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Being able to factorize expressions involving surds <strong>of</strong>ten makes the expression much<br />

tidier. For this example we can get<br />

6 + √ 2 + √ 8<br />

3( √ 2 + √ 8) = 6 + √ 2(1 + √ 4)<br />

3 √ 2(1 + √ 4)<br />

= 6 + 3√ 2<br />

9 √ 2<br />

= 3(2 + √ 2)<br />

9 √ 2<br />

= 2 + √ 2<br />

3 √ 2<br />

√ √<br />

2( 2 + 1)<br />

=<br />

3 √ 2<br />

√<br />

2 + 1<br />

=<br />

3<br />

which is much tidier than the previous expression. We could have saved time and<br />

effort by simplifying the expression first. We needed to note that 8 has a factor<br />

which is a perfect square so<br />

√ 8 = √ 2 × √ 4 = 2 √ 2<br />

and our initial sum becomes<br />

2<br />

√ 2 + √ 8 + 1<br />

3 =<br />

=<br />

2<br />

√ √ +<br />

2 + 2 2 1<br />

3<br />

2<br />

3 √ 1<br />

+<br />

2 3<br />

√ 2<br />

2<br />

=<br />

3 √ 2 +<br />

3 √ 2<br />

= 2 + √ 2<br />

3 √ 2<br />

√<br />

2 + 1<br />

=<br />

3<br />

Page 36

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