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Fields and Potentials of a Charged Conducting Sphere.

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R<br />

Q<br />

Solid conducting sphere with<br />

charge Q on the surface<br />

(a) Find the electric field both inside <strong>and</strong> outside the sphere.<br />

(b) Find the potential both inside <strong>and</strong> outside with the zero <strong>of</strong> potential at<br />

infinity.<br />

(a) Calculation <strong>of</strong> the fields:<br />

E = 0<br />

Inside: the field inside a conductor<br />

must be zero under static conditions<br />

Q<br />

r<br />

E<br />

n<br />

Outside: the field outside is found<br />

using Gauss’ Law:<br />

S<br />

∫<br />

S<br />

Q<br />

Q<br />

E cos0<br />

dA = ⇒<br />

E<br />

dA =<br />

ε<br />

∫<br />

⇒<br />

E =<br />

0<br />

ε<br />

0<br />

4<br />

S<br />

Q<br />

r<br />

πε<br />

0<br />

2<br />

1


(b) Potential for r > R<br />

s<br />

r<br />

s<br />

We set the potential at infinity to be zero:<br />

V<br />

V −<br />

V = −<br />

r<br />

r<br />

0<br />

∞<br />

r<br />

f<br />

r<br />

∫<br />

∞<br />

r r<br />

E ⋅<br />

ds = −<br />

r<br />

∫<br />

∞<br />

Qsˆ<br />

4πε<br />

s<br />

0<br />

ds<br />

E<br />

r<br />

Qsˆ<br />

E =<br />

4πε<br />

s<br />

2<br />

⋅<br />

d ssˆ<br />

Q<br />

d s<br />

Q ⎡1⎤<br />

Q<br />

= −<br />

2<br />

4πε<br />

∫ = =<br />

s 4πε<br />

⎢<br />

s ⎥<br />

⎣ ⎦ πε<br />

r<br />

0 0 ∞<br />

4<br />

∞<br />

r<br />

0<br />

0<br />

2<br />

No negative sign here<br />

i<br />

infinity<br />

Potential inside the conducting sphere:<br />

The potential at the surface <strong>of</strong> the conducting sphere<br />

is found using the potential obtained for r > R by<br />

setting r = R:<br />

Q<br />

V R<br />

=<br />

4πε<br />

0<br />

R<br />

The potential inside the sphere is constant <strong>and</strong> must equal the potential<br />

on its surface. Therefore the above result is also the potential<br />

anywhere inside the sphere.<br />

2

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