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States on Subtraction Algebras 1 Introduction

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1156 Sang Mo<strong>on</strong> Lee and Kyung Ho Kim<br />

Zelinka [4] discussed a problem proposed by B. M. Schein c<strong>on</strong>cerning the structure<br />

of multiplicati<strong>on</strong> in a subtracti<strong>on</strong> semigroup. He solved the problem for<br />

subtracti<strong>on</strong> algebras of a special type, called the atomic subtracti<strong>on</strong> algebras.<br />

In this paper, we study the Bosbach state <strong>on</strong> subtracti<strong>on</strong> algebra and show<br />

that there exists a Bosbach state via X/θ where θ is a c<strong>on</strong>gruence relati<strong>on</strong><br />

induced by an ideal of X.<br />

2 Subtracti<strong>on</strong> algebras<br />

By a subtracti<strong>on</strong> algebra we mean an algebra (X; −) with a single binary<br />

operati<strong>on</strong> “−” that satisfies the following identities: for any x, y, z ∈ X,<br />

(S1) x − (y − x) =x;<br />

(S2) x − (x − y) =y − (y − x);<br />

(S3) (x − y) − z =(x − z) − y.<br />

The last identity permits us to omit parentheses in expressi<strong>on</strong>s of the form<br />

(x − y) − z. The subtracti<strong>on</strong> determines an order relati<strong>on</strong> <strong>on</strong> X: a ≤ b ⇔<br />

a − b =0, where 0 = a − a is an element that does not depend <strong>on</strong> the choice<br />

of a ∈ X. The ordered set (X; ≤) is a semi-Boolean algebra in the sense of<br />

[6], that is, it is a meet semilattice with zero 0 in which every interval [0,a]is<br />

a Boolean algebra with respect to the induced order. Here a ∧ b = a − (a − b);<br />

the complement of an element b ∈ [0,a]isa − b; and if b, c ∈ [0,a], then<br />

b ∨ c =(b ′ ∧ c ′ ) ′ = a − ((a − b) ∧ (a − c))<br />

= a − ((a − b) − ((a − b) − (a − c))).<br />

In a subtracti<strong>on</strong> algebra, the following are true: for all x, y, z ∈ X,<br />

(p1) (x − y) − y = x − y.<br />

(p2) x − 0=x and 0 − x =0.<br />

(p3) x − y ≤ x.<br />

(p4) x − (x − y) ≤ y.<br />

(p5) (x − y) − (y − x) =x − y.<br />

(p6) x − (x − (x − y)) = x − y.<br />

(p7) (x − y) − (z − y) ≤ x − z.<br />

(p8) x ≤ y if and <strong>on</strong>ly if x = y − w for some w ∈ X.

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