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The Geometry of a Circle - By: Dennis Kapatos

The Geometry of a Circle - By: Dennis Kapatos

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9. Teacher will tell students to construct an arc <strong>of</strong> a circle using the bottom <strong>of</strong> a can, or anything<br />

else that will serve this purpose. <strong>The</strong> idea is that they don’t have the hole at the center like they<br />

would from using a compass.<br />

10. Teacher will ask students how they could find the center if they used a Mira. If students need<br />

help, teacher will tell them to construct a point near both ends <strong>of</strong> the arc.<br />

11. If students need more help, teacher will tell them to use their Mira find a position where it<br />

maps one <strong>of</strong> these points onto the other.<br />

12. If students still need more help, tell them to draw this line that the Mira is on top <strong>of</strong> when it<br />

maps the two points onto each other.<br />

13. Teacher will ask the students questions about what this line is and lead them to the idea that<br />

this line must go through the center because it is a line <strong>of</strong> symmetry for the circle.<br />

14. Students should recognize the need to repeat this to obtain another line and an intersection.<br />

15. Teacher will ask students to connect the two pairs <strong>of</strong> points they mapped to each other with<br />

segments at tell them that they are called chords.<br />

16. Teacher will ask students to come up with a definition for a chord.<br />

17. Teacher will ask what they constructed to the chord that found the center (a perpendicular<br />

bisector to the chord, be definition <strong>of</strong> a perpendicular bisector).<br />

18. Teacher will have students make conjecture <strong>of</strong> this (<strong>The</strong>orem 12.8).<br />

19. Teach will have student break groups, go to their computers, and start up GSP<br />

20. Teacher will have student’s open a pre-made sketch <strong>of</strong> a circle, a chord, and its<br />

perpendicular bisector.<br />

21. Student’s will more around the points to see that any chord’s perpendicular<br />

bisector crosses the center <strong>of</strong> the circle (see first picture).<br />

22. Teacher will discuss with class and have students formalize their conjecture and<br />

write <strong>The</strong>orem 12.8 in their notes.<br />

22. Teacher will have students look on anther page <strong>of</strong> this sketch <strong>of</strong> the satellite from<br />

the beginning problem.<br />

23. Teacher will ask students to find the placement <strong>of</strong> the receiver (see second<br />

picture).<br />

24. Teacher will students look at other pages <strong>of</strong> the sketches which will have them<br />

discover <strong>The</strong>orems 12.5, 12.6, and 12.9. <strong>The</strong>y are very obvious and thus not too<br />

much time is devoted to them. (see third and fourth pictures).<br />

25. Students will enter these theorems into their notes.<br />

26. Students will spend rest <strong>of</strong> class trying to solve question 20 on page 604.<br />

?<br />

Homework:<br />

Length D'E on<br />

m D'E = 4.83 cm<br />

BC = 5.13 cm<br />

E<br />

drag<br />

a a = 68.76 °<br />

Prove <strong>The</strong>orem 12.9, and on page 603 <strong>of</strong> the textbook, questions 1-13,<br />

18, and finish 20.<br />

G'<br />

D'<br />

B<br />

Length FG' on BC =<br />

m G'G = 4.83 cm<br />

F<br />

m AB = 3.27 cm<br />

G<br />

B<br />

C<br />

A<br />

m CD = 3.3<br />

m GE = 3.09 cm<br />

E<br />

F<br />

D<br />

m EF = 3.06 cm

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