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Fundamentals of Electrochemistry - W.H. Freeman

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1504T_ch14_270-297 1/23/06 11:35 Page 293<br />

molecules. For ATP synthesis, G 34.5 kJ/mol. This energy is<br />

then made available to the cell when ATP is hydrolyzed to ADP<br />

(adenosine diphosphate). In animals, ATP is synthesized when protons<br />

pass through a complex enzyme in the mitochondrial membrane.<br />

14 Two factors account for the movement <strong>of</strong> protons through<br />

this enzyme into the mitochondrion (see the figure): (1) [H ] is<br />

higher outside the mitochondrion than inside because protons are<br />

pumped out <strong>of</strong> the mitochondrion by enzymes that catalyze the oxidation<br />

<strong>of</strong> food. (2) The inside <strong>of</strong> the mitochondrion is negatively<br />

charged with respect to the outside.<br />

(a) The synthesis <strong>of</strong> one ATP molecule requires 2H to pass<br />

through the phosphorylation enzyme. The difference in free energy<br />

when a molecule travels from a region <strong>of</strong> high activity to a region <strong>of</strong><br />

low activity is<br />

A high<br />

G RT ln<br />

A low<br />

How big must the pH difference be (at 298 K) if the passage <strong>of</strong><br />

two protons is to provide enough energy to synthesize one ATP<br />

molecule?<br />

(b) pH differences this large have not been observed in mitochondria.<br />

How great an electric potential difference between inside and<br />

outside is necessary for the movement <strong>of</strong> two protons to provide<br />

energy to synthesize ATP? In answering this question, neglect any<br />

contribution from the pH difference.<br />

(c) The energy for ATP synthesis is thought to be provided by<br />

both the pH difference and the electric potential. If the pH difference<br />

is 1.00 pH unit, what is the magnitude <strong>of</strong> the potential<br />

difference?<br />

Positive electric<br />

potential<br />

+<br />

+<br />

–<br />

+<br />

Mitochondrial membrane<br />

–<br />

–<br />

Negative electric<br />

potential<br />

Low H +<br />

concentration<br />

ADP + HPO 2– 2H +<br />

2H +<br />

High H +<br />

concentration<br />

+<br />

+<br />

+<br />

–<br />

4<br />

ATP<br />

–<br />

–<br />

Phosphorylation<br />

enzyme<br />

H + H +<br />

H + driven<br />

out <strong>of</strong><br />

mitochondrion<br />

during<br />

respiration<br />

Problems<br />

Basic Concepts<br />

14-5. Consider the redox reaction<br />

14-1. Explain the difference between electric charge (q, coulombs),<br />

electric current (I, amperes), and electric potential (E, volts).<br />

Thiosulfate<br />

14-2. (a) How many electrons are in one coulomb?<br />

(b) How many coulombs are in one mole <strong>of</strong> charge?<br />

14-3. The basal rate <strong>of</strong> consumption <strong>of</strong> O 2 by a 70-kg human is<br />

about 16 mol <strong>of</strong> O 2 per day. This O 2 oxidizes food and is reduced to<br />

H 2 O, providing energy for the organism:<br />

O 2 4H 4e T 2H 2 O<br />

(a) To what current (in amperes C/s) does this respiration rate<br />

correspond? (Current is defined by the flow <strong>of</strong> electrons from food<br />

to O 2 .)<br />

(b) Compare your answer in part (a) with the current drawn by a<br />

refrigerator using 5.00 10 2 W at 115 V. Remember that power<br />

(in watts) work/s E I.<br />

(c) If the electrons flow from nicotinamide adenine dinucleotide<br />

(NADH) to O 2 , they experience a potential drop <strong>of</strong> 1.1 V. What is<br />

the power output (in watts) <strong>of</strong> our human friend?<br />

14-4. A 6.00-V battery is connected across a 2.00-k resistor.<br />

(a) How many electrons per second flow through the circuit?<br />

(b) How many joules <strong>of</strong> heat are produced for each electron?<br />

(c) If the circuit operates for 30.0 min, how many moles <strong>of</strong> electrons<br />

will have flowed through the resistor?<br />

(d) What voltage would the battery need to deliver for the power to<br />

be 1.00 10 2 W?<br />

I 2 2S 2 O 2 3<br />

T 2I S 4 O 2 6<br />

Tetrathionate<br />

(a) Identify the oxidizing agent on the left side <strong>of</strong> the reaction and<br />

write a balanced oxidation half-reaction.<br />

(b) Identify the reducing agent <strong>of</strong> the left side <strong>of</strong> the reaction and<br />

write a balanced reduction half-reaction.<br />

(c) How many coulombs <strong>of</strong> charge are passed from reductant to<br />

oxidant when 1.00 g <strong>of</strong> thiosulfate reacts?<br />

(d) If the rate <strong>of</strong> reaction is 1.00 g <strong>of</strong> thiosulfate consumed per<br />

minute, what current (in amperes) flows from reductant to<br />

oxidant?<br />

14-6. The space shuttle’s expendable booster engines derive their<br />

power from solid reactants:<br />

6NH4 ClO 4 (s) 10Al(s) S 3N 2 (g) 9H 2 O(g)<br />

FM 117.49<br />

5Al 2 O 3 (s) 6HCl(g)<br />

(a) Find the oxidation numbers <strong>of</strong> the elements N, Cl, and Al in<br />

reactants and products. Which reactants act as reducing agents and<br />

which act as oxidants?<br />

(b) The heat <strong>of</strong> reaction is 9 334 kJ for every 10 mol <strong>of</strong> Al consumed.<br />

Express this as heat released per gram <strong>of</strong> total reactants.<br />

Galvanic Cells<br />

14-7. Explain how a galvanic cell uses a spontaneous chemical<br />

reaction to generate electricity.<br />

Problems 293

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