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Deformation Techniques for Efficient Polynomial Equation ... - RISC

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96 HEINTZ ET AL.<br />

Taking into account M 1 (T ){0 we conclude<br />

R(T, Y) := 1<br />

M 1 (T )<br />

:<br />

0 jr<br />

(&1) r& j M r+1&j (T ) Y j .<br />

Now we are going to construct our approximation polynomial R (T, Y).<br />

Let M (T ) be the 2r_(2r+1) submatrix of the Sylvester matrix of Q and<br />

Q $:=Q Y determined by the same choice of rows and columns as the<br />

matrices M t and M(T ) (this makes sense because we have, by assumption,<br />

deg Y Q =deg Y Q).<br />

Again, <strong>for</strong> 1 jr+1, denote by M j(T ) the minor of M(T ) obtained<br />

by deleting the j th column. As by assumption Q (t, Y)=Q(t, Y) holds we<br />

deduce easily the identities M j(t)=M j (t) <strong>for</strong> 1 jr+1. In particular we<br />

have M 1(t){0 and M 1(T ){0. More precisely, M 1 (t){0 implies that<br />

M 1(T ) is a unit of the local Q-algebra Q[T] M . In particular, <strong>for</strong> any<br />

1 jr+1 the rational function M j(T )M 1(T ) belongs to Q[T] M .We<br />

would like to use the expression<br />

1<br />

M 1(T )<br />

:<br />

0 jr<br />

(&1) r& j M r+1&j(T ) Y j (16)<br />

<strong>for</strong> the definition of the approximation polynomial R (T, Y).<br />

However, the expression (16) contains terms which are rational functions<br />

in T=(T 1 , ..., T m ). In order to avoid this difficulty we replace the rational<br />

functions M r+1&j(T )M 1(T ) occurring in (16) by suitable approximation<br />

polynomials of Q[T]. For this purpose we proceed as follows.<br />

Without loss of generality we may assume that M 1 (t)=M 1(t)=1 holds.<br />

Let us write H :=1&M 1 and H :=1&M 1. Hence, H(t)=H (t)=0 and we<br />

obtain the following identities in the power series ring QT&t :<br />

1<br />

= : H l<br />

M 1 l0<br />

and<br />

1<br />

= : H l<br />

.<br />

M 1<br />

l0<br />

Thus, in order to approximate R(T, Y) with precision s in QT&t, we<br />

define the polynomial R (T, Y)#Q[T, Y] as<br />

R (T, Y):= :<br />

0ls<br />

H<br />

l (T ) :<br />

0 jr<br />

(&1) r& j M r+1&j(T ) Y j .<br />

Let us verify that R satisfies the requirements of the statement of Lemma 7:<br />

v Obviously we have R {0 and from M 1 {0 we deduce that<br />

deg Y R =r=deg Y R holds.

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