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Tutorial Answers - School of Physics - The University of New South ...

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15. [Serway et al 15.17]. By considering the quark makeup <strong>of</strong> the various particles, deduce the<br />

identity <strong>of</strong> the unknown particle in the reaction<br />

Σ<br />

0<br />

+ p → Σ<br />

+<br />

+ γ + ?<br />

Σ<br />

u<br />

d<br />

0<br />

: 3<br />

= uds;<br />

p = uud;<br />

Σ<br />

: 2<br />

s :1 → 1<br />

Mystery particle has quark makeup udd i.e. neutron.<br />

16. [K9.9]. <strong>The</strong> complete processes are:<br />

3 3<br />

ν + He→<br />

H + e<br />

− 8 8<br />

e + B→<br />

Be + ν<br />

40<br />

K →ν<br />

+ e<br />

+<br />

+<br />

+<br />

40<br />

Ar<br />

→ 2 + ? ∴u<br />

→ 0∴<br />

dd<br />

6<br />

He→<br />

ν +<br />

40<br />

12<br />

+<br />

6<br />

C→<br />

= uus<br />

Li + e<br />

12<br />

−<br />

N + e<br />

−<br />

K →ν<br />

+ e +<br />

17. [K9.4]. <strong>The</strong> maximum kinetic energy <strong>of</strong> the positron spectrum emitted in the decay 11 C→<br />

11 B<br />

Q = K<br />

∴ m(<br />

11<br />

is 1.983±0.003 MeV. Use this information and the known mass <strong>of</strong> 11 B to calculate the mass <strong>of</strong><br />

11 C.<br />

max<br />

β<br />

= 1.983(3) MeV =<br />

⎛ Q ⎞<br />

C)<br />

= ⎜ + m(<br />

2<br />

⎟<br />

⎝ c ⎠<br />

11<br />

B)<br />

+ 2m<br />

11<br />

6<br />

C→<br />

11<br />

5<br />

+<br />

B + β + ν<br />

11<br />

11<br />

[ m(<br />

C)<br />

− m(<br />

B)<br />

− 2me<br />

]<br />

e<br />

c<br />

2<br />

e<br />

+ ν<br />

−<br />

40<br />

Ca<br />

⎧ 1.983(3) MeV ⎫<br />

= ⎨<br />

⎬ + 11.009305u<br />

+ 2(5.485803×<br />

10<br />

⎩931.502<br />

MeV / u ⎭<br />

−4<br />

) = 11.012531(3) u<br />

18. [Serway 45.59]. A by-product <strong>of</strong> some fission reactors is 239 Pu which is an α-emitter with a<br />

half-life <strong>of</strong> 24,120 years. Consider 1 kg <strong>of</strong> 239 Pu at t=0. (a) What is the number <strong>of</strong> 239 Pu nuclei at<br />

t=0 ? (b) What is the initial activity ? (c) For how long would you need to store the Plutonium<br />

until it had decayed to a safe activity level <strong>of</strong> 0.1 Bq ?<br />

( a)<br />

1 nucleus = 239 × 1.66×<br />

10<br />

( b)<br />

( c)<br />

R<br />

0<br />

= λN<br />

0<br />

ln 2<br />

= N<br />

t 1<br />

0.1 = 2.305×<br />

10<br />

2<br />

12<br />

e<br />

0<br />

−27<br />

= 2.305×<br />

10<br />

= 3.97 × 10<br />

12<br />

Bq<br />

∴t<br />

= 1.07 × 10<br />

−λt 6<br />

yrs<br />

−25<br />

kg ∴ N<br />

0<br />

= 1/(3.97 × 10<br />

−25<br />

) = 2.519 × 10<br />

24<br />

19. [A&M 15.14]. Calculate the Q value for the β – decay <strong>of</strong> 108 Ag.<br />

108<br />

47<br />

Ag→<br />

108<br />

48<br />

−<br />

Cd + β + ν<br />

2<br />

Q = ( M P − M D ) c = (107.905952 −107.904176)<br />

u × 931.5MeV<br />

/ u = 1. 65MeV<br />

20. [A&M 15.19]. On the basis <strong>of</strong> Q values, determine if the 98 Tc nucleus can decay by (a) β –<br />

(a)<br />

98<br />

43<br />

decay, (b) β + decay, (c) electron capture.<br />

Tc→<br />

98<br />

44<br />

−<br />

Ru + β + ν<br />

e<br />

2<br />

Q = ( M − M ) c = (97.907215 − 97.905287) u × 931.5MeV<br />

/ u = 1.796MeV<br />

i.<br />

e.<br />

> 0∴Yes<br />

P<br />

D<br />

e

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