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Alternating Current in RC Circuits

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Physics 241 Lab – Matt Leone<br />

Week 8: <strong>Alternat<strong>in</strong>g</strong> <strong>Current</strong> <strong>in</strong> <strong>RC</strong> <strong>Circuits</strong><br />

Leone@physics.arizona.edu (email preferred), PAS 376, o. 520-621-6819<br />

Office Hours: M & W 11:00-11:50, or by appo<strong>in</strong>tment. Consultation Room (PAS 372): F 12:00-12:50<br />

http://bohr.physics.arizona.edu/~leone/phy241/phys241lab.html<br />

General Comments:<br />

• Today we study ALTERNATING CURRENT charg<strong>in</strong>g and discharg<strong>in</strong>g of capacitors.<br />

• You will practice us<strong>in</strong>g your oscilloscope <strong>in</strong> a test-like environment.<br />

Lab 8 – Summary:<br />

There are three key concepts you should know about an <strong>RC</strong> circuit driven with a s<strong>in</strong>e source.<br />

1. The capacitor voltage lags beh<strong>in</strong>d the resistor voltage by 90 o (phase shift).<br />

2. The capacitor is described by a capacitive reactance X C that acts like a resistance.<br />

3. A s<strong>in</strong>usoidally driven circuit is described by an overall IMPEDANCE, Z that acts<br />

like the total resistance of the whole circuit.<br />

Lab 8 – Matt’s discussion on board: now on the paper!<br />

We now study the <strong>RC</strong> circuit driven by a s<strong>in</strong>usoidal alternat<strong>in</strong>g voltage source:<br />

For an advanced course, you could write a differential equation for this circuit and solve it to<br />

study its behavior mathematically. We will only discuss how to use the solution <strong>in</strong> this lab.<br />

Each component of the above circuit has a s<strong>in</strong>usoidally vary<strong>in</strong>g voltage across it, though each<br />

peaks at a different time. The voltage of each is given by the equations:<br />

• V source<br />

(t) = V MAX<br />

s<strong>in</strong>("t + #)<br />

"<br />

• V R<br />

(t) = R %<br />

$ ' V<br />

# Z &<br />

MAX<br />

s<strong>in</strong>((t)<br />

!<br />

#<br />

• V C<br />

(t) = " &<br />

C<br />

%<br />

$ Z '<br />

( V s<strong>in</strong> #<br />

)t * + &<br />

%<br />

MAX $ 2 (<br />

'<br />

where ! there are several new parameters to discuss. Let’s discuss each equation <strong>in</strong> detail. Incidentally,<br />

the current is also oscillat<strong>in</strong>g with the same frequency. The oscillat<strong>in</strong>g current <strong>in</strong> the resistor is often<br />

used as a start<strong>in</strong>g po<strong>in</strong>t to teach $ this material (but not here because I th<strong>in</strong>k it confuses the big idea).<br />

!<br />

%<br />

Also, <strong>in</strong> case you’re curious " = arctan # L<br />

$ # C<br />

(<br />

' *.<br />

& R )<br />

!<br />

1


!<br />

V source<br />

(t) = V MAX<br />

s<strong>in</strong>("t + #)<br />

The source voltage equation is straightforward. It oscillates s<strong>in</strong>usoidally, i.e. it is a s<strong>in</strong>e<br />

function of time. It determ<strong>in</strong>es the maximum voltage across the whole circuit with V MAX . It oscillates<br />

with an angular frequency " = 2#f .<br />

Notice that it also has a phase shift φ. Now why on earth would we describe the source voltage<br />

with a phase shift? If you look below at the resistor equation, you will see no phase shift. What this<br />

means is that we measure all phases <strong>in</strong> relation to the resistor not the source. The resistor will have<br />

its maximum voltage<br />

!<br />

at a different time than when the source voltage is maximum.<br />

!<br />

"<br />

V R<br />

(t) = R %<br />

$ ' V<br />

# Z &<br />

MAX<br />

s<strong>in</strong>((t)<br />

The resistor voltage equation <strong>in</strong>cludes some new stuff. It also oscillates s<strong>in</strong>usoidally and<br />

without a phase shift. R is the resistance.<br />

What is new is Z. Z is the impedance of the whole circuit. It is given by the equation<br />

( ) 2 .<br />

Z = R 2 + " L<br />

# " C<br />

Uh oh, this def<strong>in</strong>ition has new stuff, too. Now X L and X C are like the resistances of the <strong>in</strong>ductor and<br />

capacitor <strong>in</strong> the circuit. S<strong>in</strong>ce we don’t have an <strong>in</strong>ductor (coil) <strong>in</strong> the circuit, you can set this to zero.<br />

So we have Z = R 2 + " 2 C<br />

.<br />

!<br />

Now what if I rewrote the resistor equation as V R<br />

(t) = V R,MAX<br />

s<strong>in</strong>("t). What maximum and<br />

m<strong>in</strong>imum voltage would oscillate across the resistor? V R,MAX<br />

= R<br />

!<br />

Z V MAX<br />

. That means that the ratio of<br />

the resistor resistance and the total circuit resistance (impedance) times the source amplitude gives you<br />

the amplitude of the voltage just across the resistor.<br />

!<br />

!<br />

#<br />

V C<br />

(t) = " &<br />

C<br />

%<br />

$ Z '<br />

( V s<strong>in</strong> #<br />

)t * + &<br />

%<br />

MAX $ 2 (<br />

'<br />

!<br />

The capacitor voltage oscillates s<strong>in</strong>usoidally and lags the voltage across the resistor by 90 o .<br />

$<br />

Knowledge of trigonometry allows you to also write V C<br />

(t) = " # '<br />

C<br />

& ) V<br />

% Z (<br />

MAX<br />

cos (*t) s<strong>in</strong>ce s<strong>in</strong>e shifted left<br />

by 90 o is the negative cos<strong>in</strong>e. This is sometimes useful for graph<strong>in</strong>g.<br />

The reactive capacitance is like the resistance of the capacitor. More precisely, " C<br />

= 1<br />

#C .<br />

!<br />

Yikes! The “resistance” of the capacitor is related to the capacitance of the capacitor. The larger the<br />

capacitance, the less “resistance” <strong>in</strong> the capacitor. But just as importantly X C is also related to the<br />

frequency of the driv<strong>in</strong>g voltage. If the frequency is <strong>in</strong>creased, the “resistance” of the capacitor<br />

decreases. This is why a capacitor is often used as a high pass filter. The capacitor ! has less resistance<br />

to more quickly oscillat<strong>in</strong>g currents. BE SURE TO REMEMBER THIS DURING TODAY’S LAB!<br />

%<br />

Now what if I rewrote the capacitor equation as V C<br />

(t) = V C,MAX<br />

s<strong>in</strong> "t # $ (<br />

' *. What maximum<br />

& 2 )<br />

and m<strong>in</strong>imum voltage would oscillate across the capacitor? V C,MAX<br />

= " C<br />

Z V MAX<br />

. That means that the<br />

ratio of the capacitive reactance and the total circuit resistance (impedance) times the source amplitude<br />

gives you the amplitude of the voltage just across<br />

!<br />

the capacitor.<br />

!<br />

2


Lab 8 – Predictions – rem<strong>in</strong>der: your solutions on these pages are always worth po<strong>in</strong>ts.<br />

!<br />

Lets work though an example before we beg<strong>in</strong>. Remember the equations,<br />

V source<br />

(t) = V MAX<br />

s<strong>in</strong>("t + #)<br />

"<br />

V R<br />

(t) = R %<br />

#<br />

$ ' V<br />

# Z &<br />

MAX<br />

s<strong>in</strong>((t) V C<br />

(t) = " &<br />

C<br />

%<br />

$ Z '<br />

#<br />

)t * + &<br />

%<br />

MAX $ 2 (<br />

'<br />

If your circuit has V MAX<br />

= 2 Volts, R =10,000 " , C =1x10 -7 Farads, and " =1,500 radians/sec f<strong>in</strong>d<br />

the follow<strong>in</strong>g values with correct units<br />

1. X C .<br />

!<br />

!<br />

!<br />

!<br />

!<br />

!<br />

2. Z<br />

3. V R,MAX .<br />

4. V C,MAX .<br />

5. Now exam<strong>in</strong>e V R,MAX + V C,MAX .<br />

They add to more than V MAX !!! No, you didn’t make a mistake. S<strong>in</strong>ce the voltages are out of phase,<br />

their maximums do not add together at the same time. Now let’s visualize this.<br />

6. Write the functions for V R<br />

(t) and<br />

V C<br />

(t).<br />

7. Plot V R<br />

(t) and V C<br />

(t) on the o-scope screen below. Be sure to label units and hash marks<br />

! !<br />

correctly for full credit.<br />

!<br />

!<br />

8. On your graph, sketch the addition of the V R<br />

(t) and V C<br />

(t). This is V source<br />

(t).<br />

3<br />

!<br />

!<br />

!


Lab 8 – On your own.<br />

Experiment 1: Exam<strong>in</strong><strong>in</strong>g the phase shift between V R<br />

(t) and<br />

V C<br />

(t).<br />

a. Set your function generator to create a s<strong>in</strong> wave with a voltage amplitude of a nice round<br />

number like 3 Volts. You may change your frequency later, but start at about 400 Hz..<br />

! !<br />

b. Set up the <strong>RC</strong> circuit with the s<strong>in</strong>usoidal driv<strong>in</strong>g function generator with R =10,000 " ,<br />

and C =1x10 -7 Farads.<br />

c. Set up a middle ground to view the voltage across both the resistor and the capacitor<br />

simultaneously. Make a sketch on the o-scope screen below mak<strong>in</strong>g<br />

!<br />

sure to <strong>in</strong>vert the<br />

!<br />

correct channel for your graph (a necessary step when us<strong>in</strong>g a middle ground).<br />

!<br />

d. Label the signals V R<br />

(t) and V C<br />

(t) on your sketch and determ<strong>in</strong>e equations for V R<br />

(t) and<br />

V C<br />

(t). Also expla<strong>in</strong> which is phase shifted by 90 o . Write your equations and<br />

explanation here:<br />

!<br />

!<br />

!<br />

4


Experiment 2: Test<strong>in</strong>g the relationship " C<br />

= 1 with many frequencies.<br />

#C<br />

a. Use the theoretical relationship " C<br />

= 1 and the equations for voltage amplitutde on the resistor<br />

#C<br />

and capacitor, V C,MAX<br />

= " C<br />

!<br />

Z V and<br />

MAX<br />

V R,MAX<br />

= R Z V MAX<br />

to calculate the driv<strong>in</strong>g angular frequency<br />

necessary to have V R,MAX<br />

= V<br />

! C,MAX<br />

. (You will want to take your data around this angular<br />

frequency <strong>in</strong> the next parts of this experiment.) Report ω EQUAL here.<br />

!<br />

!<br />

!<br />

b. Set your function generator to create a s<strong>in</strong> wave with a voltage amplitude of a nice round number<br />

like 3 Volts. You will be adjust<strong>in</strong>g the frequency dur<strong>in</strong>g the experiment. Use the same R and C<br />

as <strong>in</strong> experiment 1.<br />

c. S<strong>in</strong>ce<br />

!<br />

V C,MAX<br />

= " C<br />

Z V MAX and<br />

V C,MAX<br />

V R,MAX<br />

= R Z V MAX<br />

, divid<strong>in</strong>g these equations gives<br />

= " C<br />

or after multiply<strong>in</strong>g both sides by R, " C<br />

= R #V C,MAX<br />

.<br />

V R,MAX<br />

R V R,MAX<br />

You can measure V!<br />

C,MAX<br />

and V R,MAX<br />

on the oscilloscope, and you can measure R with a DMM.<br />

Therefore, f<strong>in</strong>d X C for many different frequencies us<strong>in</strong>g the equation <strong>in</strong> the box above.<br />

Remember that you can only be sure a DMM resistance measurement<br />

!<br />

!<br />

is accurate by measur<strong>in</strong>g<br />

the resistor naked. Use the data table below:<br />

! !<br />

d. Plot X C vs. ω to support our claim that there is an <strong>in</strong>verse relationship between them. Be sure to<br />

f<strong>in</strong>d ω from f before graph<strong>in</strong>g. (Th<strong>in</strong>k about what the graph should look like if " C<br />

= 1<br />

#C ?)<br />

GRAPH 1<br />

e. Expla<strong>in</strong> why your graph supports the relationship " C<br />

= 1 . Write explanation ! here:<br />

#C<br />

!<br />

5


Experiment 3: F<strong>in</strong>d<strong>in</strong>g C with a s<strong>in</strong>gle frequency measurement.<br />

a. Us<strong>in</strong>g the relationship from experiment 2,<br />

" C<br />

= R #V C,MAX<br />

V R,MAX<br />

You can use this relation for experimental determ<strong>in</strong>ations of C.<br />

1<br />

, you know that<br />

"C = R # V C,MAX<br />

V R,MAX .<br />

b. Make a s<strong>in</strong>gle measurement of ω, ! R, V R,MAX and V C,MAX us<strong>in</strong>g a ! frequency where V R,MAX<br />

and V C,MAX are about the same and determ<strong>in</strong>e C. Report your value for C here:<br />

c. Now perform an x-y measurement with the oscilloscope for V R<br />

(t) versus<br />

ω EQUAL and sketch your result on scope A. Be sure to label your axis.<br />

V C<br />

(t). Start with<br />

d. Now lower the frequency so that V C<br />

(t) is larger than V<br />

! R<br />

(t) and sketch your result on B<br />

!<br />

(another x-y measurement).<br />

e. Now raise the frequency so that V<br />

!<br />

C<br />

(t) is smaller than V<br />

!<br />

R<br />

(t) and sketch your result on C<br />

(another x-y measurement).<br />

A B C<br />

!<br />

!<br />

f. Expla<strong>in</strong> why V C<br />

(t) is larger than V R<br />

(t) when the frequency is low enough. Write<br />

explanation here:<br />

Experiment 4:<br />

!<br />

Mak<strong>in</strong>g and measur<strong>in</strong>g<br />

!<br />

your own capacitor.<br />

a. Make a capacitor from the square cardboard pieces covered <strong>in</strong> foil. Sandwich a non-foil<br />

square with them, and be sure your makeshift capacitor is not shorted.<br />

b. Measure the capacitance of your homemade capacitor us<strong>in</strong>g the technique from part 3. Be<br />

sure to f<strong>in</strong>d a frequency where V R,MAX and V C,MAX are about the same. You may need to<br />

use a different resistor. Report your homemade capacitor capacitance here:<br />

5. CLEAN UP LAB STATION.<br />

6


Lab 8 – Report Guidel<strong>in</strong>es<br />

I will be pay<strong>in</strong>g careful attention to your solutions <strong>in</strong> the above pages. (Ellipsis means you<br />

should not need help here on what to write about).<br />

1. Title - …<br />

2. Goals – …<br />

3. Theory –<br />

• When an <strong>RC</strong> circuit is driven with a s<strong>in</strong>usoidal voltage source, how do the voltages<br />

across the resistor and capacitor behave? What functions describe them?<br />

• At any <strong>in</strong>stant of time, the voltage across the resistor plus the voltage across the<br />

capacitor should add to the voltage across the source. Sometimes the voltage across the<br />

source is zero s<strong>in</strong>ce it is alternat<strong>in</strong>g. At this particular <strong>in</strong>stant of time, what must happen<br />

with the voltages across the resistor and capacitor?<br />

4. Procedure – No more than 3 sentences for each experiment please!!!<br />

5. Results – Describe your results for each experiment with a separate short paragraph.<br />

6. Conclusion – Write a short conclusion paragraph for each experiment and a f<strong>in</strong>al summariz<strong>in</strong>g<br />

paragraph.<br />

7. Attachments <strong>in</strong>clud<strong>in</strong>g all the notes you took on the pages of this handout.<br />

7

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