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FORUM PROCEEDINGS<br />

In this manner we finish with as many stacks as there<br />

are singularities. They are properly coded with respect to<br />

each other. Next they are fed through the collator. Here<br />

all cards belonging to the same coordinates are stacked together.<br />

This new total stack enters the accounting machine<br />

where the values cp, tf' x, yare added together for each<br />

coordinate. A new card is summary punched for each addition.<br />

The new resulting stack is the solution. Other singularities<br />

can be added to it if a modification of it is desired.<br />

The solution is not yet in the fon11 in which we need it.<br />

We must find the points for a number of (equally spaced)<br />

constant values of tf (stream lines). The .t' and y values<br />

appearing along these lines furnish coordinates of the<br />

physical stream lines. One of these is the profile. What is<br />

needed is a fast and simple inverse interpolation for tf and<br />

a direct interpolation for .t' and y. In the absence of a fast<br />

method, we use the old and time-honored method of cross<br />

plotting. We hope to be able some day to do this part by<br />

machine. As long as machines become faster there is hope.<br />

60· - 60· Bucket Turn<br />

FIGURE 6<br />

Here are some of the more simple examples which we<br />

have done. We are collecting experience about the most<br />

promising combination of singularities. Figure 5 shows· a<br />

very simple flow turn which has a constant velocity on the<br />

inside of the turn. By the addition of two singularities, one<br />

source and one sink, we arrive at turning streamlines, one<br />

of which has constant velocity throughout. The other<br />

streamlines decelerate first and then accelerate. None of<br />

these streamlines generates a closed profile.<br />

The simplest closed curve we could generate is shown<br />

in Figure 6. A vortex source flows into a vortex sink and<br />

both are 0pP9sed by equal and opposite singularities. This<br />

results in a closed curve in both hodograph (circle) and<br />

physical plane. Here we have a saddle point which is not<br />

situated at minus infinity. As a result, the profile does not<br />

have a finite entrance angle at its nose. The velocity there<br />

is not zero. There is, by the way, a very simple condition<br />

which assures that if you have a closed curve in the hodograph<br />

map you will also get a closed physical flow curve.<br />

65

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