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Schaum's Outline Series

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CHAPTER 6 Risk Analysis and Management 97<br />

Normal risks—Misunderstanding user desires, miscommunication with user, user<br />

hardware problems, cost overrun, project delays, and so on<br />

Unique risks—Interfacing with patient record system<br />

2. Consider a project that has 0.5 percent probability of an undetected fault that would<br />

cost the company $100,000 in fines. Calculate the risk exposure.<br />

The risk exposure is the sum of the risk exposure for each possibility.<br />

0:005 100,000 þ 0:995 0 ¼ $500<br />

3. Consider the use of an additional review for Problem 2 that would cost $100 but<br />

eliminate such a fault 50 percent of the time. Calculate this new risk exposure with<br />

using the additional review. Is the additional review approach better?<br />

0:0025 100,100 þ 0:9975 100 ¼ 250:25 þ 99:75 ¼ $350:00<br />

The additional review approach is better.<br />

4. What would change in Problem 3 if the additional review was only effective 10 percent<br />

of the time?<br />

The risk exposure would increase.<br />

0:0045 100; 100 þ 0:9955 100 ¼ 450:45 þ 99:55 ¼ 550:00<br />

and be marginally worse than the nonadditional review approach.<br />

5. Build a decision tree for the problem in Example 6.3 if in Game A, the payoff was<br />

$5.00 and if the cost of playing in Game B was $4.00. Should you play either game?<br />

The risk decision tree is shown in Fig. 6-2. In both games you would expect to lose<br />

money. In game A you would lose an average of $0.75, and in Game B you would lose<br />

an average of $1.50.<br />

Game A<br />

Game B<br />

2 heads _ 0.25<br />

1 heads _ 0.5<br />

0 heads _ 0.25<br />

2 heads _ 0.25<br />

1 heads _ 0.5<br />

0 heads _ 0.25<br />

Fig. 6-2<br />

0.25 * $5 = $1.25<br />

0.5 * _ $2 = _ $1.00<br />

0.25 * _ $4 = _ $1.00<br />

0.25 * $10 _ $4 = $1.50<br />

0.5 * _ $4 = _ $2.00<br />

0.25 * _ $4 = $1.00

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