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Applications of Derivatives

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MCV 4U0<br />

Unit 6<br />

Part I: Theory<br />

1. True or false.<br />

<strong>Applications</strong> <strong>of</strong> Derivative Practice Test<br />

Date:<br />

(a) . If f ′ (c) = 0, then f must have either a relative minimum or a<br />

relative maximum at c.<br />

(b) . Since function f(x) = − 1<br />

is increasing on the intervals (−∞, 0)<br />

and (0, ∞), it is impossible to find x1 and x2 in the domain <strong>of</strong> f such that x1 > x2 and<br />

f(x1) > f(x2).<br />

(c) . On the interval (−1, 1], the function f(x) = x 4 has an absolute<br />

maximum and an absolute minimum.<br />

2. Fill in the blank.<br />

(a) cos 2 θ+ = 1<br />

(b) 1+ = sec 2 θ<br />

(c) If y = sin x, then y ′ = .<br />

(d) If r = cos θ, then dr<br />

=<br />

dθ<br />

.<br />

(e) For y = x 9 − 7x 3 + 2, d2 y<br />

= .<br />

dx2 (f) Extreme Values: If a function f(x) has a derivative at every point in the interval a ≤<br />

x ≤ b, calculuate f(x) at<br />

• all points in the interval a ≤ x ≤ b, where f ′ (x) =<br />

• the x = a and x = b<br />

The value <strong>of</strong> f(x) on the interval a ≤ x ≤ b is the largest <strong>of</strong> these<br />

values, and the value <strong>of</strong> f(x) on the interval is the smallest <strong>of</strong><br />

these values.<br />

(g) If the position <strong>of</strong> an object, s(t), is a function <strong>of</strong> time, t, then the first derivative <strong>of</strong><br />

this function represents the <strong>of</strong> the object at time t. i.e., s ′ (t) =<br />

.<br />

(h) is the second derivative <strong>of</strong> the position function.<br />

(i) a(t) < 0 indicates that the velocity is .<br />

(j) a(t) = 0 indicates that the velocity is .<br />

3. Multiple Choice.<br />

(a) If f(x) = sec x + csc x, then f ′ (x) =<br />

(a) sec 2 x + csc 2 x (b) csc x − sec x (c) sec x tan x − csc x cot x<br />

(b) If f(x) = cos 2 x, then f ′′ (π) =<br />

(a) −2 (b) 0 (c) 1 (d) 2π<br />

(c) A particle’s position is given by s(t) = t 3 − 6t 2 + 9t. What is its acceleration at time<br />

t = 4? (a) 0 (b) 9 (c) −9 (d) 12<br />

1<br />

x


MCV 4U0<br />

Unit 6<br />

<strong>Applications</strong> <strong>of</strong> Derivative Practice Test<br />

Date:<br />

(d) The maximum velocity attained on the interval 0 ≤ t ≤ 5 by the particle whose displacement<br />

is given by s(t) = 2t 3 − 12t 2 + 16t + 2 is<br />

(a) 286 (b) 46 (c) 16 (d) 0<br />

(e) If f(x) = sec(4x), then f ′ <br />

π<br />

16 is<br />

(a) 4 √ 2 (b) √ 2 (c) 0 (d) 1<br />

√ 2<br />

(f) Using the graph below, on the interval [a, b] absolute minimum value is at<br />

(a) point G (b) point H (c) point I (d) point J (e) point K<br />

y<br />

G<br />

a<br />

H<br />

I<br />

J<br />

K c<br />

(g) Using the graph from (3f), on the interval [a, b], the absolute maximum value is at<br />

(a) point G (b) point H (c) point I (d) point J (e) point K<br />

(h) Using the graph from (3f), on the interval [a, c], the absolute minimum is at<br />

(a) point G (b) point H (c) point I (d) point J (e) point K<br />

4. The critical numbers for f(x) = 3√ x − 1 are found at<br />

(a) x = −1 (b) x = 0 (c) x = 1 (d) x = {−1, 0, 1}<br />

Part II: Application<br />

1. The position <strong>of</strong> a spring is described by the function s(t) = 3 cos(2x).<br />

(a) The velocity function is v(t) = .<br />

(b) The acceleration function is a(t) = .<br />

2. Given f(x) = −2x 3 + 9x 2 + 4, find the extreme values <strong>of</strong> f(x) on [−1, 5].<br />

2<br />

b<br />

x


MCV 4U0<br />

Unit 6<br />

<strong>Applications</strong> <strong>of</strong> Derivative Practice Test<br />

Date:<br />

3. The position function <strong>of</strong> a particle is given by<br />

s(t) = √ t(3t 2 − 35t + 90)<br />

where s is measured in metres and t is in seconds.<br />

(a) Find the velocity and acceleration as a function <strong>of</strong> time.<br />

(b) Find the velocity <strong>of</strong> the particle at t = 3.<br />

(c) When is the particle at rest?<br />

(d) When is the particle moving in a positive direction.<br />

4. Mrs McCombs grows tomatoes along the side <strong>of</strong> her house. The squirrels are getting at them,<br />

and she’s decided to put a fence around the tomatoes to save them. If she has 40 m <strong>of</strong> fencing<br />

available to lay out using the straight side <strong>of</strong> her house as one line <strong>of</strong> the rectangle, what<br />

dimensions will maximize the garden area?<br />

3


MCV 4U0<br />

Unit 6<br />

<strong>Applications</strong> <strong>of</strong> Derivative Practice Test<br />

Date:<br />

5. Rick’s American Cafe sells cheeseburgers with a yearly demand function <strong>of</strong><br />

and cost function<br />

(a) State the revenue function.<br />

p =<br />

(b) Find the marginal revenue function.<br />

800000 − x<br />

200000<br />

C(x) = 125000 + 0.42x<br />

(c) What level <strong>of</strong> cheeseburger sales will maximize pr<strong>of</strong>its?<br />

6. A piece <strong>of</strong> sheet metal, 60 cm by 30 cm, is to be used to make a rectangular box with an<br />

open top. Determine the dimensions that will give the box with the largest volume.<br />

4


MCV 4U0<br />

Unit 6<br />

<strong>Applications</strong> <strong>of</strong> Derivative Practice Test<br />

Date:<br />

7. Ian and Ada are both training for a marathon. Ian’s house is located 20 km north <strong>of</strong> Ada’s<br />

house. At 9:00 am one Saturday, Ian laves his house and jogs south at 8 km/h. At the same<br />

time, Ada leaves her house and jogs east at 6 km/h. When are Ian and Ada closest together,<br />

given that they both run for 2.5 h?<br />

20<br />

J<br />

I<br />

A<br />

8. Determine the dy<br />

dx<br />

(a) y = tan x<br />

(b) y =<br />

s<br />

sin x<br />

1 + cos x<br />

B<br />

for each <strong>of</strong> the following<br />

5


MCV 4U0<br />

Unit 6<br />

(c) r = tan 3 (4θ + π)<br />

(d) y = 6 cos( √ x)<br />

<strong>Applications</strong> <strong>of</strong> Derivative Practice Test<br />

Date:<br />

9. The position <strong>of</strong> a particle as it moves horizontally is described by the function<br />

s(t) = sin 2 t − 2 cos 2 t<br />

where t ∈ [−π, π]. If s is the displacement in metres and t is the time in seconds, find the<br />

absolute maximum and minimum displacements.<br />

10. Find an equation <strong>of</strong> the tangent line to the curve y = cos2 x<br />

sin 2 x at π<br />

4 , 1 .<br />

6

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