Designing Wells to Optimize Performance and Efficiency - ICWT

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Example of Energy Cost Case 1: New Well Efficiency = 75% TDH = 308 ft Case 2: Well with 50 ft Additional Lift Efficiency = 65% TDH = 358 ft Where: Cost/Hour = gpm x TDH x 0.746 x Cost/kwh 3960 x Efficiency
Annual Cost Parameter Case 1 Case 2 Pumping Rate 1500 gpm 1500 gpm Pumping Level 250 ft 300 ft Discharge Pressure 58 ft 58 ft TDH 308 ft 358 ft Power Cost $ 0.10/kwh $ 0.10/kwh Well Efficiency 75 % 65% Annual Operation 4,380 hours 4,380 hours Annual Cost $50,595 $67,856 Differential = $17,261
Page 1 and 2: Designing Wells to Optimize Perform
Page 3 and 4: Pumping Well Terminology Cone Of De
Page 5 and 6: Critical Components in Designing Ef
Page 7 and 8: Select Samples for Sieve Tests
Page 9 and 10: Wt. % Finer (passing) 20-48 50-60 6
Page 11 and 12: Efficiency Case Study - Big Pine, C
Page 13 and 14: Properly Designed Gravel Envelope &
Page 15 and 16: Damage Zone Repair Drilling Damage
Page 17 and 18: Predevelopment • Predevelopment c
Page 19 and 20: Collapse Due to Slot Plugging
Page 21 and 22: Swabbing and Circulating • Prelim
Page 23 and 24: Development by Swabbing
Page 25 and 26: Single Swab Development • Beginni
Page 27 and 28: Double Swab
Page 29 and 30: Final Development / Pump Developmen
Page 31 and 32: Final Development • Final Develop
Page 33: Rossum Sand Tester
Page 38 and 39: Specific Drawdown, s/Q 0.080 Well D
Page 40 and 41: Water Level in Pumping Well Well Lo
Page 42 and 43: Ground Surface Q Static Water Level
Page 44 and 45: Pumping Step Test Discharge (Q) GPM
Page 46 and 47: Data Discharge Drawdown Specific Ca
Page 48 and 49: Maintaining Well Efficiency • Inc
Page 50 and 51: 50 Physical Clogging
Page 54 and 55: SUMMARY • The efficiency of the w

Designing Wells to Optimize Performance and Efficiency - ICWT

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