Chapter 15--Our Sun - Geological Sciences
Chapter 15--Our Sun - Geological Sciences
Chapter 15--Our Sun - Geological Sciences
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Figure <strong>15</strong>.9 Vibrations on the surface of<br />
the <strong>Sun</strong> can be detected by Doppler shifts.<br />
In this schematic representation, red indicates<br />
falling gas, and blue indicates rising gas.<br />
The speckled region indicates the convection<br />
zone. The vibration pattern illustrated<br />
here is just one of many possible patterns.<br />
The overall vibration pattern of the <strong>Sun</strong> is a<br />
complex combination of patterns similar to<br />
this one.<br />
In principle, we can deduce a great deal about the<br />
solar interior by carefully analyzing these vibrations. (By<br />
analogy to seismology on Earth, this type of study of the<br />
<strong>Sun</strong> is called helioseismology—helios means “sun.”) Results<br />
to date confirm that our mathematical models of the<br />
solar interior are on the right track (Figure <strong>15</strong>.10). At the<br />
same time, they provide data that can be used to improve<br />
the models further.<br />
Mathematical Insight <strong>15</strong>.1 Mass-Energy Conversion in the <strong>Sun</strong><br />
We can calculate how much mass the <strong>Sun</strong> loses through nuclear<br />
fusion by comparing the input and output masses of the proton–<br />
proton chain. A single proton has a mass of 1.6726 10 27 kg,<br />
so four protons have a mass of 6.690 10 27 kg.<br />
A helium-4 nucleus has a mass of only 6.643 10 27 kg,<br />
slightly less than the mass of the four protons. The difference is:<br />
6.690 10 27 kg 6.643 10 27 kg 4.7 10 29 kg<br />
which is 0.7%, or 0.007, of the original mass. Thus, for example,<br />
when 1 kilogram of hydrogen fuses, the resulting helium weighs<br />
only 993 grams, while 7 grams of mass turns into energy.<br />
To calculate the total amount of mass converted to energy<br />
in the <strong>Sun</strong> each second, we use Einstein’s equation E mc 2 .The<br />
total energy produced by the <strong>Sun</strong> each second is 3.8 10 26 joules,<br />
so we can solve for the total mass converted to energy each second:<br />
E mc 2 E<br />
⇒ m c 2<br />
<br />
3.8 10 26 joules<br />
<br />
<br />
3.0 10 8 m s 2<br />
4.2 10 9 kg<br />
The <strong>Sun</strong> loses about 4 billion kilograms of mass every second,<br />
which is roughly equivalent to the combined mass of nearly<br />
100 million people.<br />
Example: How much hydrogen is converted to helium each<br />
second in the <strong>Sun</strong>?<br />
Solution: We have already calculated that the <strong>Sun</strong> loses 4.2 10 9 kg<br />
of mass each second and that this is only 0.7% of the mass of hydrogen<br />
that is fused:<br />
4.2 10 9 kg 0.007 mass of hydrogen fused<br />
We now solve for the mass of hydrogen fused:<br />
mass of<br />
hydrogen fused 4.2 10<br />
9 kg<br />
<br />
0.007<br />
6.0 10 11 kg 1m etric<br />
ton<br />
103<br />
kg<br />
6.0 10 8 metric tons<br />
The <strong>Sun</strong> fuses 600 million metric tons of hydrogen each second,<br />
of which about 4 million tons becomes energy. The remaining<br />
596 million tons becomes helium.<br />
chapter <strong>15</strong> • <strong>Our</strong> Star 505