8-3 Solving Right Triangles 8-3 Solving Right Triangles
8-3 Solving Right Triangles 8-3 Solving Right Triangles
8-3 Solving Right Triangles 8-3 Solving Right Triangles
Create successful ePaper yourself
Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.
8-3 <strong>Solving</strong> <strong>Right</strong> <strong>Triangles</strong><br />
8-3 <strong>Solving</strong> <strong>Right</strong> <strong>Triangles</strong><br />
Warm Up<br />
Lesson Presentation<br />
Lesson Quiz<br />
Holt McDougal Geometry<br />
Geometry
8-3 <strong>Solving</strong> <strong>Right</strong> <strong>Triangles</strong><br />
Objective<br />
Use trigonometric ratios to find angle<br />
measures in right triangles and to solve<br />
real-world problems.<br />
Holt McDougal Geometry
8-3 <strong>Solving</strong> <strong>Right</strong> <strong>Triangles</strong><br />
Check It Out! Example 1a<br />
Use the given trigonometric<br />
ratio to determine which<br />
angle of the triangle is A.<br />
Holt McDougal Geometry
8-3 <strong>Solving</strong> <strong>Right</strong> <strong>Triangles</strong><br />
Finding Angles<br />
1. From the angle you wish to find, which of<br />
the three sides are you given: opposite,<br />
adjacent, or hypotenuse?<br />
22 cm<br />
15 cm<br />
x<br />
Holt McDougal Geometry
8-3 <strong>Solving</strong> <strong>Right</strong> <strong>Triangles</strong><br />
Finding Angles<br />
2. Given those two sides, use SOH-CAH-TOA<br />
to decide which trig ratio to use: sin, cos,<br />
or tan.<br />
22 cm<br />
15 cm<br />
x<br />
Holt McDougal Geometry
8-3 <strong>Solving</strong> <strong>Right</strong> <strong>Triangles</strong><br />
Finding Angles<br />
3. Set up an equation using the correct trig<br />
ratio and the correct order of sides.<br />
– NOTE: x is now on the other side with<br />
sin, cos, or tan.<br />
22 cm<br />
15 cm<br />
x<br />
Holt McDougal Geometry
8-3 <strong>Solving</strong> <strong>Right</strong> <strong>Triangles</strong><br />
Finding Angles<br />
4. This is the most crucial step. You cannot<br />
cross-multiply, because that will not<br />
separate cos from x. Instead you must use<br />
what is called the inverse trig function.<br />
– The symbol for this is sin -1 , cos -1 , or<br />
tan -1 .<br />
Holt McDougal Geometry
8-3 <strong>Solving</strong> <strong>Right</strong> <strong>Triangles</strong><br />
Finding Angles<br />
• So, use the cos -1 on both sides of the<br />
equation. On the right hand side, cos -1 and<br />
cos cancel, leaving you just x.<br />
• On the left hand side, we must use our<br />
calculators.<br />
Holt McDougal Geometry
8-3 <strong>Solving</strong> <strong>Right</strong> <strong>Triangles</strong><br />
Finding Angles-Calculator<br />
• Most of you will type it exactly as it is read:<br />
2nd -> cos -> 15 / 22 ) -> Enter<br />
• Others will have to work backwards:<br />
15 / 22 -> Enter -> 2nd -> cos<br />
Holt McDougal Geometry
8-3 <strong>Solving</strong> <strong>Right</strong> <strong>Triangles</strong><br />
1.<br />
25 cm<br />
5 cm<br />
90<br />
x<br />
Find the value of x<br />
Holt McDougal Geometry
8-3 <strong>Solving</strong> <strong>Right</strong> <strong>Triangles</strong><br />
2.<br />
Find the value of x<br />
90<br />
17 cm<br />
x<br />
25 cm<br />
Holt McDougal Geometry
8-3 <strong>Solving</strong> <strong>Right</strong> <strong>Triangles</strong><br />
Find the value of x and y<br />
3.<br />
y<br />
35 in<br />
x<br />
90<br />
22 in<br />
Holt McDougal Geometry
8-3 <strong>Solving</strong> <strong>Right</strong> <strong>Triangles</strong><br />
4.<br />
Find the value of x, y and z<br />
x<br />
5.8 cm<br />
y<br />
z 90<br />
3.2 cm<br />
Holt McDougal Geometry
8-3 <strong>Solving</strong> <strong>Right</strong> <strong>Triangles</strong><br />
Example 2: Calculating Angle Measures from<br />
Trigonometric Ratios<br />
Use your calculator to find each angle measure<br />
to the nearest degree.<br />
A. cos -1 (0.87) B. sin -1 (0.85) C. tan -1 (0.71)<br />
cos -1 (0.87) 30° sin -1 (0.85) 58° tan -1 (0.71) 35°<br />
Holt McDougal Geometry