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14 CHAPTER 9. VISCOUS FLOW<br />
where µ eff is the effective viscosity of the suspension, and 〈〉 is a volume<br />
average over the entire volume of the suspension.<br />
The volume averaged symmetric traceless part of the stress tensor can be<br />
expressed as<br />
〈τ ij 〉 = 1 ∫<br />
dV τ ij<br />
V V suspension<br />
⎛<br />
⎞<br />
= 1 ∫<br />
∫<br />
⎝ dV (2µE ij ) + dV (τ ij − 2µE ij ) ⎠<br />
V V suspension<br />
V suspension<br />
= 2µ〈E ij 〉 + 1 ∫<br />
dV (τ ij − 2µE ij ) (9.47)<br />
V V suspension<br />
The second term on the right side of 9.47 is identically equal to zero for the<br />
fluid, from the constitutive equation. Therefore, the second integral reduces<br />
to an integral over the particles,<br />
〈τ ij 〉 = 2µ〈E ij 〉 + 1 ∫<br />
dV (τ ij − 2µE ij ) (9.48)<br />
V V particles<br />
In order to determine the effective viscosity, it is sufficient to consider the<br />
symmetric traceless part of the above equation. Further, if the particles are<br />
solid, the rate of deformation E ij within the particles is identically equal to<br />
zero. Therefore, the symmetric traceless part of the above equation reduces<br />
to<br />
〈τ ij 〉 = 2µ〈E ij 〉 + N ∫<br />
dV (τ ij − 2µE ij ) (9.49)<br />
V V 1 particles<br />
= 2µ〈E ij 〉 + N ∫<br />
dV τ ij (9.50)<br />
V V 1 particle<br />
∫<br />
φ<br />
= 2µ〈E ij 〉 +<br />
dV τ<br />
(4πR 3 ij (9.51)<br />
/3) V 1 particle<br />
In deriving equation 9.51 from 9.50, we have used the simplification that the<br />
number of particles per unit volume is the ratio of the volume fraction and<br />
the volume of a particle. The second term on the right side of equation 9.51<br />
can be simplified as follows. Consider the divergence of (τ il x j ),<br />
∂τ il x j<br />
∂x l<br />
= τ il δ lj + x j<br />
∂τ il<br />
∂x l<br />
(9.52)