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Name Date Class<br />

LESSON<br />

<strong>14</strong>-6<br />

<strong>Reteach</strong><br />

Solving Trigonometric Equations<br />

You can use the same methods to solve trigonometric equations as to solve algebraic<br />

equations.<br />

Substitute variables to solve trigonometric equations that resemble quadratic equations.<br />

Solve: si n 2 3sin 4 0 for 0 360<br />

Step 1 Make a substitution.<br />

Let x sin in si n 2 3sin 4 0<br />

x 2 3x 4 0<br />

Step 2 Solve the quadratic x 2 3x 4 0.<br />

x 4 x 1 0<br />

Factor.<br />

x 4 0 x 1 0 Set each factor equal to 0.<br />

x 4 x 1 Solve each equation for x.<br />

Step 3 Substitute sin for x.<br />

sin 4<br />

–1 sin 1<br />

This equation has no solution.<br />

sin 1 Think: What angle has a sine of 1?<br />

270<br />

The only solution is 270.<br />

Complete to solve each equation for 0 360.<br />

1. 3t an 2 1 0 2. 2s in 2 sin 0<br />

Let x tan . Let x sin .<br />

Hint: There are 4 solutions.<br />

Hint: There are 4 solutions.<br />

3x 2 1 0 2 x 2 x 0<br />

3x 2 1 x 2x 1 0<br />

x ___ 3<br />

x 0 or 2x 1 0<br />

3<br />

tan ___ 3<br />

3 or ___ 3<br />

3 ; x 0 or x __ 1 2<br />

sin 0 or sin __ 1<br />

30, 150, 210, 330<br />

0, 30, 150, 180 2<br />

3. cos 2 2cos 1 0 4. 2c os 2 7cos 3 0<br />

x 2 2x 1; x 1 2 ;<br />

cos 1; 0<br />

The interval includes 0 but<br />

not 360.<br />

2 x 2 7x 3 0<br />

2x 1 x 3 0<br />

x __ 1 2 or x 3<br />

60, 300<br />

Copyright © by Holt, Rinehart and Winston.<br />

46 Holt Algebra 2<br />

All rights reserved.


Name Date Class<br />

LESSON<br />

<strong>14</strong>-6<br />

<strong>Reteach</strong><br />

Solving Trigonometric Equations (continued)<br />

You can use trigonometric identities to solve trigonometric equations. This<br />

is especially useful when more than one trigonometric function appears in<br />

an equation.<br />

Use an identity to rewrite the equation using a single<br />

trigonometric function or a single angle.<br />

Solve: cos2 cos 0 for 0 360<br />

Step 1 The angles are not the same.<br />

Use the double-angle identity for cosine.<br />

Choose cos2 2c os 2 1.<br />

Use an identity. Choose the<br />

formula that allows you to<br />

write the equation in terms of<br />

cos only.<br />

Step 2 Substitute 2c os 2 1 for cos2 in the original equation.<br />

cos2 cos 0<br />

Write the original equation.<br />

2co s 2 1 cos 0<br />

Substitute.<br />

2c os 2 cos 1 0<br />

Write in standard form.<br />

Step 3 Solve the equation.<br />

2c os 2 cos 1 0<br />

2cos 1 cos 1 0<br />

Factor.<br />

2cos 1 0 cos 1 0 Set each factor equal to 0.<br />

cos 1__ 2<br />

cos 1 Solve each equation for cos .<br />

Step 4 Find the values that satisfy each solution.<br />

cos 1__ Think: What angle has a cosine of 1__ 2<br />

2 ?<br />

60, 300<br />

cos 1 Think: What angle has a cosine of 1?<br />

180<br />

Remember to<br />

find all values<br />

in the interval.<br />

Use trigonometric identities to solve each equation for 0 360.<br />

5. cos2 sin 2 0 6. c os 2 2sin 1<br />

Use cos2 1 2 sin 2 . Use c os 2 1 s in 2 .<br />

1 2si n 2 sin 2 0<br />

2s in 2 – sin 3 0<br />

2sin 3 sin 1 0<br />

sin __ 3 or sin 1<br />

2<br />

270<br />

1 s in 2 2sin 1<br />

si n 2 2sin 0<br />

sin sin 2 0<br />

sin 0 or sin 2<br />

0, 180<br />

Copyright © by Holt, Rinehart and Winston.<br />

47 Holt Algebra 2<br />

All rights reserved.

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