1130 Commercial Subroutine Package - All about the IBM 1130 ...

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ADD PUTAlA3AlDEC Format: CALL PUT(JCARD,J,JLAST,VAR,ADJST,N)A3A1CARRY Function: Converts the whole portion of a real variable, VAR, to an EBCDIC integerDECA1 number, half-adjusting as specified, and places the result, after decimalDIV point alignment, in an array. An 11-zone is placed over the low-order,DPACK rightmost position in the array if VAR is negative.DUNPKEDITFILL Parameter description:GETICOMP JCARD - The name of a one-dimensional integer array defined in a DIMENSIONIOND statement. This array will contain the result of the PUT routine,KEYBD EBCDIC coded information, in Al format, one digit per word.MOVEMPY J - An integer constant, an integer expression, or an integer variable. ThisNCOMP is the first position of JCARD to be filled with the result (the left-handNSIGN end of a field).NZONEPACK JLAST - An integer constant, an integer expression, or an integer variable,PRINT greater than or equal to J. This is the last position to be filled with thePUNCH result (the right-hand end of a field).PUT -*--P1403 VAR - A real constant, a real expression, or a real variable. This is the num-P1442 ber whose whole portion will be PUT.READR2501 ADJST - A real constant, a real expression, or a real variable. This is added toSKIP the variable, VAR, as a half-adjustment factor.STACKSUB N - An integer constant, an integer expression, or an integer variable. ThisS1403 specifies the number of digits to truncate from the right-hand end of theTYPERnumber, VAR.UNPACWHOLE Detailed description: First, the half-adjustment factor is added to the real variable,VAR. Then, each digit is retrieved using the formulaEBCDIC DIGIT = 256 (BINARY DIGIT) - 4032and placed in the output area. Each binary digit is retrieved by subtracting the digitsalready retrieved from VAR and multiplying by 10. The next digit is then retrieved andplaced in the output area. More detailed information may be found in the PUT flowchartand listing.
Example: DIMENSION IPRNT(120)CALL PUT(IPRNT, 1,12, A, 5.0,1)Before:A = 1234567.IPRNT ABCDEFGHIJKLMNOPQRSbPosition 1 5 10 15 20After:A = 1234567.IPRNT 000000123457MNOPQRSb4 I 4 4Position 1 5 10 15 20Errors: NoneRemarks: If the receiving field, JCARD, is not large enough to hold all of the output,only the low-order digits are placed.If JLAST is less than or equal to J, only one digit will be PUT.It is necessary for the programmer to use the ADJST parameter in every PUT. Forexample, assume that the number to be PUT is 123.00. Because the IBM 1130 is a binarymachine, the number may be represented in core storage as 122.999....If this number isPUT with ADJST equal to zero, the result will be 122. However, with ADJST equal to0.5, the preliminary result is 123.499; when PUT, the result is 123. The value of ADJSTshould be a 5 in the decimal position one to the right of the low-order digit to be PUT.The last two factors, ADJST and N, form a logical pair, and should usually appear aseither:ADJSTN.5 and 0or 5. and 1or 50. and 2or 500. and 3etc.etc.ADJST should never be less than .5, since this will introduce fraction inaccuracies.From this it follows that N should never be negative.If PUT (or GET) is used, the calling program must use extended precision.
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aApplication ProgramH20-0241-31130
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CONTENTSIntroduction 1Use of the Co
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Sample Problems 93Problem 1 93Probl
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In addition to input/output, subrou
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SPECIAL CONSIDERATIONS — ARITHMET
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The use of the overlapped I/O porti
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A decimal field is stored in an arr
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FORMAT REQUIREMENTSThe requirements
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ADDFormat: CALL ADD(JCARD, J, JLAST
Page 21 and 22: A1A3Format: CALL A1A3(JCARD, J, JLA
Page 23 and 24: Errors: If a character does not app
Page 25 and 26: Example: DIMENSION IFLD(20)N=0CALL
Page 27 and 28: A3A1Format: CALL A3A1(JCARD, J, JLA
Page 29 and 30: Errors: If JLAST is less than J, on
Page 31 and 32: Example: DIMENSION NUMB(10)Before:C
Page 33 and 34: Example: DIMENSION IFLD(20)N=0CALL
Page 35 and 36: 5. As long as the result is positiv
Page 37 and 38: DPACKFormat: CALL DPACK(JCARD, J, J
Page 39 and 40: Example: DIMENSION IUNPK(26), IPAKD
Page 41 and 42: More detailed information may be fo
Page 43 and 44: Control Character Function. (decima
Page 45 and 46: Example: There are three common met
Page 47 and 48: FILLFormat: CALL FILL(JCARD,J,JLAST
Page 49 and 50: Example 1: DIMENSION INCRD(80)B=GET
Page 51 and 52: ICOMPFormat: ICOMP (JCARD,J,JLAST,K
Page 53 and 54: IONDFormat: CALL IONDFunction: Chec
Page 55 and 56: Errors: The following WAITs may occ
Page 57 and 58: Example: DIMENSION INPUT(80),IOUT(1
Page 59 and 60: Example: DIMENSION MPLR(5),MCAND(15
Page 61 and 62: Example: DIMENSION IN(80), MASTR(80
Page 63 and 64: Example: DIMENSION INUMB(9)CALL NSI
Page 65 and 66: When a special character is the ori
Page 67 and 68: [Example: DIMENSION IUNPK(26),IPAKD
Page 69 and 70: All of the above WAITS require oper
Page 71: Only one card can be punched at a t
Page 75 and 76: Only one line can be printed at a t
Page 77 and 78: Only one card can be punched at a t
Page 79 and 80: READFormat: CALL READ(JCARD,J,JLAST
Page 81 and 82: Remarks: After each card read, the
Page 83 and 84: Only one card can be read at a time
Page 85 and 86: SKIPADDA1A3Format: CALL SKIP(N)A1DE
Page 87 and 88: STACKFormat: CALL STACK,Example: A
Page 89 and 90: Example: DIMENSION IGRND(12), ITEM(
Page 91 and 92: Example: NUMBR=12544CALL S1403(NUMB
Page 93 and 94: Errors: If a WAIT occurs at locatio
Page 95 and 96: UNPACFormat: CALL UNPAC(JCARD,J,JLA
Page 97 and 98: WHOLEFormat: WHOLE (EXPRS)Function:
Page 99 and 100: SAMPLE PROBLEMSPROBLEM 1This progra
Page 101 and 102: 111 um 11IPMEMCPIPIPP111111.11 1111
Page 103 and 104: CARD AFTER •1234567NOW TESTING 11
Page 105 and 106: INDICATORS CARD BEFORE. 12345678901
Page 107 and 108: Sample Problem 1: Data Input Listin
Page 109 and 110: 1234567890123456789 412345678901234
Page 111 and 112: Sample Problem 2: Detailed Descript
Page 113 and 114: 38. Did overflow occur in the addit
Page 115 and 116: CHART 52 1130 COMMERCIAL SAMPLE PRO
Page 117 and 118: SAMPLE PROBLEM 2 PAGE 02GO TO 13807
Page 119 and 120: Sample Problem 2: Invoice OutputDAV
Page 121 and 122: Sample Problem 2: Data Input Listin
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Sample Problem 3: Detailed Descript
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CHART S3 1130 COMMERCIAL SAMPLE PRO
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Sample Problem 3: Payroll Register
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Sample Problem 3: Data Input Listin
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CHART Al 1130 COMMERCIALNO IS JTEST
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CHART CA 1130 COMMERCIAL SUBROUTINE
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CHART DIX.0.YES KLAST 0.KSTRT-JSPAN
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CHART DU1130 COMMERCIAL DUNPK SUBRO
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CHART GTSTARTX• NZONE •NZONEJCA
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SCHART 10STARTxxYES AN..X.. INTERRU
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CHART MPSTART1130 COMMERCIAL MPY SU
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CHART NS 1130 COMMERCIAL NSIGN SUBR
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CHART PU1130 COMMERCIAL PACK/UNPAC
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CHART PT1130 COMMERCIAL PUT SUBROUT
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11111•111011MI■IIMINII IYxl1S1
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CHART R21130 COMMERCIAL R2501 SUBRO
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CHART SU 1130 COMMERCIAL SUB SUBROU
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1CHART WHSET RESULT EQUAL TO •ZER
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PAGE 2002C 0 D070 STO JSIGN SAVE SI
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ADDA lA 3A 1DECA3A1CARRYDE CA 1C5P0
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ADDA1A3// ASMCSP03260•• A1DEC S
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szt// ASMCSPO4890•• DECAL SUBRO
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PAGE 2ADD• KSTRT-K-1 CSP06330 A1A
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PAGE 4ADDA1A3•NOUO-MULTCSP0743000
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CSP09200// OUPADD•STORE WS UA DUN
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0064 0 CO320065 01 4C08007EPAGE 3AD
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ASMCSPI1800ADD*• GET SUBROUTINE F
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PAGE 20038 0 9008 S ONE*1 SUBTRACT
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CSP14800ADDCSP14810CSP14820CSP14830
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$tPAGE 3ADD006F 00 4C000000 DONEI B
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ASM CSP17000•• NSIGN SUBROUTINE
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ASMCSP18360*• PRINT AND SKIP SUBR
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ii.PAGE 20030 0 TIFF MDX 1 . 1 DECR
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ASMCSP20910•• PUNCH SUBROUTINE
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ASM0• READ SUBROUTINE FOR 1130 CS
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DUP'STORE WS UA33C0 0006TYPERCSP239
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3// ASM•• ARGS. RPACK AND SWING
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,CSP Routine NameNumber ofWordsCall
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TIMING DATASubprogram NameApproxima
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j1130 Commercial Subroutine Package
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OPERATING INSTRUCTIONSThe procedure
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BIBLIOGRAPHYIBM 1130 Functional Cha
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', W.P.M. RP
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1130 Commercial Subroutine Package(
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