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Teacher's notes and answers to questions in the book - Hodder Plus ...

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WJEC GCSE Additional Science Teacher’s Notes<br />

2. Describe <strong>in</strong> words <strong>the</strong> pattern of each graph. This means that you have <strong>to</strong> describe how <strong>the</strong> voltage<br />

(on <strong>the</strong> y-axis) varies with <strong>the</strong> current (on <strong>the</strong> x-axis).<br />

Resis<strong>to</strong>r – voltage is proportional <strong>to</strong> current (graph is l<strong>in</strong>ear with a positive gradient).<br />

Bulb – voltage <strong>in</strong>creases faster than current (graph is curved with <strong>in</strong>creas<strong>in</strong>g positive<br />

gradient).<br />

3. Expla<strong>in</strong> how a variable resis<strong>to</strong>r can be used <strong>in</strong> a circuit <strong>to</strong> control <strong>the</strong> current through <strong>and</strong> <strong>the</strong> voltage<br />

across o<strong>the</strong>r components.<br />

Alter<strong>in</strong>g <strong>the</strong> resistance of a circuit alters <strong>the</strong> current flow<strong>in</strong>g through <strong>the</strong> circuit. If <strong>the</strong><br />

current is altered <strong>the</strong>n <strong>the</strong> voltage across <strong>the</strong> o<strong>the</strong>r components will change due <strong>to</strong> Ohm’s<br />

law.<br />

Questions<br />

7. Us<strong>in</strong>g <strong>the</strong> data that you collected for <strong>the</strong> Practical: Measur<strong>in</strong>g current <strong>and</strong> voltage <strong>in</strong> circuits<br />

controlled by a variable resis<strong>to</strong>r, construct two tables. One table will be for <strong>the</strong> fixed resis<strong>to</strong>r data,<br />

<strong>and</strong> <strong>the</strong> o<strong>the</strong>r table will be for <strong>the</strong> bulb.<br />

The values <strong>in</strong> <strong>the</strong> table will depend on <strong>the</strong> students’ results from <strong>the</strong> Practical.<br />

8. Describe <strong>the</strong> patterns <strong>in</strong> your results for Question 7. How does <strong>the</strong> resistance of <strong>the</strong> fixed resis<strong>to</strong>r vary<br />

with current (or voltage) How does <strong>the</strong> resistance of <strong>the</strong> bulb vary with current (or voltage)<br />

The resistance of <strong>the</strong> fixed resis<strong>to</strong>r is constant for different values of current (or voltage).<br />

The resistance of <strong>the</strong> bulb will <strong>in</strong>crease with an <strong>in</strong>creas<strong>in</strong>g current (or voltage).<br />

9. A 25 Ω fixed resis<strong>to</strong>r has a current of 2 A through it. Calculate <strong>the</strong> voltage across <strong>the</strong> fixed resis<strong>to</strong>r.<br />

V = I × R; V = 2 × 25 = 50 V<br />

10. In a mobile phone circuit, 1.5 V is applied across a keyboard circuit with a resistance of 5000 Ω. What is<br />

<strong>the</strong> current <strong>in</strong> <strong>the</strong> keyboard circuit<br />

V<br />

I R<br />

V<br />

so I <br />

R<br />

1.5<br />

5000<br />

0.003 A<br />

11. Figure 14.13 shows <strong>the</strong> electrical characteristic of a 12 V car bulb. Use <strong>the</strong> graph <strong>to</strong> calculate <strong>the</strong><br />

resistance of <strong>the</strong> bulb when <strong>the</strong> current through <strong>the</strong> bulb is:<br />

a 0.2 A V = 0.4 V so R =<br />

b 0.6 A V = 3.6 V so R =<br />

c 1.0 A V = 10.0 V so R =<br />

0.4<br />

= 2 <br />

0.2<br />

3.6<br />

= 6 <br />

0.6<br />

10 .0 = 10 <br />

1.0<br />

12. Expla<strong>in</strong> why <strong>the</strong> resistance of a bulb changes when more current is passed through it. (H<strong>in</strong>t: when <strong>the</strong><br />

bulb has more current go<strong>in</strong>g through it, it is brighter <strong>and</strong> hotter. How might this affect <strong>the</strong> structure of<br />

<strong>the</strong> metal filament)<br />

As more current flows through <strong>the</strong> filament, <strong>the</strong>re will be more collisions of <strong>the</strong> free electrons<br />

with <strong>the</strong> structure of <strong>the</strong> metal filament <strong>and</strong> <strong>the</strong> electrons <strong>the</strong>mselves. This heats <strong>the</strong> filament<br />

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