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Chapter 9 Viscous flow

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14 CHAPTER 9. VISCOUS FLOW<br />

where µ eff is the effective viscosity of the suspension, and 〈〉 is a volume<br />

average over the entire volume of the suspension.<br />

The volume averaged symmetric traceless part of the stress tensor can be<br />

expressed as<br />

〈τ ij 〉 = 1 ∫<br />

dV τ ij<br />

V V suspension<br />

⎛<br />

⎞<br />

= 1 ∫<br />

∫<br />

⎝ dV (2µE ij ) + dV (τ ij − 2µE ij ) ⎠<br />

V V suspension<br />

V suspension<br />

= 2µ〈E ij 〉 + 1 ∫<br />

dV (τ ij − 2µE ij ) (9.47)<br />

V V suspension<br />

The second term on the right side of 9.47 is identically equal to zero for the<br />

fluid, from the constitutive equation. Therefore, the second integral reduces<br />

to an integral over the particles,<br />

〈τ ij 〉 = 2µ〈E ij 〉 + 1 ∫<br />

dV (τ ij − 2µE ij ) (9.48)<br />

V V particles<br />

In order to determine the effective viscosity, it is sufficient to consider the<br />

symmetric traceless part of the above equation. Further, if the particles are<br />

solid, the rate of deformation E ij within the particles is identically equal to<br />

zero. Therefore, the symmetric traceless part of the above equation reduces<br />

to<br />

〈τ ij 〉 = 2µ〈E ij 〉 + N ∫<br />

dV (τ ij − 2µE ij ) (9.49)<br />

V V 1 particles<br />

= 2µ〈E ij 〉 + N ∫<br />

dV τ ij (9.50)<br />

V V 1 particle<br />

∫<br />

φ<br />

= 2µ〈E ij 〉 +<br />

dV τ<br />

(4πR 3 ij (9.51)<br />

/3) V 1 particle<br />

In deriving equation 9.51 from 9.50, we have used the simplification that the<br />

number of particles per unit volume is the ratio of the volume fraction and<br />

the volume of a particle. The second term on the right side of equation 9.51<br />

can be simplified as follows. Consider the divergence of (τ il x j ),<br />

∂τ il x j<br />

∂x l<br />

= τ il δ lj + x j<br />

∂τ il<br />

∂x l<br />

(9.52)

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