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Theory of the Fireball

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I .<br />

b. Temperature Distribution behind <strong>the</strong> Shock<br />

We wish to calculate <strong>the</strong> temperature distribution behind <strong>the</strong> shock.<br />

We can do this because <strong>the</strong> material which has gone through <strong>the</strong> shock<br />

expands very nearly adiabatically, as long as it is not engulfed by <strong>the</strong><br />

internal, hot iso<strong>the</strong>mal sphere. We are interested in <strong>the</strong> period when<br />

<strong>the</strong> shock temperature goes from about 4000 to a few hundred degrees, i.e.,<br />

until <strong>the</strong> strong cooling wave (Sec. 5) starts. For a 1-megaton explosion,<br />

this corresponds roughly to t = 0.05 to 0.25 second.<br />

At a given time, <strong>the</strong> pressure is nearly constant over most <strong>of</strong> <strong>the</strong><br />

volume inside <strong>the</strong> shock, except for <strong>the</strong> Mediate neighborhood <strong>of</strong> <strong>the</strong><br />

shock; <strong>the</strong> shock pressure is roughly twice this constant, inside pressure.<br />

I1<br />

Conrparing two material elements in <strong>the</strong> inside" region, we may calculate<br />

<strong>the</strong>ir relative temperatures if we knm. t.heir .tqeratures when <strong>the</strong> she-ck .<br />

traversed <strong>the</strong>m, and assume adiabatic. expansion from <strong>the</strong>re on.<br />

A material element which is initially at point r w ill be shocked<br />

when <strong>the</strong> shock radius is r. The shock pressure at this time is*<br />

where<br />

~ -<br />

~<br />

Ps( r) = 20( 7Av - lw3<br />

Y = yield in megatons<br />

r = radius in kilometers<br />

y' P pressure<br />

-1z-z (3.3)<br />

pE energy per unit volume<br />

?Notations for <strong>the</strong>modpamic quantities similar to those <strong>of</strong> Gilmore<br />

(Report IN-1543)<br />

.,<br />

19

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