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University of Paderborn Department of Mathematics Diploma Thesis ...

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24 CHAPTER 2. STABLE IDEALSm ∈ M <strong>of</strong> I the term U c (m) is contained in I (if U c is an upper triangular matrix). SinceI is a monomial ideal (i.e. I is homogeneous, especially), it follows I = U c (I). Since the set<strong>of</strong> all upper triangular matrices <strong>of</strong> the form U c and all diagonal matrices in G forms a basis<strong>of</strong> all upper triangular matrices <strong>of</strong> G, I is fixed under the action <strong>of</strong> all upper triangularmatrices <strong>of</strong> G.This characterization <strong>of</strong> Borel-fixed ideals will be used in the following sections <strong>of</strong> thisthesis and we will call an ideal, which fulfills the condition <strong>of</strong> the preceding Theorem 2.7,a stable ideal.Definition 2.8. Let K be a field <strong>of</strong> characteristic zero and let R := K[x 0 , . . . , x n ]. Amonomial ideal I ⊂ R is called a stable ideal, if for every monomial m = x a 00 · x a 11 · . . . · x ann<strong>of</strong> I we havefor i < j and s ≤ a j .x a 00 · . . . · x a i−1i−1 · xa i+si · x a i+1i+1 · . . . · xa j−1j−1 · xa j−sj · x a j+1j+1 · . . . · xan n ∈ IRemark 2.9. Indeed, it is easy to see that the condition <strong>of</strong> Definition 2.8 is equivalentto the one in Theorem 2.7: Any stable ideal fulfills the condition <strong>of</strong> Theorem 2.7. On theother hand, let I ⊂ R be a monomial ideal fulfilling the condition <strong>of</strong> Theorem 2.7. We haveto show that I is stable. Let m ∈ I be a monomial. Then there is a monomial generatorm ′ ∈ I and a monomial m ′′ ∈ M, such that m = m ′ · m ′′ . Let x k , k > 0, be a variabledividing m. It suffices to show that x l · m ∈ I for 0 ≤ l < k. If x k divides m ′′ , we havex kx l · mx k= m ′ ·hence, x l · mx k=) (x l · m′′x k ) (x l · m′· m ′′ ∈ I, which proves the assertion.x k∈ I, since m ′ ∈ I. If x k divides m ′ , we know x l · m′x k∈ I and,Example 2.10. To come back to Example 2.2 <strong>of</strong> the preceding section, we can easily seethat the ideal I = (x 3 0, x 2 0x 1 , x 2 0x 2 ) is stable, sincex 2 0x 1x 1· x 0 = x 3 0 ∈ I,x 2 0x 2x 2· x 1 = x 2 0x 1 ∈ I and x2 0x 2x 2· x 0 = x 3 0 ∈ I.In the following, we will present an easy way to compute the saturation <strong>of</strong> a stable ideal.2.3 Saturation <strong>of</strong> stable idealsIn order to decide, whether a given stable ideal is saturated and, if this is not the case,to compute its saturation, we have to examine the associated prime ideals in the primarydecomposition <strong>of</strong> the stable ideal.We will prove that all associated prime ideals <strong>of</strong> a given stable ideal are <strong>of</strong> the form(x 0 , . . . , x i ) for an i ≥ 0. Within the pro<strong>of</strong> <strong>of</strong> this assertion, we will make use <strong>of</strong> a theoremby Bayer and Stillman (see [6], Proposition 15.24 ).

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