Integrated mathematics scheme: IMS T2 - National STEM Centre

M52 1. 2cm 2
2. 6.PAO = 6.PBO = 6.PXO, 6.PXR = LPAR = 6.PBR,
6.OBR = L OXR = 6.OYR = 6.OAR,
6. RXS = 6.RYS,
6. BOX = L BRX = 6. BPX, 6.OXS = 6. OYS
6. 2cm 2 2. 3 cm 2 3. 2 cm 2 4. 5 cm 2
7. 2·25cm 2 8. 3·75cm 2 9. 4cm 2 5. 5cm 2
P32
A. 1.
B. 1.
2.
3.
Drawing 2. Drawing
Drawing
Yes, the altitudes should meet at a point
Yes, the altitudes will meet at a point (outside the triangle)
P33
A. 1.
3.
B.
231 km 2. 2·8 m
You construct each triangle with compasses. Start with 6.ABC.
Areas are LABC 770 m 2 6.ACD 680 m 2 LADE 774 m 2
Total area = 2224 m 2
1. True
2. (a) True
3. Not true
(b) True
4.
(c) True
Not true
5. True
C. This is the formula Area = abc/4R and it works for all triangles. This is
especially easy if you want to find the areas of a family of triangles all
drawn with their vertices on the same circle. Area = 800 mm 2 •
E33 A. 2. The figure made up of P and the three arc intersections '" '2 and x
is a rhombus. It has 4 sides equal because that is how you have
drawn them. Therefore PX and AB are diagonals of the same
rhombus and must be perpendicular.
3. Drawing
B. 2. (b) is true
3. The altitudes still meet at a point but outside the triangle
C. Find points " and '2 on the line, an equal distance from P. Now draw
two circles with " and '2 as centres and with the same radius. Choose
the radius large enough for the two circles to meet above and below
the line. The points '" '2 and the two points of intersection of the
circles will form a rhombus.
E34 A. B., C. see P33
D. 1. Measurement 2. All th ree suggestions are true
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