EEET 201: ELECTRONIC CIRCUITS
EEET 201: ELECTRONIC CIRCUITS
EEET 201: ELECTRONIC CIRCUITS
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PHYS 162: Solid State Devices<br />
(Chapter 1) Introduction to Semiconductors<br />
HW 1 QUESTIONS<br />
DUE DATE: SATURDAY, 1 OCTOBER <strong>201</strong>1<br />
Conduction in Semiconductors<br />
1.1 What happens when heat is added to silicon?<br />
1.2 Name the two energy bands where current is produced in silicon.<br />
N-Type and P-Type Semiconductors<br />
1.3 Describe the process of doping and explain how it alters the atomic structure if<br />
silicon.<br />
The Diode<br />
1.4 How is the electric field in the pn junction created?<br />
1.5 Because of its barrier, can a diode be used as a voltage source? Explain.<br />
Biasing a Diode<br />
1.6 Explain why a series resistance is necessary when a diode is forward biased.<br />
Diode Models<br />
1.7 Determine whether each diode in Figure 1.1 is forward-biased or reversed-biased.<br />
1.8 Determine the voltage across each diode in Figure 1.1, assuming the practical model.<br />
1.9 Determine the voltage across each diode in Figure 1.1, assuming the ideal model.<br />
1.10 Determine the voltage across each diode in Figure 1.1, using the complete diode<br />
model with r’ d = 7Ω and r’ R = 100MΩ.<br />
Figure 1.1<br />
1
SOLUTION<br />
Conduction in Semiconductors<br />
1.1<br />
1.2<br />
N-Type and P-Type Semiconductors<br />
1.3<br />
The Diode<br />
1.4<br />
1.5<br />
Biasing a Diode<br />
1.6<br />
Diode Models<br />
1.7<br />
1.8<br />
1.9<br />
1.10<br />
Ignoring r′ R<br />
(a) V R ≈ 5V − 8V = −3V<br />
(b)<br />
100V − 0.7V<br />
I F =<br />
560Ω + 7Ω = 175.1mA<br />
2
(c)<br />
(d)<br />
V F = I F r ′ d + V B = 175.1mA 7Ω + 0.7V = 1.9V<br />
I tot = 30V<br />
R tot<br />
R tot = 1KΩ + 1.5KΩ + 4.7KΩ = 2.5KΩ + 2.35KΩ = 4.85KΩ<br />
2<br />
I tot =<br />
30V<br />
4.85KΩ = 6.19mA<br />
I F = 6.19mA = 3.1mA<br />
2<br />
V F = I F r ′ d + V B = 3.1mA 7Ω + 0.7V = 0.722V<br />
I F =<br />
20V − 0.7V<br />
10KΩ + 7Ω = 1.93mA<br />
V F = I F r ′ d + V B = 1.93mA 7Ω + 0.7V = 0.71V<br />
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