Schwarz-Christoffel Formula for Multiply Connected Domains
Schwarz-Christoffel Formula for Multiply Connected Domains
Schwarz-Christoffel Formula for Multiply Connected Domains
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454 V. Mityushev CMFT<br />
Introduce the function<br />
(15) Φ(z) =<br />
where<br />
(16) Φ k (z) = 1 2<br />
n∑<br />
Φ k (z),<br />
k=1<br />
∑M k<br />
l=1<br />
β lk<br />
z − z lk<br />
.<br />
Then ψ(z) ∈ C A (D, 2Φ) and ψ k (z) ∈ C A (D k , Φ k ). The problems (2) and (13) in<br />
the classes considered are equivalent in the sense of the following result.<br />
Lemma 1.<br />
(i) If ψ(z) and ψ k (z) are solutions of (13) in the class considered, then ψ(z)<br />
satisfies (2).<br />
(ii) If ψ(z) is a solution of (2), there exist functions ψ k ∈ C A (D k , Φ k ) and real<br />
constants ξ k such that the R-linear conditions (13) are fulfilled.<br />
Proof. The proof of the first assertion is evident. It is sufficient to take the real<br />
part of (13).<br />
Conversely, let ψ(z) satisfy (2). The function<br />
Ψ k (z) = iξ k<br />
2 + (z − a k)ψ k (z)<br />
can be uniquely determined from the simple <strong>Schwarz</strong> problem <strong>for</strong> the disk D k<br />
[10, 16]<br />
(17) 2 Im Ψ k (t) = Im(t − a k )ψ(t), |t − a k | = r k .<br />
It is assumed that the function Ψ k (z) is continuous in |z − a k | ≤ r k except at<br />
the points z lk , where the principal part β lk (z lk − a k )/[2(z − z lk )] of Ψ k (z) is<br />
determined by the right hand part of (17). The problem (17) <strong>for</strong> the function<br />
Ψ k (z) has a unique solution, since Re Ψ k (a k ) = 0. There<strong>for</strong>e, the function<br />
ψ k (z) and the constant ξ k are uniquely determined in terms of ψ(z) <strong>for</strong> each<br />
k = 1, . . . , n. Direct calculations yields the asymptotic (14).<br />
Hence the lemma is proved.<br />
We now proceed to solve the R-linear problem (13) written in the <strong>for</strong>m<br />
( ) 2 rk<br />
(18) ψ(t) = ψ k (t) − ψ k (t) − 1 − iξ k<br />
, |t − a k | = r k , k = 1, . . . , n.<br />
t − a k t − a k