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LM741 1 2 2 3 3 4 8 7 7 +15 V 15 V 4 6 6out 5 + - Indiana University

LM741 1 2 2 3 3 4 8 7 7 +15 V 15 V 4 6 6out 5 + - Indiana University

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INDIANA UNIVERSITY, DEPT. OF PHYSICS, P400/540 LABORATORY<br />

FALL 2008<br />

Laboratory #6: Operational Amplifiers<br />

Goal: Study the use of the operational amplifier in a number of different<br />

configurations: inverting amplifier, non-inverting amplifier, summing amplifier,<br />

follower, current source, and current to voltage converter (transconductance amplifier)<br />

1. Introduction<br />

This is the first integrated circuit ("IC") that we will be using. The particular<br />

package style is called "DIP" for "dual in-line package." We will be using the <strong>LM741</strong>, the<br />

"original" low-cost operational amplifier. There are now op amps with lower noise, faster<br />

response ("slewing"), etc., but this one illustrates generic op amp behavior.<br />

The chip should "straddle" the trench in the breadboard, making connections to<br />

each pin very easy. The pin numbering scheme for all chips is as shown:<br />

8 7<br />

<strong>LM741</strong><br />

1 2<br />

6<br />

5<br />

3 4<br />

2<br />

3<br />

<strong>+<strong>15</strong></strong> V<br />

7<br />

4<br />

!<strong>15</strong> V<br />

The "dot" always designates pin 1, and the pins are numbered counter-clockwise<br />

looking down on the chip. Note that in the above, not all pins are used ("NC" or "not<br />

connected").<br />

Remember to use a DVM to set the adjustable <strong>+<strong>15</strong></strong> V supply to <strong>+<strong>15</strong></strong> V and ditto<br />

for the –<strong>15</strong> V supply. Connect these to "bus bars" on the breadboard, with the <strong>+<strong>15</strong></strong> V<br />

across the top and the –<strong>15</strong> V across the bottom. Immediately make the power<br />

connections to the IC chip, and before any other connections, use a DVM right at the<br />

pins to make sure that the <strong>+<strong>15</strong></strong> and –<strong>15</strong> Volts are present. This is one of the dominant<br />

reasons for IC circuits not working: lack of proper power!<br />

2. Open-loop gain<br />

Wire up the circuit below. Watch the output voltage with a DVM as you slowly<br />

twiddle the potentiometer, trying to apply zero volts (when the "wiper" is exactly at the<br />

center and you have exactly the midpoint between +/–<strong>15</strong> V).<br />

!<br />

+<br />

6<br />

out


Describe the behavior. Is it consistent with gain claims of "100's of volts/mV'?<br />

3. Inverting Amplifier<br />

10k<br />

in<br />

<strong>+<strong>15</strong></strong> V<br />

!<strong>15</strong> V<br />

1k<br />

2<br />

<strong>+<strong>15</strong></strong> V<br />

3<br />

+<br />

<strong>LM741</strong><br />

7<br />

2<br />

! 4<br />

10k<br />

<strong>LM741</strong><br />

3<br />

+<br />

!<strong>15</strong> V<br />

Construct the inverting amplifier drawn above. Drive the amplifier with a 1 kHz<br />

sine wave. Measure the gain? What is the maximum output swing? How about linearity<br />

(try a triangle wave)? Try sine waves of different frequencies. At some high frequency,<br />

the amplifier fails to work well. Figure out a way to estimate the slew rate, i.e., the fastest<br />

"slope" in V/ms or V/ns to which the amplifier can respond (N.B. if your signal is<br />

Asin(2πft), differentiating this once gives the slope of the signal (in volts per unit time) for<br />

any time, and you should be able to find the maximum slope. Alternatively, try inputting a<br />

square wave and see how the device tries to duplicate the "infinite" input slope.).<br />

Drive the circuit with a sine wave at 1 kHz again. Measure the input impedance of<br />

this amplifier circuit by adding a 1 kΩ resistor in series with the input.<br />

!<br />

6<br />

6<br />

out<br />

out


4. Summing Amplifier<br />

in<br />

10k<br />

<strong>15</strong>k<br />

10k<br />

<strong>+<strong>15</strong></strong> V !<strong>15</strong> V<br />

Adjustable<br />

"DC Offset"<br />

2<br />

10k<br />

<strong>LM741</strong><br />

3<br />

+<br />

Let's get the "operational" of the operational amplifier: adding signals (currents<br />

really): Build the circuit above that allows you to sum a DC level with an input signal. For<br />

the input, choose a small amplitude sine wave. Describe its operation and the range of<br />

DC offsets you were able to achieve.<br />

5. Non-inverting Amplifier<br />

Wire up the non-inverting amplifier below. Measure the voltage gain and compare<br />

it to prediction.<br />

Try to measure the circuit's input impedance, at 1 kHz, by putting a 1 Meg<br />

resistor in series with the input. How is this different from the inverting amplifier?<br />

in<br />

1k<br />

3<br />

2<br />

+<br />

<strong>LM741</strong><br />

!<br />

10k<br />

!<br />

6<br />

6<br />

out<br />

out


6. Follower<br />

in<br />

3 +<br />

2<br />

<strong>LM741</strong><br />

Build the follower shown above. Input a sine wave of some frequency and<br />

examine the output and measure the gain. The ultimate boring circuit! What is it good<br />

for?<br />

Different Op Amp Uses<br />

Because they can accept either voltages or currents as inputs, and produce voltage<br />

or current outputs, we can label amplifiers as one four types:<br />

!<br />

6<br />

out<br />

Input Output Amplifier Name<br />

Voltage Voltage Voltage<br />

Voltage Current Transconductance<br />

Current Voltage Transresistance<br />

Current Current Current<br />

In the next section, you will construct a current source that is controlled by an input<br />

voltage (a "transconductance" amplifier). It is similar to the non-inverting amplifier, with<br />

the input voltage set with a voltage divider.


7. Current Source<br />

<strong>15</strong>k<br />

1k<br />

<strong>+<strong>15</strong></strong> V<br />

180<br />

3<br />

2<br />

+<br />

<strong>LM741</strong><br />

!<br />

A<br />

6<br />

10k "load"<br />

Try out the op-amp current source shown above. What should the current be,<br />

and what do you measure it as? Vary the load potentiometer and watch the current using<br />

the DVM. Determine the range of load resistances over which the current source varies<br />

by less than 10%. This is called its compliance.<br />

This current source, although far more precise and stable than our simple<br />

transistor current source, has the disadvantage of requiring a "floating" load (neither side<br />

connected to ground). It also has significant speed limitations when the output current or<br />

load impedance varies at microsecond speeds.<br />

8. Current to Voltage Converter<br />

Phototransistor<br />

(no collector<br />

connection)<br />

light<br />

2<br />

"<br />

3 +<br />

<strong>LM741</strong><br />

10 M!<br />

6<br />

out<br />

out


(a) Photodiode: Use the supplied phototransistor (feel free to peel back some of<br />

the rubber coating if not enough light is getting into the fiber optic lead) as a photodiode<br />

in the circuit above. To determine the pins, try using the DVM to distinguish them as<br />

learned previously. Examine the output signal (if the DC level is more than 10 V, reduce<br />

the feedback resistor to 1 MΩ).<br />

If you see fuzz on the output (oscillations), put a small capacitor (~100 pF) in<br />

parallel with the feedback resistor.<br />

What is the average DC output level, and what is the percentage "modulation"?<br />

This can be quite large due to the fluorescent lights in the lab... What input photocurrent<br />

does the output level correspond to? Try covering the phototransistor with your hand.<br />

Look at the "summing junction" (the inverting input pin) with the scope, as the output<br />

voltage varies. What should you see?<br />

(b) Phototransistor: Now connect the device as a phototransistor, as shown<br />

below (the base is to be left open, as shown). What is the average input photocurrent<br />

now? What about the percentage modulation? Look again at the summing junction.<br />

light<br />

<strong>+<strong>15</strong></strong> V<br />

Phototransistor<br />

2<br />

<strong>LM741</strong><br />

3<br />

+<br />

100k (or more)<br />

If you are curious and/or interested, try out the "game" on pg. 182 of your<br />

manual!<br />

!<br />

6<br />

out

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