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Interpreting SrœNd isotopic data from magmatic and metamorphic ...

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Vojtěch Janoušek:<br />

<strong>Interpreting</strong> Sr–Nd <strong>isotopic</strong> <strong>data</strong>: numerical recipes<br />

originated <strong>from</strong> the same magma by various degrees of fractional crystallization only preserve<br />

identical initial <strong>isotopic</strong> ratios (forming horizontal lines).<br />

Eqs [6.2] <strong>and</strong> [6.4] can be, after eliminating c M , combined into a formula for f. The parameter f can<br />

be calculated if the <strong>isotopic</strong> compositions <strong>and</strong> element concentrations for both end-members as well as<br />

the <strong>isotopic</strong> composition of the presumed hybrid are known:<br />

f<br />

=<br />

I<br />

M<br />

( c<br />

A<br />

cB<br />

− c<br />

( I − I )<br />

B<br />

B<br />

) − I<br />

A<br />

M<br />

c<br />

A<br />

+ I<br />

B<br />

c<br />

B<br />

[6.6]<br />

Exercise 6–2<br />

Plot the theoretical mixing hyperbola between granite <strong>and</strong> basalt, whose compositions<br />

are given below. Calculate the 87 Sr/ 86 Sr ratio of a mixture, containing 50 % of the<br />

granite. Calculate proportion of the granite in a mixture that has 87 Sr/ 86 Sr = 0.71200.<br />

A: granite B: basalt<br />

Sr 160 ppm 318 ppm<br />

87 Sr/ 86 Sr 0.73691 0.70362<br />

Hints:<br />

! Calculate the Sr concentrations (eq. [6.2]) <strong>and</strong> <strong>isotopic</strong> composition (eq. [6.4]) of the hybrid<br />

for various proportions of the granite (f = 0–1)<br />

! Plot the results in the Sr– 87 Sr/ 86 Sr diagram<br />

! Check the results in the 1/ Sr– 87 Sr/ 86 Sr plot — they should form a straight line<br />

! Proportion f of the granite end-member is obtained using eq. [6.6].<br />

B2 Using a pair of different <strong>isotopic</strong> ratios (Sr–Nd)<br />

Taking into account that [6.2]<br />

c = c f + c ( 1−<br />

f )<br />

M<br />

A<br />

B<br />

the equation [6.4] can be rewritten as:<br />

I<br />

Ac<br />

A<br />

f + I<br />

BcB<br />

(1 − f )<br />

I<br />

M<br />

= [6.7]<br />

c f + c (1 − f )<br />

A<br />

Both Sr <strong>and</strong> Nd <strong>isotopic</strong> compositions can be calculated for pre-set values of the parameter f <strong>and</strong> the<br />

corresponding mixing hyperbola plotted in the 87 Sr/ 86 Sr – 143 Nd/ 144 Nd space.<br />

General equation of this mixing hyperbola is derived <strong>from</strong> two equations [6.7], one for Sr <strong>and</strong> one for<br />

Nd, by solving both equations for f <strong>and</strong> equating the results:<br />

B<br />

– 12 –

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