08.02.2015 Views

Solutions to Chapter 4 - Communication Networks

Solutions to Chapter 4 - Communication Networks

Solutions to Chapter 4 - Communication Networks

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

<strong>Communication</strong> <strong>Networks</strong> (2 nd Edition)<br />

<strong>Chapter</strong> 4 <strong>Solutions</strong><br />

61. Suppose that setting up a call requires reserving N switch and link segments.<br />

a. Suppose that each segment is available with probability p. What is the probability that a call<br />

request can be completed<br />

For a call <strong>to</strong> be completed, every segment in the circuit must be free. Thus, assuming that each<br />

switch and link has a probability p of being available, and assuming that this probability is<br />

independent of all others,<br />

P[every circuit free] = P[1 st free]P[2 nd free]…P[N th free] = p N<br />

b. In allocating switch and transmission resources, explain why it makes sense <strong>to</strong> give priority <strong>to</strong><br />

call requests that are almost completed rather than <strong>to</strong> locally originating call requests.<br />

For calls that are almost completed, resources are already locked up, so if the call is denied,<br />

there is a large overhead penalty. Thus they should be given priority. To illustrate, suppose<br />

locally originating calls are given a higher priority. One can then envision a situation where very<br />

few completed connections exist, but all resources are used by partially completed calls.<br />

62. Consider a cellular telephone system with the following parameters: B is the <strong>to</strong>tal bandwidth<br />

available for the system for communications in both directions; b is the bandwidth required by each<br />

channel, including guard bands; R is the re-use fac<strong>to</strong>r; and a is the fraction of channels used for set up.<br />

<strong>Solutions</strong> follow questions:<br />

a. Find an expression for the number of channels available in each cell.<br />

Number of channels available in each cell =<br />

B<br />

( 1−<br />

a)<br />

b<br />

R<br />

channels/cell<br />

b. Evaluate the number of channels in each cell for the AMPS system.<br />

In AMPS, there are 416 <strong>to</strong>tal channels, 21 of which are used for call setup. The reuse fac<strong>to</strong>r is 7.<br />

Thus the number of channels per cell is:<br />

(416 –21)/7 = 56 channels per cell<br />

63. Consider the AMPS system in problem 62.<br />

<strong>Solutions</strong> follow questions:<br />

a. How many Erlangs of traffic can be supported by the channels in a cell with a 1% blocking<br />

probability 5%<br />

The probability of blocking is given by the equation:<br />

P b =<br />

c<br />

a<br />

c!<br />

c<br />

<br />

a<br />

j<br />

j<br />

j=<br />

0 !<br />

where in the AMPS system c = 56 and a is the number of Erlangs of traffic in a cell. If the blocking<br />

probability is 10% and 1%, the maximum number of Erlangs that can be handled is:<br />

Leon-Garcia/Widjaja 29

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!