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Theory of the Fireball

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Inserting (3.33) for JIJ and changing <strong>the</strong> unit <strong>of</strong> p from dynes/cm 2 to<br />

6 2<br />

bars = LO dpes/cm we get<br />

Setting nar p1 = po and C ~ O O S ~ as ~ , in Sec. 5d, Tc 1 = 3.6 and T1 r = 1.08<br />

yields<br />

p1 = 5.0 bars<br />

Thus <strong>the</strong> critical pressure is 5 bars, which was tne reason for <strong>the</strong> choice<br />

<strong>of</strong> this, number at t'ne end <strong>of</strong> Sec. 5d. Tnere it vas shown that 5 bars and<br />

T' = 3.6 leads to Ti = 1.08 so that our numbers are consistent.<br />

C<br />

We had to rely on Brode ' s solution to find Tc for a given p; this<br />

could only be avoided by obtaining an analytic solution for <strong>the</strong> isotneml<br />

sphere which will be discussed in a subsequent paper. Apart from this<br />

our treatment is analytical, making use <strong>of</strong> <strong>the</strong> equation <strong>of</strong> state and <strong>the</strong><br />

absorption characteristics <strong>of</strong> air.

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