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⎡1<br />
1 ⎤ ⎡ ⎤<br />
7. Let E = ⎥ + 1 2<br />
⎢ + ⎢ + ⎥ + ... upto 50 terms, then -<br />
⎣3<br />
50 ⎦ ⎣3<br />
50 ⎦<br />
(A) E is divisible by exactly 2 primes<br />
(B) E is prime<br />
(C) E ≥ 30<br />
(D) E ≤ 35<br />
8. If m is a positive integer, then [( 3 + 1) ] + 1,<br />
where [x] denotes greatest integer ≤ n, is divisible<br />
by-<br />
(A) 2 m (B) 2 m+1 (C) 2 m+2 (D) 2 2m<br />
9. If A and B are acute angles such that sin A = sin 2 B,<br />
2 cos 2 A = 3 cos 2 B; then -<br />
(A) A = π/6 (B) A = π/2<br />
(C) B = π/4 (D) B = π/3<br />
This section contains 2 questions (Questions 10 to 11).<br />
Each question contains statements given in two<br />
columns which have to be matched. Statements (A, B,<br />
C, D) in Column I have to be matched with statements<br />
(P, Q, R, S, T) in Column II. The answers to these<br />
questions have to be appropriately bubbled as<br />
illustrated in the following example. If the correct<br />
matches are A-P, A-S, A-T, B-Q, B-R, C-P, C-Q and<br />
D-S, D-T then the correctly bubbled 4 × 5 matrix<br />
should be as follows :<br />
P Q R S T<br />
A<br />
B<br />
C<br />
D<br />
P<br />
P<br />
P<br />
P<br />
Q<br />
Q<br />
Q<br />
Q<br />
R<br />
R<br />
R<br />
R<br />
S<br />
S<br />
S<br />
S<br />
T<br />
T<br />
T<br />
T<br />
10. For the circle x 2 + y 2 + 4x + 6y – 19 = 0<br />
Column-I<br />
Column-II<br />
72 226<br />
(A) Length of the tangent (P)<br />
113<br />
from (6, 4) to the circle<br />
(B) Length of the chord (Q) 113<br />
of contact from (6, 4)<br />
to the circle<br />
(C) Distance of (6, 4) (R) 113 – 32<br />
from the centre of the<br />
circle<br />
(D) Shortest distance of (S) 9<br />
(6, 4) from the circle<br />
(T) None<br />
11. Value of x when<br />
Column-I<br />
Column-II<br />
(A) 5 2 5 4 5 6 ... 5 2x = (0.04) –28 (P) 3 log 3 5<br />
⎛ 1 1 1 ⎞<br />
(B) x 2 log 5 ⎜ + + + ... ⎟<br />
=<br />
⎝ 4 8 16<br />
( 0.2)<br />
⎠<br />
(Q) 4<br />
⎛ 1 1 1<br />
log<br />
⎞<br />
2.5 ⎜ + + + ... ⎟<br />
⎝ 3 2 3<br />
3 3 ⎠<br />
(C) x = ( 0.16)<br />
(R) 2<br />
2m<br />
(D) 3 x–1 + 3 x–2 + 3 x–3 + ... (S) 7<br />
⎛ 2 1 1 ⎞<br />
= 2 ⎜5<br />
+ 5 + 1+<br />
+ + ... ⎟<br />
⎝ 5<br />
2<br />
5 ⎠<br />
(T) None<br />
This section contains 8 questions (Questions 12 to 19).<br />
The answer to each of the questions is a SINGLE-<br />
DIGIT INTEGER, ranging from 0 to 9. The<br />
appropriate bubbles below the respective question<br />
numbers in the OMR have to be darkened. For<br />
example, if the correct answers to question numbers X,<br />
Y, Z and W (say) are 6, 0, 9 and 2, respectively, then<br />
the correct darkening of bubbles will look like the<br />
following :<br />
X Y Z W<br />
0<br />
1<br />
2<br />
3<br />
4<br />
5<br />
6<br />
7<br />
8<br />
9<br />
0<br />
1<br />
2<br />
3<br />
4<br />
5<br />
6<br />
7<br />
8<br />
9<br />
12. Fifteen persons, among whom are A and B, sit down at<br />
random at a round table. if p is The probability that<br />
there are exactly 4 persons between A and B find 14 p.<br />
13. If l is the length of the intercept made by a common<br />
tangent to the circle x 2 + y 2 = 16 and the ellipse<br />
x 2 /25 + y 2 /4 = 1, on the coordinate axes, then<br />
81l<br />
2 + 3<br />
is equal to<br />
1059<br />
14. If x + y = k is a normal to the parabola y 2 = 12x, p is<br />
the length of the perpendicular from the focus of the<br />
3k<br />
3 2<br />
+ 2p<br />
parabola on this normal; then<br />
is equal to<br />
741<br />
15. The volume of the tetrahedron whose vertices are<br />
(0, 1, 2) (3, 0, 1) (4, 3, 6) (2, 3, 2) is equal to<br />
0<br />
1<br />
2<br />
3<br />
4<br />
5<br />
6<br />
7<br />
8<br />
9<br />
0<br />
1<br />
2<br />
3<br />
4<br />
5<br />
6<br />
7<br />
8<br />
9<br />
16. Let a 1 = 2<br />
1 , ak+1 = a k 2 + a k ∀ k ≥ 1 and<br />
1 1 1<br />
x n = + + ... +<br />
a1 + 1 a 2 + 1 a n + 1<br />
Find [x 100 ] where [x] denotes the greatest integer ≤ x.<br />
17. Find the value of x which satisfy the equation<br />
log 2 (x 2 – 3) – log 2 (6x – 10) + 1 = 0<br />
18. Find the coefficient of x 2009 in the expansion of<br />
(1 – x) 2008 (1 + x + x 2 ) 2007<br />
1/ log x<br />
2<br />
19. Find the value of x satisfying 4 = 2.<br />
XtraEdge for <strong>IIT</strong>-<strong>JEE</strong> 68 DECEMBER 2009