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<strong>EMBEDDING</strong> <strong>OPERATORS</strong> <strong>INTO</strong> C 0 -SEMIGROUPS 4<br />

Question 3.4. For which (classes of) operators the necessary condition given in Theorem 3.1<br />

is also sufficient for embeddability?<br />

Note that the condition given in Theorem 3.1 is not sufficient for embeddability in general. For<br />

example, Halmos, Lumer an Schäffer [14] constructed a class of invertible operators on Hilbert<br />

spaces which have no square root. Later, Deckard and Pearcy [4] showed that such operators<br />

exist on every infinite-dimensional Hilbert space.<br />

4. Embedding isometries on Hilbert spaces<br />

In this section we characterise the embedding property for isometries, co-isometries and projections<br />

on Hilbert spaces. Note that the spectrum of a non-invertible isometry is the unit disc<br />

(see Conway [3, Exercise VII.6.7] for the Banach space case or Theorem 4.2 below for isometries<br />

on Hilbert spaces), and hence the spectral calculus method is not applicable.<br />

We first recall that unitary operators are embeddable.<br />

Proposition 4.1. Every unitary operator U on a Hilbert space H can be embedded into a unitary<br />

C 0 -group with bounded generator.<br />

Proof. By the spectral theorem, see e.g. Halmos [13], we can assume that U has a cyclic vector,<br />

H = L 2 (Γ, µ) for the unit circle Γ and some Borel measure µ and<br />

Define now<br />

(Uf)(z) = zf(z), z ∈ Γ, f ∈ L 2 (Γ, µ).<br />

(U(t)f)(e iϕ ) := e itϕ f(e iϕ ), f ∈ L 2 (Γ, µ),<br />

for ϕ ∈ [0, 2π) and t ∈ R. The operators U(t) form a unitary C 0 -group which is even uniformly<br />

continuous and satisfies U(1) = U.<br />

□<br />

To treat the general case we need the following structure theorem for isometries on Hilbert<br />

spaces.<br />

Theorem 4.2. (Wold decomposition, see Sz.-Nagy, Foiaş [20, Theorem 1.1].) Let V be an<br />

isometry on a Hilbert space H. Then H can be decomposed into an orthogonal sum H = H 0 ⊕H 1<br />

of V -invariant subspaces such that the restriction of V on H 0 is unitary and the restriction of<br />

V on H 1 is a unilateral shift. More precisely, for Y := (rg V ) ⊥ ⊂ H 1 one has V n Y ⊥ V m Y for<br />

all n ≠ m ∈ N 0 and H 1 = ⊕ ∞<br />

n=0 V n Y .<br />

So, by Wold’s decomposition and Proposition 4.1, the problem of embedding an isometry<br />

reduces to embedding the right shift on the space l 2 (N, Y ) for some Hilbert space Y . The<br />

following result shows when this can be achieved.<br />

Proposition 4.3. Let T be the right shift on l 2 (N, Y ) for an infinite-dimensional Hilbert space<br />

Y . Then T can be embedded into an isometric C 0 -semigroup.<br />

Proof. Let T be the right shift on l 2 (N, Y ), i.e.,<br />

T(x 1 , x 2 , x 3 , . . .) := (0, x 1 , x 2 , . . .).<br />

By general Hilbert space theory, Y is unitarily isomorphic to the space L 2 ([0, 1], Y ), hence there<br />

is a unitary operator J : l 2 (N, Y ) → l 2 (N, L 2 ([0, 1], Y )) such that JTJ −1 is again the right shift

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