23.07.2013 Views

Degree of Parabolic Quantum Groups - Dipartimento di Matematica ...

Degree of Parabolic Quantum Groups - Dipartimento di Matematica ...

Degree of Parabolic Quantum Groups - Dipartimento di Matematica ...

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

5. <strong>Quantum</strong> universal enveloping algebras for parabolic Lie algebras 65<br />

Then the claim is proved.<br />

Theorem 5.4.19. If l is a good integer (cf theorem 4.5.7)<br />

deg Sǫ(p) = l 1<br />

2(l(w0)+l(w l 0)+rank(w0−w l 0))<br />

Pro<strong>of</strong>. Denote by Sǫ(p) the quasi polynomial algebra associated to Sǫ(p).<br />

We know by the general theory that<br />

Let xi denote the class E β 1 i<br />

deg Sǫ(p) = deg Sǫ(p).<br />

for i = 1, . . .,h and yj the class <strong>of</strong> Fβj for<br />

j = 1, . . .,N, then from theorem 5.4.14 we have<br />

xixj = ǫ (β1 i |β1 j ) xjxi, (5.18)<br />

yiyj = ǫ −(βi|βj) yjyi. (5.19)<br />

if i < j. Thus we introduce the skew symmetric matrices A = (aij) with<br />

aij = (βi|βj) for i < j and Al <br />

= a ′ <br />

ij<br />

with a ′ ij = (β1 i |β1 j ) for i < j.<br />

Let ki the class <strong>of</strong> Ki, using the relation in theorem 5.4.14 we obtain a<br />

n × N matrix B = ((wi|βj)) and a h × N matrix Bl = ((wi|β1 j )).<br />

Let t = 2 unless the Cartan matrix is <strong>of</strong> type G2, in which case t = 6.<br />

Since we will eventually reduce modulo l an odd integer coprime with t,<br />

we start inverting t. Thus consider the free Z <br />

1 module V + with basis<br />

t<br />

u1, . . .,uh, V − with basis u ′ 1 , . . .,u′ N and V 0 with basis w1, . . .,wn. On<br />

V = V + ⊕ V 0 ⊕ V − consider the bilinear form given by<br />

⎛<br />

T = ⎝<br />

A l − t B l 0<br />

B l 0 −B<br />

0 t B −A<br />

then the rank <strong>of</strong> T is the degree <strong>of</strong> Sǫ(p). Consider the operators M l =<br />

A l − t B l 0 , M = 0 t B −A , and N = B l 0 −B , so that<br />

T = M l ⊕ N ⊕ M.<br />

Note that<br />

and<br />

B(u ′ i) = βi<br />

B l (ui) = β 1 i<br />

Set T1 = Ml ⊕ M, then using the notation <strong>of</strong> lemma 4.5.4, we have<br />

Lemma 5.4.20. The vector vω = <br />

t∈Iω(wl 0 ) ut − ω − w0(ω) + <br />

t∈Iω(w0) u′ t,<br />

as ω runs through the fundamental weights, form a basis <strong>of</strong> the kernel <strong>of</strong> T1.<br />

⎞<br />

⎠,

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!