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k - spsc - Graz University of Technology

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SPSC – Signal Processing & Speech Communication Lab<br />

Therefore:<br />

τ =<br />

na<br />

k<br />

T<br />

nK int eger,<br />

a<br />

k<br />

T Kstep<br />

size<br />

hence:<br />

h<br />

(<br />

−k<br />

(<br />

k<br />

) (<br />

−k<br />

a na T − t = h nT − a t)<br />

Summarizing, we are computing:<br />

<br />

X<br />

X<br />

DWT<br />

DWT<br />

,<br />

∞<br />

∫<br />

−∞<br />

−k<br />

2<br />

−k<br />

( k,<br />

n) a x() t h( nT − a t)<br />

= dt<br />

∞<br />

∫<br />

−∞<br />

k<br />

( k n) x( t) h ( na T − t)<br />

= dt<br />

k<br />

DWT...Discrete Wavelet Transform<br />

figure 12: Analysis bank <strong>of</strong> DWT<br />

Pr<strong>of</strong>essor Georg Holzmann, Horst Cerjak, Christian 19.12.2005 Wallinger 12.06.07 Wavelet T. - Relation to Filter Banks<br />

27

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