P_PracticeExam6_05-1..
P_PracticeExam6_05-1..
P_PracticeExam6_05-1..
You also want an ePaper? Increase the reach of your titles
YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.
! 1 $<br />
A. # &<br />
"<br />
#<br />
! %<br />
&<br />
B.<br />
! 1 $<br />
# &<br />
1<br />
"<br />
#<br />
! %<br />
& "<br />
2<br />
C.<br />
1 1<br />
"<br />
! ! " 2<br />
D. e!<br />
e ! " 1<br />
PRACTICE EXAMINATION NO. 6<br />
10. X and Y are independent and both distributed uniformly from 0 to 20. Find the probability<br />
density function of Z = 25X ! 10Y .<br />
A. fZ ( z)<br />
= <strong>1.</strong>5 where non-zero<br />
B. Stepwise formula:<br />
# 200 ! z<br />
%<br />
, !200 " z < 0,<br />
100000<br />
% 1<br />
fZ ( z)<br />
= $ , 0 " z < 300,<br />
% 300<br />
% 500 + z<br />
, 300 " z " 500.<br />
&<br />
% 100000<br />
C. fZ ( z)<br />
= 1<br />
where non-zero<br />
200<br />
1<br />
!<br />
200 D. fZ ( z)<br />
= 200e z<br />
, for z > 0, zero otherwise<br />
E. Stepwise formula:<br />
# 200 + z<br />
%<br />
, !200 " z < 0,<br />
100000<br />
% 1<br />
fZ ( z)<br />
= $ , 0 " z < 300,<br />
% 500<br />
% 500 ! z<br />
, 300 " z " 500.<br />
&<br />
% 100000<br />
1<strong>1.</strong> Let X( 1)<br />
, X( 2)<br />
,…, X( 8)<br />
be the order statistics from a random sample X1, X2,…, X8 of size 8<br />
from a continuous probability distribution. What is the probability that the median of the<br />
distribution under consideration lies in the interval ! X( 2)<br />
, X #<br />
" ( 7)<br />
$ ?<br />
110 112 119 124<br />
A. B. C. D.<br />
128 128 128 128<br />
ASM Study Manual for Course P/1 Actuarial Examination. © Copyright 2004-2007 by Krzysztof Ostaszewski - 253 -<br />
E.<br />
"<br />
e<br />
1<br />
! 1<br />
E. Cannot be determined<br />
12. In a block of car insurance business you are considering, there is a 50% chance that a claim<br />
will be made during the upcoming year. Once a claim is submitted, the claim size has the Pareto<br />
distribution with parameters ! = 3 and ! = 1000. Only one claim will happen during the year.