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Diploma thesis as pdf file - Johannes Kepler University, Linz

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3.4 Numerical experiments 35<br />

3.4.2 Example 2<br />

We consider another radially symmetric problem when: Ω is a unit circle, constant<br />

force is acting on the membrane f = −10, and the obstacle is described <strong>as</strong><br />

{ √<br />

R<br />

ψ(x,y) =<br />

2 − x 2 − y 2 − R − 1, if x 2 + y 2 ≤ R 2 ,<br />

−5, if x 2 + y 2 > R 2<br />

where R = 0.7<br />

The exact solution to this problem is :<br />

{ √<br />

R<br />

u =<br />

2 − x 2 − y 2 − R − 1, if x 2 + y 2 < r<br />

5(x 2 + y 2 )/2 − alnr − 5/2, if x 2 + y 2 ≥ r<br />

where r = 0.3976, a = r 2 (5 + 1/ √ R 2 − r 2 ).<br />

Figure 3.5 depicts the final iterate of the approximate solution.<br />

Figure 3.5: Approximate solution for the obstacle with the spherical surface<br />

The table 3.4.2 reports the results when the stopping criterion for the Newton<br />

iterations w<strong>as</strong> changed to δu<br />

u−ψ<br />

≤ 0.1. It illustrates that stricter stopping criterion<br />

doesn’t improve the accuracy of the solution for the original constrained problem,<br />

but only incre<strong>as</strong>es the number of iterations. This confirms the fact that we<br />

don’t need to solve each corrector problem with high accuracy but it’s sufficient

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