Sample Assessment Schedule 2012

NCEA Level 2 Chemistry 91165 (2.5) — page 1 of 6 

SAMPLE ASSESSMENT SCHEDULE 

Chemistry 91165 (2.5): Demonstrate understanding of the properties of selected organic 

compounds 

Assessment Criteria 

Achievement Achievement with Merit Achievement with Excellence 

Demonstrate understanding involves 

naming and drawing structural 

formulae of selected organic 

compounds (no more than eight 

carbons in the longest chain) and 

giving an account of their chemical 

and physical properties. This 

requires the use of chemistry 

vocabulary, symbols and 

conventions. 

Demonstrate in-depth understanding 

involves making and explaining links 

between structure, functional groups 

and the chemical properties of 

selected organic compounds. This 

requires explanations that use 

chemistry vocabulary, symbols and 

conventions. 

Demonstrate comprehensive 

understanding involves 

elaborating, justifying, relating, 

evaluating, comparing and 

contrasting, or using links 

between the structure, functional 

groups and the chemical 

properties of selected organic 

compounds. This requires the 

consistent use of chemistry 

vocabulary, symbols and 

conventions. 

Evidence Statement 

One Expected Coverage Achievement Merit Excellence 

(a) Monomer is: THREE of 

following: 

(b) 

(c) (i) 

(ii) 

1, 2-dichloroethene 



cis 

in (a) structure 

of monomer 

correct 

in (b) BOTH 

structures 

correct 

in (c) BOTH 

isomers drawn 

correctly in 

correct box 

in (d) structural 

or geometric 

isomers 

described 

in (d) structural 

isomers for 

C 2 H 4 Cl 2 drawn. 

In (d) structural 

isomers linked 

to both C 2 H 4 Cl 2 

and to C 2 H 2 Cl 2 

OR 

in (d) geometric 

isomers linked 

to C 2 H 2 Cl 2 and 

reasons why 

C 2 H 4 Cl 2 does 

not have 

geometric 

isomers 

OR 

in (d) BOTH 

isomer types 

linked to either 

the chloroalkane 

or the 

chloroalkene. 

In (d) 

requirements for 

both geometric 

and structural 

isomers linked to 

both molecules.


trans 

(d) 

Structural isomers are compounds with 

the same molecular formula (they have 

the same type and number of atoms) but 

different structural formulae (structures). 

C 2 H 4 Cl 2 has two structural isomers, one 

has a condensed structural formula 

CH 2 Cl–CH 2 Cl and the other CH 3 –CHCl 2 

C 2 H 2 Cl 2 also has structural isomers, one 

has a condensed structural formula 

CH 2 Cl–CHCl and the other CH 2 –CCl 2 

Geometric isomers are compounds with 

the same molecular formula, the same 

(condensed) structural formula but 

different arrangement of atoms. It occurs 

in molecules that have double bonds 

because the rotation of the atoms about 

the axis of the carbon to carbon double 

bond is restricted. They must also have 

two different groups attached to each end 

of the double bond. 

C 2 H 4 Cl 2 doesn’t have a double bond; it 

has a single bond between the carbon 

atoms. Rotation of the atoms about this 

bond can occur freely so C 2 H 4 Cl 2 cannot 

form geometric isomers. 

C 2 H 2 Cl 2 has a double bond and each 

carbon involved has two different groups 

attached to them so C 2 H 2 Cl 2 can form 

geometric isomers.


NØ 

N1 

N2 

A3 

A4 

M5 

M6 

E7 

E8 

No response or does not address the question. 

Provides some writing but does not fulfil any statement from the Achievement criteria column. 

Any ONE statement from the Achievement criteria column. 

Any TWO statements from the Achievement criteria column. 

Any THREE statements from the Achievement criteria column. 

Any ONE statements from the Merit criteria column. 

Gives BOTH statements from the Merit criteria column. 

Only minor error – omission or additional information – from the Excellence criteria column. 

All the evidence from the Excellence criteria column. 

Two Expected Coverage Achievement Merit Excellence 

(a) See Appendix One. THREE of the 

(b) Water 

following: 

Add water to the five solutions. Three 

solutions will dissolve in water 

(ethanol, aminoethane, ethanoic 

acid), two will not (hexane, hex-1- 

ene). 

Litmus 

Use the solutions formed by 

dissolving in water. Add both red and 

blue litmus paper to the solutions in 

water. 

One will not change the colour of the 

litmus paper, this is ethanol. 

One will turn blue litmus red, this is 

ethanoic acid. 

One will turn red litmus blue, this is 

aminoethane. 

Test the solutions which did not 

dissolve in water by reacting fresh 

solutions with bromine water. If the 

solution turns from brown to 

colourless the solution is hex-1-ene. 

Hexane will not react with the 

bromine water. 

Equations with water - 

CH 3 COOH + H 2 O CH 3 COO – + 

H 3 O + 

in (a) THREE 

names or 

structural 

formulae correct 

in (a) THREE 

homologous 

series identified 

or functional 

groups correct 

in (b) reaction 

with two of water, 

litmus or bromine 

water described 

with observations 

for one solution 

OR any two 

observations 

in (b) reaction 

with one of 

water, litmus or 

bromine water 

described with 

observations for 

three (different) 

solutions. 

OR any one 

solution correctly 

identified 

In (b) THREE 

solutions identified 

with all tests 

required to 

positively identify. 

In (b) writes a valid 

method that 

distinguishes 

between the five 

solutions. At least 

two equations are 

included.


CH 3 CH 2 NH 2 + H 2 O CH 3 CH 2 NH 3 

+ 

+ 

OH – 

Equation with bromine water – 

CH 3 – CH 2 – CH 2 – CH 2 – CH=CH 2 + 

Br 2 CH 3 – CH 2 – CH 2 – CH 2 – CHBr– 

CH 2 Br 

NØ 

N1 

N2 

A3 

A4 

M5 

M6 

E7 

E8 






TWO solutions identified with all tests to positively identify. 

Gives BOTH statements from the Merit criteria column. 


All the evidence from the Excellence criteria column. 

Three Expected Coverage Achievement Merit Excellence 

(a) 

(b) (i) 

Compound A is CH 3 –CH 2 –CH 2 –OH 

Compound B is CH 3 –CH 2 –CH 2 –NH 2 

THREE of the 

following: 

in (a) compound 

(ii) Reactant P is HCI 

A correct 

Reactant Q is concentrated H 2 SO 4 

in (b) TWO out 

Reactant R is HCl 

of FOUR 

(c) (i) 

(ii) 

(1) substitution. 

(2) substitution. 

(3) elimination. 

(4) addition. 

compounds of 

reactants 

correct 

in (c)(i) TWO 

reaction types 

described but 

not linked to the 

atoms involved 

Molecules that undergo substitution 

reactions have carbon to carbon single 

bonds and form molecules with carbon 

to carbon single bonds. In a substitution 

reaction an atom or group of atoms is 

replaced by another atom or group of 

atoms. 

Molecules that undergo elimination 

reactions have carbon to carbon single 


to carbon double bonds. In an 

elimination reaction two atoms or small 

groups are removed from a molecule 

forming a carbon to carbon to double 

bond. 

Molecules that undergo addition 

in (c) (ii) ONE 

reaction type 

described. 

In (c) THREE 

reactions correct 

in terms of 

reactant, product 

and reaction type 

which is linked to 

a reason for the 

reaction type. 

In (c) THREE 

reactions correct 

in terms of both 

reactant, product 

and reaction type 

AND the 

justification of 

reaction type for 

that reaction.


reactions have carbon to carbon double 


to carbon single bonds. In an addition 

reaction the reaction involves breaking 

a double bond between the carbon 

atoms and forming a single bond in its 

place as well as forming two new single 

bonds. 

Reactions (1) and (2) are both 

substitution reactions as the molecules 

have carbon to carbon single bonds. In 

(1) the hydroxyl group (–OH) is 

replaced by a chloro group (–Cl). In (2) 

the chloro group (–Cl) is replaced by 

the amine group (–NH 2 ). 

Reaction (3) is an elimination reaction 

as the molecule has carbon to carbon 

single bonds and a double bond is 

formed when it reacts. A hydrogen atom 

and the hydroxyl group on adjacent 

carbon atoms are removed forming a 

carbon to carbon double bond. 

Reaction (4) is an addition reaction as 

the molecule has carbon to carbon 

double bonds and the product has 

carbon to carbon single bonds. In this 

reaction the double bond breaks 

forming a single bond, a hydrogen atom 

attaches itself to one of the carbon 

atoms and a chlorine atom attaches 

itself to the other carbon atom. 

NØ 

N1 

N2 

A3 

A4 

M5 

M6 

E7 

E8 






TWO reactions correct in terms of reactant, product, reaction type, which is linked to a reason for the 


THREE reactions correct in terms of reactant, product, reaction type, which is linked to a reason for the 



All the evidence from the Excellence criteria column.


Appendix One: Question Two (a) 

Organic 

substances 

Structural formula 

IUPAC 

(systematic) name 

Homologous 

series 

A CH 3 –CH 2 –CH 2 –NH 2 

1-aminopropane 

amine 

B CH 3 –OH methanol 

alcohol 

2-choropentane 

chloroalkane/ 

C 

CH 3 –CH 2 – CH 2 –CHCl–CH 3 

haloalkane 

D 

CH 3 –CH 2 –COOH 

propanoic acid 

carboxylic acid 

3, 4- dimethylpent-2-ene alkene 

E

Sample Assessment Schedule 2012

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