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University of Paderborn Department of Mathematics Diploma Thesis ...

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3.3. STABLE IDEALS WITH THE SAME DOUBLE SATURATION 57Example 3.25. Consider the stable and saturated ideal I := (x 2 0, x 0 x 1 , x 0 x 3 2) in R :=K[x 0 , x 1 , x 2 , x 3 ]. By Algorithm 2.29, we compute the Hilbert polynomial <strong>of</strong> R/I, whichyieldsp R/I (z) = 1 2 z2 + 3 2 z + 4.Contraction <strong>of</strong> the monomial x 0 x 2 2 in I is possible: We obtain the idealI (1) := I con = (x 2 0, x 0 x 1 , x 0 x 2 2),in which we perform an expansion via the monomial x 0 x 1 yielding the idealComputing p R/J (z) by Algorithm 2.29 showsJ := (I (1) ) exp = (x 2 0, x 0 x 2 1, x 0 x 1 x 2 , x 0 x 2 2).p R/J (z) = 1 2 z2 + 3 2 z + 4,i.e. the Hilbert polynomial <strong>of</strong> J indeed equals the Hilbert polynomial <strong>of</strong> I. Below we willconsider an example, where we use the corollary stated above.Corollary 3.26. Let I ⊂ R be a saturated stable ideal. Let I exp be the ideal obtained from Iby performing the expansion <strong>of</strong> some monomial and let I con be the ideal obtained from I byperforming the contraction <strong>of</strong> some monomial m in I, where m·x n−1 is a minimal generator<strong>of</strong> I. Then the Hilbert polynomials <strong>of</strong> R/I exp and R/I con are given by p R/I exp(z) = p R/I (z)+1and p R/I con(z) = p R/I (z) − 1.Pro<strong>of</strong>. The assertion immediately follows from the pro<strong>of</strong> <strong>of</strong> Proposition 3.23.Example 3.27. Consider the ideals I and J <strong>of</strong> Example 3.25 in R := K[x 0 , x 1 , x 2 , x 3 ]. Weobtained the ideal I (1) from I by the contraction <strong>of</strong> x 0 x 2 2. The Hilbert polynomial <strong>of</strong> I (1)can be computed by Algorithm 2.29, which yieldsp R/I (1)(z) = 1 2 z2 + 3 2 z + 3 = p R/I(z) − 1.The ideal J was obtained from the ideal I (1) by the expansion <strong>of</strong> the monomial x 0 x 1 . Sincewe know by Example 3.25 thatp R/I (z) = p R/J (z) = 1 2 z2 + 3 2 z + 4,we see that the expansion <strong>of</strong> x 0 x 1 in I (1) does indeed increase the Hilbert polynomial <strong>of</strong>R/J by one, i.e. p R/J (z) = p R/I (1)(z) + 1.In Corollary 3.22, we stated that all saturated stable ideals I, J ⊂ R with the same doublesaturation are linked by a finite sequence <strong>of</strong> contractions and expansions. This means thatwe can always find monomials m 1 , . . . , m l ∈ M, such that the contraction <strong>of</strong> m 1 , . . . , m l

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