Articles - CCRMA - Stanford University

Tonal Correction Filter
Let hk(n) = impulse response of kth system pole. Then
∞
Ek = |hk(n)| 2 = total energy
n=0
Thus, total energy is proportional to decay time.
To compensate, Jot proposes a tonal correction filter
E(z) for the late reverb (not the direct signal).
First-order case:
where
and
as before.
E(z) = 1−bz−1
1−b
b = 1−α
1+α
α ∆ = t60(π/T)
t60(0)
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