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16 MULTIPLE INTEGRALS

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( ∫ 1 ∫ √ 4−x 2<br />

0 1<br />

SECTION <strong>16</strong>.6<br />

4. Symmetry gives 4<br />

( ∫ 1 ∫ √ 4−x<br />

8<br />

2 ∫ √ 4−x 2 −z 2<br />

0 1 0<br />

dydzdx + ∫ 2 ∫ √ 4−x 2<br />

1 0<br />

TRIPLE <strong>INTEGRALS</strong><br />

∫ √<br />

√<br />

4−x2−z2<br />

dydzdx + ∫ 2<br />

− 4−x 2 −z 2 1<br />

∫ √ 4−x 2<br />

0<br />

)<br />

∫ √ 4−x 2 −z 2<br />

0<br />

dydzdx<br />

∫ √ )<br />

4−x 2 −z<br />

√<br />

2<br />

dydzdx<br />

− 4−x 2 −z 2<br />

or<br />

GROUP WORK 3: An Unusual Volume<br />

This is a challenging group work for more advanced students. The idea is to show that just because a solid<br />

looks simple, the computation of its volume may be difficult. The line generated by P 1 and P 2 has equation<br />

z =− 3 4<br />

x + 4, and hence this equation, interpreted in three dimensions, is also the equation of the plane S.<br />

The integral V (E) = ∫ 2 ∫ √ ( )<br />

√<br />

4−(x−2) 2<br />

−2<br />

− 3<br />

− 4−(x−2) 2 4 x + 4 dydx requires polar coordinates to solve by hand (since<br />

the bounding circle has equation r = 4cosθ, 0≤ θ ≤ π) and also requires the students to remember how to<br />

integrate cos 2 θ and cos 4 θ. The volume is <strong>16</strong>π.<br />

Note that the problem can be simplified by moving the solid so that the z-axis runs through the center of D.<br />

Point out that a simple geometric solution can be obtained by replacing S by the horizontal plane z = 5 2 , thus<br />

giving a standard cylinder.<br />

HOMEWORK PROBLEMS<br />

Core Exercises: 5, 11, 13, 19, 24, 25, 27, 34, 39<br />

Sample Assignment: 2, 5, 8, 10, 11, 13, 17, 19, 21, 23, 24, 25, 26, 27, 30, 34, 39, 42, 46, 50, 51<br />

Exercise D A N G<br />

2 ×<br />

5 ×<br />

8 ×<br />

10 ×<br />

11 ×<br />

13 ×<br />

17 ×<br />

19 ×<br />

21 ×<br />

23 ×<br />

24 ×<br />

Exercise D A N G<br />

25 ×<br />

26 ×<br />

27 ×<br />

30 ×<br />

34 × ×<br />

39 ×<br />

42 ×<br />

46 × ×<br />

50 ×<br />

51 ×<br />

907

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