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Degree of Parabolic Quantum Groups - Dipartimento di Matematica ...

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2. Algebras with trace 20<br />

and the power sums function ψk = xk i . It is easy to prove that, for every<br />

k ≤ n, is a polynomial pk(y1, . . .,yk) with rational coefficient, independent<br />

<strong>of</strong> n and such that:<br />

σk = pk(ψ1, . . .,ψk).<br />

We then set<br />

σk(a) = pk(tr(a), . . .,tr(a k )).<br />

Next we can formally define for every element a ∈ A and for every integer<br />

d a d th -characteristic polynomial:<br />

χd,a[t] =<br />

d<br />

(−1) i σi(a)t d−i<br />

i=0<br />

Definition 2.1.2. 1. We say that an algebra A with trace satisfies the<br />

d th -formal Cayley-Hamilton theorem if χd,a[a] = 0 for all a ∈ A.<br />

2. We say that A has degree d if it satisfies the d th -formal Cayley-Hamilton<br />

theorem and tr(1) = d.<br />

Note that algebra with trace <strong>of</strong> degree d form a category with morphisms<br />

being algebra morphisms compatible with trace, which will be denoted by<br />

Cd.<br />

2.2 Representations<br />

We are interested in a representation theory <strong>of</strong> algebra with trace <strong>of</strong> degree<br />

d. Let give an example<br />

Example 2.2.1. Let A be a commutative algebra, then Md(A) with the<br />

or<strong>di</strong>nary trace is an algebra with trace <strong>of</strong> degree d.<br />

Definition 2.2.2. A n <strong>di</strong>mensional representation <strong>of</strong> an algebra with trace R<br />

with value in a commutative algebra A is an homomorphism ρ : R → Mn(A)<br />

compatible with the trace map. If A = k we think <strong>of</strong> this representation as<br />

a geometric point.<br />

Remark 2.2.3. We have necessarily n = d, since<br />

d = ρ(tr(1)) = tr(ρ(1)) = tr(I) = n,<br />

where I is the identity matrix <strong>of</strong> Mn(A).<br />

Before stating the main theorem <strong>of</strong> this section, we will give some examples<br />

<strong>of</strong> algebra with trace. In order to simplify the treatment and stick to a<br />

geometric language we assume, from now until the end <strong>of</strong> the chapter, that<br />

k is algebraically closed and <strong>of</strong> characteristic 0.

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