21.11.2014 Views

Chapter 15--Our Sun - Geological Sciences

Chapter 15--Our Sun - Geological Sciences

Chapter 15--Our Sun - Geological Sciences

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

Figure <strong>15</strong>.9 Vibrations on the surface of<br />

the <strong>Sun</strong> can be detected by Doppler shifts.<br />

In this schematic representation, red indicates<br />

falling gas, and blue indicates rising gas.<br />

The speckled region indicates the convection<br />

zone. The vibration pattern illustrated<br />

here is just one of many possible patterns.<br />

The overall vibration pattern of the <strong>Sun</strong> is a<br />

complex combination of patterns similar to<br />

this one.<br />

In principle, we can deduce a great deal about the<br />

solar interior by carefully analyzing these vibrations. (By<br />

analogy to seismology on Earth, this type of study of the<br />

<strong>Sun</strong> is called helioseismology—helios means “sun.”) Results<br />

to date confirm that our mathematical models of the<br />

solar interior are on the right track (Figure <strong>15</strong>.10). At the<br />

same time, they provide data that can be used to improve<br />

the models further.<br />

Mathematical Insight <strong>15</strong>.1 Mass-Energy Conversion in the <strong>Sun</strong><br />

We can calculate how much mass the <strong>Sun</strong> loses through nuclear<br />

fusion by comparing the input and output masses of the proton–<br />

proton chain. A single proton has a mass of 1.6726 10 27 kg,<br />

so four protons have a mass of 6.690 10 27 kg.<br />

A helium-4 nucleus has a mass of only 6.643 10 27 kg,<br />

slightly less than the mass of the four protons. The difference is:<br />

6.690 10 27 kg 6.643 10 27 kg 4.7 10 29 kg<br />

which is 0.7%, or 0.007, of the original mass. Thus, for example,<br />

when 1 kilogram of hydrogen fuses, the resulting helium weighs<br />

only 993 grams, while 7 grams of mass turns into energy.<br />

To calculate the total amount of mass converted to energy<br />

in the <strong>Sun</strong> each second, we use Einstein’s equation E mc 2 .The<br />

total energy produced by the <strong>Sun</strong> each second is 3.8 10 26 joules,<br />

so we can solve for the total mass converted to energy each second:<br />

E mc 2 E<br />

⇒ m c 2<br />

<br />

3.8 10 26 joules<br />

<br />

<br />

3.0 10 8 m s 2<br />

4.2 10 9 kg<br />

The <strong>Sun</strong> loses about 4 billion kilograms of mass every second,<br />

which is roughly equivalent to the combined mass of nearly<br />

100 million people.<br />

Example: How much hydrogen is converted to helium each<br />

second in the <strong>Sun</strong>?<br />

Solution: We have already calculated that the <strong>Sun</strong> loses 4.2 10 9 kg<br />

of mass each second and that this is only 0.7% of the mass of hydrogen<br />

that is fused:<br />

4.2 10 9 kg 0.007 mass of hydrogen fused<br />

We now solve for the mass of hydrogen fused:<br />

mass of<br />

hydrogen fused 4.2 10<br />

9 kg<br />

<br />

0.007<br />

6.0 10 11 kg 1m etric<br />

ton<br />

103<br />

kg<br />

6.0 10 8 metric tons<br />

The <strong>Sun</strong> fuses 600 million metric tons of hydrogen each second,<br />

of which about 4 million tons becomes energy. The remaining<br />

596 million tons becomes helium.<br />

chapter <strong>15</strong> • <strong>Our</strong> Star 505

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!