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Example 2 :<br />

Exercises:<br />

Solve for x in terms <strong>of</strong> y.<br />

1 + 2xy<br />

y + 1<br />

= 3x<br />

(1 + 2xy)<br />

(y + 1) ×<br />

(y + 1)<br />

= (y + 1)3x (multiplying both sides by (y + 1))<br />

1 + 2xy = 3xy + 3x<br />

Example 3 :<br />

Solve for y in terms <strong>of</strong> x.<br />

1 = xy + 3x<br />

1 = x(y + 3) (factoring to separate the x)<br />

x =<br />

1<br />

y + 3<br />

4 + x<br />

3y2 =<br />

x + 1<br />

2y<br />

6y2 (4 + x)<br />

3y2 = 6y2 (x + 1)<br />

2y<br />

(multiply both sides by 6y2 )<br />

2(4 + x) = 3y(x + 1)<br />

2(4 + x)<br />

(x + 1)<br />

= 3y isolate y<br />

y =<br />

2(4 + x)<br />

3(x + 1)<br />

In the last two steps, we were aiming to make x the subject <strong>of</strong> the equation.<br />

1. Solve for x:<br />

(a) x+8<br />

5<br />

(b) x+1<br />

3<br />

(c) 3(x−2)<br />

(d)<br />

4<br />

4<br />

x+1<br />

− x−2<br />

3<br />

+ x−4<br />

2<br />

= 4<br />

= 5<br />

2(x+1)<br />

− 5<br />

+ 3<br />

x−4<br />

5 2<br />

(e) + x+3 2x+6<br />

= 2<br />

x+1<br />

= 4<br />

1 = 10<br />

Page 22

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