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Fundamentals of Electrochemistry - W.H. Freeman

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1504T_ch14_270-297 1/23/06 11:35 Page 290<br />

Solution Abbreviating dehydroascorbic acid as D, and ascorbic acid as H 2 A, we rewrite<br />

the reduction as<br />

for which the Nernst equation is<br />

(14-33)<br />

D is not an acid or a base, so its formal concentration equals its molar concentration:<br />

F D [D]. For the diprotic acid H 2 A, we use Equation 14-29 to express [H 2 A] in terms<br />

<strong>of</strong> F H2 A:<br />

Putting these values into Equation 14-33 gives<br />

E E° <br />

which can be rearranged to the form<br />

D 2H 2e T H 2 A H 2 O<br />

E E° <br />

0.059 16<br />

2<br />

0.059 16<br />

log<br />

2<br />

0.059 16<br />

1<br />

E E° log<br />

<br />

2 [H<br />

14444444244444443<br />

] 2 [H ]K 1 K 1 K 2<br />

Formal potential ( E°¿ if pH 7)<br />

0.062 V<br />

£<br />

[H 2 A]<br />

log<br />

[D][H ] 2<br />

[H ] 2 F H2 A<br />

[H 2 A] <br />

[H ] 2 [H ]K 1 K 1 K 2<br />

[H ] 2 F H2 A<br />

[H ] 2 [H ]K 1 K 1 K 2 ≥<br />

F D [H ] 2<br />

0.059 16 F H2 A<br />

log<br />

2 F D<br />

(14-34)<br />

Putting the values <strong>of</strong> E°, K and into Equation 14-34 and setting [H ] 10 7.00 1 , K 2<br />

, we<br />

find E°¿ 0.062 V.<br />

Curve a in Figure 14-11 shows how the calculated formal potential for Reaction 14-32<br />

depends on pH. The potential decreases as the pH increases, until pH pK 2 . Above pK 2 ,<br />

0.40<br />

0.30<br />

Formal potential (V)<br />

0.20<br />

0.10<br />

(b)<br />

(a)<br />

0.00<br />

–0.10<br />

0<br />

2 4 6 8 10 12 14<br />

pH<br />

Figure 14-11 Reduction potential <strong>of</strong> ascorbic acid, showing its dependence on pH. (a) Graph<br />

<strong>of</strong> the function labeled formal potential in Equation 14-34. (b) Experimental polarographic halfwave<br />

reduction potential <strong>of</strong> ascorbic acid in a medium <strong>of</strong> ionic strength 0.2 M. The half-wave<br />

potential, discussed in Chapter 17, is nearly the same as the formal potential. At high pH (712), the<br />

half-wave potential does not level <strong>of</strong>f to a slope <strong>of</strong> 0, as Equation 14-34 predicts. Instead, a<br />

hydrolysis reaction <strong>of</strong> ascorbic acid occurs and the chemistry is more complex than Reaction<br />

14-32. [J. J. Ruiz, A. Aldaz, and M. Dominguez, Can. J. Chem. 1977, 55, 2799; ibid. 1978, 56, 1533.]<br />

290 CHAPTER 14 <strong>Fundamentals</strong> <strong>of</strong> <strong>Electrochemistry</strong>

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