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ASSIGNMENT 2–MATH 2100 Due Monday, September 27 at 10:35 ...

ASSIGNMENT 2–MATH 2100 Due Monday, September 27 at 10:35 ...

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<strong>ASSIGNMENT</strong> <strong>2–MATH</strong> <strong>2<strong>10</strong>0</strong><br />

<strong>Due</strong> <strong>Monday</strong>, <strong>September</strong> <strong>27</strong> <strong>at</strong> <strong>10</strong>:<strong>35</strong> in tutorial.<br />

Suppose V and W are vector spaces over a field F .<br />

1. Suppose ϕ : V → W is an isomorphism. Recall th<strong>at</strong> the inverse func- /<strong>10</strong><br />

tion ϕ −1 : W → V is defined in the following way. For any w ∈ W there<br />

exists some v ∈ V such th<strong>at</strong> ϕ(v) = w (surjectivity of ϕ). Moreover,<br />

this v is unique (injectivity of ϕ). Therefore it makes sense to define<br />

ϕ −1 (w) = v. This has the consequences th<strong>at</strong><br />

and<br />

ϕ(ϕ −1 (w)) = ϕ(v) = w<br />

ϕ −1 (ϕ(v)) = ϕ −1 (w) = v.<br />

Prove th<strong>at</strong> ϕ −1 : W → V is an isomorphism, by verifying th<strong>at</strong> it is<br />

linear and bijective.<br />

2. Suppose x, y, z ∈ V s<strong>at</strong>isfy x + y + z = 0. Prove th<strong>at</strong> span{x, y} =<br />

span{y, z}. /<strong>10</strong><br />

3. Recall th<strong>at</strong> F [x] is the vector space (over F ) of polynomials with coefficients<br />

in x, i.e.<br />

F [x] = {a0 + a1x + · · · + anx n : a0, . . . an ∈ F, n ≥ 0}.<br />

Fix a positive integer m. For this exercise you may use without proof<br />

th<strong>at</strong> the subset W ⊂ F [x] of all polynomials of degree m or less is a<br />

subspace of F [x] and th<strong>at</strong> this subspace has two ordered bases<br />

and<br />

B = {1, x, x 2 , . . . , x m }<br />

B ′ = {1, x, x 2 , . . . , x m−1 , x m−1 + x m }.<br />

(a) Determine the basechange m<strong>at</strong>rix P ∈ F m+1×m+1 such th<strong>at</strong> B ′ =<br />

BP and compute the determinant of P . (Hint: Determine P by<br />

specifying its m<strong>at</strong>rix entries pij ∈ F . Show your work!)<br />

/<strong>10</strong>


(b) Suppose here th<strong>at</strong> F = R and {f1, . . . , fm+1} ⊂ W such th<strong>at</strong> /<strong>10</strong><br />

fj(1) = 0<br />

for all 1 ≤ j ≤ m + 1. Prove th<strong>at</strong> {f1, . . . , fm+1} is linearly<br />

dependent. (Hint: Wh<strong>at</strong> is the dimension of W ?)<br />

SUGGESTED EXERCISES<br />

Chapter Exercises<br />

3 3.1, 3.4, 3.5, 3.8., 4.1-4.3

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