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<strong>EMBEDDING</strong> <strong>OPERATORS</strong> <strong>INTO</strong> C 0 -SEMIGROUPS 6<br />

Proof. If 0 < dim(kerP) < ∞, P is not embeddable by Theorem 3.1. The rest follows from the<br />

decomposition H = ker P ⊕ rg P into two invariant subspaces, Lemma 4.6 and embeddability of<br />

the identity operator (on any Banach space) into the identity semigroup.<br />

□<br />

We finish this section with the following natural question.<br />

Open Problem 4.8. Does the necessary condition given in Theorem 3.1 suffice to embed partial<br />

isometries on Hilbert spaces?<br />

Note that for a partial isometry T the condition is sufficient in each of the following cases:<br />

(a) T is injective, i.e., T is an isometry (Theorem 4.4);<br />

(b) T is surjective, i.e., T ∗ is an isometry (Corollary 4.5);<br />

(c) ker T reduces T.<br />

The argument in (c) is similar to the proof of Proposition 4.7 using Theorem 4.4.<br />

5. More examples, a category result<br />

In this section we give more examples of embeddable operators.<br />

The following result extends the argument from (the proof of) Proposition 4.1 to normal<br />

operators.<br />

Proposition 5.1. Let T be a normal operator on a Hilbert space. Then T is embeddable if and<br />

only if T is injective or dim kerT = ∞.<br />

Proof. By the spectral theorem, see e.g. Halmos [13], we may assume that T is a multiplication<br />

operator on H = L 2 (Ω, µ) for Ω = σ(T) and some Borel measure µ, say Tf = mf with<br />

m ∈ L ∞ (Ω, µ). Note that the essential image of m equals σ(T).<br />

Assume first that T is injective, whence µ(m −1 (0)) = 0. Using the principal value of the<br />

logarithm on C \ {0}, which is measurable, define (T(t)) t≥0 by<br />

T(t)f := e t log m f, f ∈ L 2 (Ω, µ), t ≥ 0.<br />

Each T(t) is a bounded operator on L 2 (Ω, µ). Moreover, the family (T(t)) t≥0 is strongly continuous<br />

by Lebesgue’s dominated convergence theorem. The semigroup law and the property<br />

T(1) = T are clear, so T is embeddable.<br />

Assume now dim ker T = ∞. Since T is normal, we have rg T ∗ = (kerT) ⊥ = (kerT ∗ ) ⊥ = rg T.<br />

Therefore ker T and rg T reduce T and H = kerT ⊕ rg T. The restriction T | ker T is embeddable<br />

by Lemma 4.6. On the other hand, T | rg T<br />

is an injective normal operator and hence embeddable<br />

by the first part of the proof. This shows that T is embeddable as well.<br />

The remaining case is answered in the negative by Theorem 3.1.<br />

□<br />

Remark 5.2. The above proof shows that T can be embedded into a normal C 0 -semigroup<br />

whenever T is injective. Moreover, if T is invertible, then 0 has positive distance to σ(T) and T<br />

can be embedded into a normal C 0 -group with bounded generator employing the same definition<br />

for t ∈ R (cf. Proposition 4.1).<br />

Remark 5.3. Clearly, also each operator T similar to a normal operator is embeddable if and<br />

only if T is injective or dim kerT = ∞. For example, Sz.-Nagy [19] showed that a bijective<br />

operator T on a Hilbert space satisfying sup j∈Z ‖T j ‖ < ∞ is similar to a unitary operator and<br />

hence embeddable into a C 0 -group by Proposition 4.1. We refer also to van Casteren [2] for

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