for primary air 

Calculate which cooling unit is required 

16 Median temperature difference ∆ϑm 17 Specific cooling capacity qKspec. 18 Total ribbed length required Lfinned 19 Specific cooling capacity qKspec. 20 Total finned length required Lfinned 21 Select the no. of cooling units required 

22 Required length, Lfinned for one cooling unit 

23 Cooling capacity Q (one cooling unit) 

K(1 unit) 

24 Corrected cooling capacity QK(1 unit) 

25 Cooling capacity Q from V K air L(in) 

26 Water mass flow mW 27 Specific pressure drop water side ∆pWspec. 28 Total pressure drop ∆pWtotal 3 /h 

dB(A) 

. 

> for category 1: 

K 

W/m 

. 



m 

W/m 

> for category 2: m 

n 

. 

. 

. 

m 

W 

W 

kW 

Calculate the pressure difference on the water side 

. 

. 

. 

kg/h 

kPa/m 

kPa 

Vital for your order 

Cooling unit part no. (see page 2): 

Type 

Air inlet grating part no: 

Type 

Make: TTC Timmler Technology GmbH Make: Make: 

Zum Wetterschacht 1, D-45659 Recklinghausen 

0C 0C 0C 0C With regard to the whole of the room 

h • w • l clear clear clear 

See Page 5, 5.1 

Please tick as appropriate 

With reference to the installation space 

With reference to the installation space 

See Page15, 15.1 

Item 12 – [Item 10 + Item 11 : 2] 

From Fig. 12.1 (s. page 12) 

(Item 1) : (Item 17) 

From Fig. 13.1 (s. page 13) 

(Item 1) : (Item 19) 

See tables on pages 10 and 11 

(Item 18) or (Item 20) : (Item 22) 

(Item 22) · (Item 17) or (Item 19) 

See table on page 16 

(Item 14) · 0.0003 · (Item 12 - Zif. 13) 

860 · [Item 23 (in kW) : Item 11-Item 10] 

See Fig. on page 12 or 13 

Item 22 · Item 26 

Air outlet grating part no: 

Type 


19

TTC Timmler Technology TTC Silent Gravitiy Cooling – Modultherm ...

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