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FORUM PROCEEDINGS<br />
In this manner we finish with as many stacks as there<br />
are singularities. They are properly coded with respect to<br />
each other. Next they are fed through the collator. Here<br />
all cards belonging to the same coordinates are stacked together.<br />
This new total stack enters the accounting machine<br />
where the values cp, tf' x, yare added together for each<br />
coordinate. A new card is summary punched for each addition.<br />
The new resulting stack is the solution. Other singularities<br />
can be added to it if a modification of it is desired.<br />
The solution is not yet in the fon11 in which we need it.<br />
We must find the points for a number of (equally spaced)<br />
constant values of tf (stream lines). The .t' and y values<br />
appearing along these lines furnish coordinates of the<br />
physical stream lines. One of these is the profile. What is<br />
needed is a fast and simple inverse interpolation for tf and<br />
a direct interpolation for .t' and y. In the absence of a fast<br />
method, we use the old and time-honored method of cross<br />
plotting. We hope to be able some day to do this part by<br />
machine. As long as machines become faster there is hope.<br />
60· - 60· Bucket Turn<br />
FIGURE 6<br />
Here are some of the more simple examples which we<br />
have done. We are collecting experience about the most<br />
promising combination of singularities. Figure 5 shows· a<br />
very simple flow turn which has a constant velocity on the<br />
inside of the turn. By the addition of two singularities, one<br />
source and one sink, we arrive at turning streamlines, one<br />
of which has constant velocity throughout. The other<br />
streamlines decelerate first and then accelerate. None of<br />
these streamlines generates a closed profile.<br />
The simplest closed curve we could generate is shown<br />
in Figure 6. A vortex source flows into a vortex sink and<br />
both are 0pP9sed by equal and opposite singularities. This<br />
results in a closed curve in both hodograph (circle) and<br />
physical plane. Here we have a saddle point which is not<br />
situated at minus infinity. As a result, the profile does not<br />
have a finite entrance angle at its nose. The velocity there<br />
is not zero. There is, by the way, a very simple condition<br />
which assures that if you have a closed curve in the hodograph<br />
map you will also get a closed physical flow curve.<br />
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