Reteach 14-6
Reteach 14-6
Reteach 14-6
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Name Date Class<br />
LESSON<br />
<strong>14</strong>-6<br />
<strong>Reteach</strong><br />
Solving Trigonometric Equations<br />
You can use the same methods to solve trigonometric equations as to solve algebraic<br />
equations.<br />
Substitute variables to solve trigonometric equations that resemble quadratic equations.<br />
Solve: si n 2 3sin 4 0 for 0 360<br />
Step 1 Make a substitution.<br />
Let x sin in si n 2 3sin 4 0<br />
x 2 3x 4 0<br />
Step 2 Solve the quadratic x 2 3x 4 0.<br />
x 4 x 1 0<br />
Factor.<br />
x 4 0 x 1 0 Set each factor equal to 0.<br />
x 4 x 1 Solve each equation for x.<br />
Step 3 Substitute sin for x.<br />
sin 4<br />
–1 sin 1<br />
This equation has no solution.<br />
sin 1 Think: What angle has a sine of 1?<br />
270<br />
The only solution is 270.<br />
Complete to solve each equation for 0 360.<br />
1. 3t an 2 1 0 2. 2s in 2 sin 0<br />
Let x tan . Let x sin .<br />
Hint: There are 4 solutions.<br />
Hint: There are 4 solutions.<br />
3x 2 1 0 2 x 2 x 0<br />
3x 2 1 x 2x 1 0<br />
x ___ 3<br />
x 0 or 2x 1 0<br />
3<br />
tan ___ 3<br />
3 or ___ 3<br />
3 ; x 0 or x __ 1 2<br />
sin 0 or sin __ 1<br />
30, 150, 210, 330<br />
0, 30, 150, 180 2<br />
3. cos 2 2cos 1 0 4. 2c os 2 7cos 3 0<br />
x 2 2x 1; x 1 2 ;<br />
cos 1; 0<br />
The interval includes 0 but<br />
not 360.<br />
2 x 2 7x 3 0<br />
2x 1 x 3 0<br />
x __ 1 2 or x 3<br />
60, 300<br />
Copyright © by Holt, Rinehart and Winston.<br />
46 Holt Algebra 2<br />
All rights reserved.
Name Date Class<br />
LESSON<br />
<strong>14</strong>-6<br />
<strong>Reteach</strong><br />
Solving Trigonometric Equations (continued)<br />
You can use trigonometric identities to solve trigonometric equations. This<br />
is especially useful when more than one trigonometric function appears in<br />
an equation.<br />
Use an identity to rewrite the equation using a single<br />
trigonometric function or a single angle.<br />
Solve: cos2 cos 0 for 0 360<br />
Step 1 The angles are not the same.<br />
Use the double-angle identity for cosine.<br />
Choose cos2 2c os 2 1.<br />
Use an identity. Choose the<br />
formula that allows you to<br />
write the equation in terms of<br />
cos only.<br />
Step 2 Substitute 2c os 2 1 for cos2 in the original equation.<br />
cos2 cos 0<br />
Write the original equation.<br />
2co s 2 1 cos 0<br />
Substitute.<br />
2c os 2 cos 1 0<br />
Write in standard form.<br />
Step 3 Solve the equation.<br />
2c os 2 cos 1 0<br />
2cos 1 cos 1 0<br />
Factor.<br />
2cos 1 0 cos 1 0 Set each factor equal to 0.<br />
cos 1__ 2<br />
cos 1 Solve each equation for cos .<br />
Step 4 Find the values that satisfy each solution.<br />
cos 1__ Think: What angle has a cosine of 1__ 2<br />
2 ?<br />
60, 300<br />
cos 1 Think: What angle has a cosine of 1?<br />
180<br />
Remember to<br />
find all values<br />
in the interval.<br />
Use trigonometric identities to solve each equation for 0 360.<br />
5. cos2 sin 2 0 6. c os 2 2sin 1<br />
Use cos2 1 2 sin 2 . Use c os 2 1 s in 2 .<br />
1 2si n 2 sin 2 0<br />
2s in 2 – sin 3 0<br />
2sin 3 sin 1 0<br />
sin __ 3 or sin 1<br />
2<br />
270<br />
1 s in 2 2sin 1<br />
si n 2 2sin 0<br />
sin sin 2 0<br />
sin 0 or sin 2<br />
0, 180<br />
Copyright © by Holt, Rinehart and Winston.<br />
47 Holt Algebra 2<br />
All rights reserved.