25.12.2013 Views

ABSTRACT - DRUM - University of Maryland

ABSTRACT - DRUM - University of Maryland

ABSTRACT - DRUM - University of Maryland

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

onding basis. Hamiltonian in the bonding sector is just a theory <strong>of</strong> free bosons. In<br />

the anti-bonding sector, it reads<br />

Ĥ= v 2<br />

[K(∂ x θ) 2 + 1 K (∂ xϕ) 2 ]<br />

+ 2t ⊥<br />

πa 0<br />

cos √ 2πϕ cos √ 2πθ. (7.20)<br />

The bosonic fields ϕ and θ are in the anti-bonding basis. The perturbation (t ⊥ )<br />

term has nonzero conformal spin which implies that two-particle processes are automatically<br />

generated by RG flow even when they are absent in the bare Hamiltonian.<br />

Therefore, one has to include two-particle perturbations in the RG flow<br />

Ĥ 2 = g 1<br />

(πa 0 ) 2 cos √ 8πϕ + g 2<br />

(πa 0 ) 2 cos √ 8πθ. (7.21)<br />

The RG flow equations for weak couplings have been derived by Yakovenko [169]<br />

and Nersesyan et al. [170]. Here we cite their results [159]:<br />

dz<br />

(<br />

dl = 2 − K + )<br />

K−1<br />

z<br />

2<br />

dy 1<br />

= (2 − 2K)y 1 + (K − K −1 )z 2<br />

dl<br />

, (7.22)<br />

dy 2<br />

= (2 − 2K −1 )y 2 + (K −1 − K)z 2<br />

dl<br />

dK<br />

= 1 dl 2 (y2 2 − y1K 2 2 )<br />

where the dimensionless couplings are defined as z = t ⊥a<br />

2πv and y 1,2 = g 1,2<br />

πv .<br />

Since we are interested in the phase where the pair tunneling dominates at low<br />

energy, we assume K > 1 so y 1 is irrelevant and can be put to 0. Also we neglect<br />

renormalization <strong>of</strong> K.<br />

Integrating the RG flow equations with initial conditions<br />

z(0) = z 0 ≪ 1, y 2 (0) = 0 we obtain<br />

y 2 (l) = z 2 0<br />

K −1 − K [<br />

e 2(1−α)l − e ] 2(1−K−1 )l , (7.23)<br />

2α<br />

140

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!