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Chapter 2 Stellar Structure Equations 1 Mass conservation equation

Chapter 2 Stellar Structure Equations 1 Mass conservation equation

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( d 2 P<br />

dr 2 )c<br />

= −<br />

( dρ Gm<br />

+ ρ G dm<br />

dr r 2 r 2 dr − 2ρGm r<br />

)c<br />

3<br />

= − 4πGρ2 c<br />

, (16)<br />

3<br />

Therefore near the centre<br />

P (r) = P c − 2 3 πGρ2 cr 2 . (17)<br />

For the luminosity F (r) we have F c = 0 (boundary condition), and<br />

( d 2 F<br />

dr 2 )c<br />

( ) dF<br />

= 4π ( r 2 ρq ) = 0, (18)<br />

dr<br />

c<br />

c<br />

(<br />

= 4π 2rρq + r 2 dρ<br />

dr q + r2 ρ dq )<br />

= 0, (19)<br />

dr<br />

c<br />

( d 3 F<br />

dr 3 )c<br />

= 4π [ 2ρq + r (...) + r 2 (..) ] c = 8πρ cq c . (20)<br />

Therefore near the centre<br />

F (r) = 4 3 πρ cq c r 3 . (21)<br />

For the temperature T (r) we obtain<br />

( ) dT<br />

= − 3 ( kρ F<br />

= −<br />

dr<br />

c<br />

16πac T 3 r<br />

)c<br />

1 ( ) kρ 2 q<br />

2 4ac T r = 0, (22)<br />

3<br />

( d 2 T<br />

dr 2 )c<br />

= − 3 [ ( )<br />

kρ d F<br />

+ F (<br />

d kρ<br />

= −<br />

16πac T 3 dr r 2 r 2 dr T<br />

)]c<br />

1<br />

3 4ac<br />

k c ρ 2 cq c<br />

. (23)<br />

Tc<br />

3<br />

5

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